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Roman Numerals

Questions and answers related to the symbols used by the ancient Romans to represent numbers. These include the numerals: I, V, X, L, C, D and M.

14,167 Questions

What are four possible ways of adding 1976 to 1776 and four possible ways of subtracting 1776 from 1976 but working out all eight calculations from start to finish entirely in Roman numerals?

The rules as we now know them today governing the Roman numeral system had nothing to do withe the Romans because they were introduced during the Middle Ages long after the fall of the Roman Empire but we can extrapolate from historical sources that the ancient Romans in almost all probability would have worked out the given numbers as in the following formats:-

CMMLXXVI+MDCCLXXVI = MMMDCCLII => (-100+2076)+1776 = 3752

VXXMMI+MDCCLXXVI = MMMDCCLII => (-25+2001)+1776 = 3752

CMMLXXVI+VXXCCMMI = MMMDCCLII => (-100+2076)+(-225+2001) = 3752

VXXMMI+VXXCCMMI = MMMDCCLII => (-25+2001)+(-225+2001) = 3752

CMMLXXVI-MDCCLXXVI = CC => (-100+2076)-1776 = 200

VXXMMI-MDCCLXXVI = CC => (-25+2001)-1776 = 200

CMMLXXVI-VXXCCMMI = CC => (-100+2076)-(-225+2001) = 200

VXXMMI-VXXCCMMI = CC => (-25+2001)-(-225+2001) = 200

Note that in mathematics -(-225+2001) becomes 225-2001 and that there are other possible ways to work out the given numbers into Roman numerals but for more complicated calculations the Romans would have made usage of an abacus calculating device.

What is 159 plus 149 added in two different ways and 159 minus 149 subtracted in two different ways but working out all four calculations entirely in Roman numerals?

The rules as we now know them today governing the Roman numeral system have absolutely nothing to do with the ancient Romans whatsoever because they were changed in the Middle Ages presumably to make the Roman numeral system more compatible with the Hindu-Arabic numeral system that was gradually being introduced into Western Europe via Spain at the time and as a result the Hindu-Arabic numerals of 159 and 149 are now considered to be CLIX and CXLIX when converted into Roman numerals respectively which does not quite lend themselves easily towards mathematical interactivity between each other or any other numerals for that matter but nowadays we can extrapolate from reliable historical sources that the ancient Romans would have probably calculated the given integers as in any of the following formats:-


CLVIIII+CXXXXVIIII = CCCVIII => 159+149 = 308

ICLX+ICL = CCCVIII => (-1+160)+(-1+150) = 308

CLVIIII+CXXXXVIIII = X => 159-149 = 10

ICLX-ICL = X => (-1+160)-(-1+150) = 10


Note that the above calculations are pretty fundamental and were fairly easy to work out but for more complicated calculations the ancient Romans would have made usage of an abacus calculating device.

How would you actually add together 1999 and 619 giving reasons why that two methods of addition are possible?

Since 1999 is 1 less than 2000, it is instantly apparent that the sum is 2618.

It is also possible but much less efficient to write the numbers as a school exercise would show them.

How do you write out correctly in two different ways 9-19-1999 in Roman numerals?

Nowadays 9-19-1999 is officially notated as IX-XIX-MCMXCIX in Roman numerals.

But there exist historical evidence to show that the ancient Romans would have worked out the equivalent of 9-19-1999 on an abacus counting device as follows:-

VIIII-XVIIII-MDCCCCLXXXXVIIII => 9-19-1999

And then abridged them logically in written format as follows:-

IX-IXX-IMM => (10-1)-(20-1)-(2000-1)

QED

How would you subtract 1776 from 1999 in two different ways but entirely in Roman numerals with explanations?

The ancient Romans would have worked out 1776 on an abacus counting device as MDCCLXXVI and 1999 as MDCCCCLXXXXVIIII which can be abridged to IMM thus facilitating the speed and ease of subtraction in either of the following formats:-

A: IMM-MDCCLXXVI = CCXXIII => (2000-1)-1776 = 223

B: MDCCCCLXXXXVIIII-MDCCLXXVI = CCXXIII => 1999-1776 = 223

Note that in todays modern configuration of Roman numerals 1999 is now considered to be MCMXCIX

If all the people on the world made a chain how long would it be?

If each person's link was 2 feet wide, The chain would wrap around the equator 100 times

What is the connection with Hindu Arabic numerals and that which involves angles?

This question has already been answered by myself but someone else has entirely deleted the original answer probably for plagiarizing purposes so here we go again:-

It is written that at one time in the distant past the Hindu-Arabic numerals or digits of 1, 2, 3, 4, 5, 6, 7, 8, 9 and 0 were once encoded with secret geometrical symbols inasmuch that the first digit of 1 had either an arc or an angle of 36 degrees hidden in it and then thereafter each consecutive digit was increased by increments of 36 degrees by means of arcs and angles or a combination of both in which the digit 0 finally consisted of 360 degrees.

As a consequence of these concealed codes the digit degree sum of any number from 1 to infinity would always finally total to 9 degrees as the following example shows:-

Digit degree sum of 2357 = 36*(2+3+5+7) = 612 => 6+1+2 = 9 degrees

Over the past thousands of years Hindu-Arabic numerals have been transformed into the configuration that we use today but the zero figure at one time probably resembled a circle which even today consist of ten 36 degree arcs amounting to 360 degrees.

QED

How would you actually add together 998001 and 1999 in two different ways using only Roman numerals which in both calculations it must be the Roman equivalent of one million?

Nowadays we would convert 998,001 into Roman numerals as CMXCVMMMI with lines above the first five numerals to indicate multiplication by a thousand and 1999 as MCMXCIX in which the ancient Romans would have probably discarded them as the scribblings of a child because the way we write out Roman numerals today differs in many respects in the way that the Romans actually did themselves thus preventing logical interaction of these numerals.

But notwithstanding the aforementioned inasmuch that there is historical evidence to suggest that the Romans would have abridged their numeracy system whenever possible as for example IX (10-1) is an abridged version of VIIII (9) and so it's quite feasible that the Roman equivalent of 998,001 and 1999 could have been calculated together in either of the following formats:-

(IIM)I+IMM = (M) => [1,000,000-2000+1]+[2000-1] = 1,000,000

Alternatively:-

(DCCCCLXXXXVIII)I+MDCCCCLXXXXVIIII = (M) => 998,001+1999 = 1,000,000

Note that numerals within brackets indicate multiplication by a 1000 and that todays practice of over lining numerals to indicate multiplication by a 1000 was introduced during the Middle Ages along with other rules still governing todays Roman numeral system.

Remember: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M

Values: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1

QED by David Gambell

How would you add 14 18 and 19 in Roman numerals using two different methods of addition giving reasons why?

Under todays rules (which had nothing to do with the Romans because they were introduced during the Middle Ages) governing the Roman numeral system we would convert the equivalent of 14, 18 and 19 into Roman numerals as XIV, XVIII and XIX respectively which are a mishmash of numerals that are incapable of being added together in some sort of a logical pattern.

Yet there is evidence to suggest that the Romans themselves in the past would have probably used either of the following formats to add together these numbers:-

IXV+IIXX = XXXII (15-1)+(20-2) = (32)

XXXII+IXX = XXXXXI = LI (32)+(20-1) = (51)

Alternatively:-

XIIII+XVIII = XXXII (14)+(18) = (32)

XXXII+XVIIII = XXXXXI = LI (32)+(19) = (51)

Remember: 5*I=V, 2*V=X, 5*X=L

Roman numerals: L=50, X=10, V=5 and I=1

Numbers that equal an eighteen perimeter?

what type of polgon is it?

quadrilateral:6,7,3,2 and a bunch any way i cant go on because this is boring.

How do you write the roman numeral for the year 1911?

MCMXI is the number 1911 in roman numerals. This is a notation used earlier for representing numbers.

How would you subtract 444 from 1999 using two different methods entirely in Roman numerals without the help of Hindu-Arabic numerals?

Notwithstanding todays modern notation of Roman numerals inasmuch that there is compelling historical evidence to suggest that the ancient Romans would have notated and subtracted the equivalent of 444 from 1999 using either of the following formats:-

IMM-IVLD = MDLV => (2000-1)-(500-56) = 1555

Remember that in arithmetic a double minus becomes a plus.

Alternatively by cancelling out like numerals:-

MDCCCCLXXXXVIIII-CCCCXXXXIIII = MDLV => 1999-444 = 1555

Todays rules governing the Roman numeral system were compiled and introduced during the Middle Ages so therefore it follows that they had little or even nothing to do with the original Roman way of calculating.

Values: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1

Note: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M

QED by David Gambell

How would you add together 990 plus 1915 plus 2095 in two different ways entirely in Roman numerals in step by step stages?

Nowadays we would convert the equivalent of 990, 1915 and 2095 into Roman numerals as CMXC, MCMXV and MMXCV respectively which makes addition of them quite difficult but there is credible evidence to suggest that the ancient Romans would have calculated the sum of these numbers in either of the following formats:-

A: XM+CMMXV = CMMMV => (1000-10)+(2015-100) = (3005-100) => 2905

CMMMV+VMMC = (V) => (3005-100)+(2100-5) = 5000

B: DCCCCLXXXX+MDCCCCXV = MMDCCCCV => 990+1915 = 2905

MMDCCCCV+MMLXXXXV = (V) => 2905+2095 = 5000

Note that MMMMM is the equivalent of (V) which means 1000*5 = 5000 and that for more complicated calculations the ancient Romans would have made use of an abacus calculating device.

QED

Where do you find hindu arabic number system and roman system?

The Hindu-Arabic system of numeracy is what we use today that is 0, 1, 2, 3, 5 .... etc.

The Roman system of numeracy was used before the introduction of the Hindu-Arabic system in the Middle Ages and consisted of 7 symbols each having different values.

How do you write numerical values 637353233?

637,353,233 = six hundred thirty-seven million, three hundred fifty-three thousand, two hundred thirty-three.

How would you write out 1 to 2000 in Roman numerals in the same way as the ancient Romans did and not in todays notation of them?

Notwithstanding todays modern configuration of Roman numerals inasmuch that there is substancial evidence to qualify the fact that the ancient Romans would have worked out the equivalent of 1 to 2000 on an abacus counting device as follows:-

1 to 9: I, II, III, IIII, V, VI, VII, VIII and VIIII

10 to 90: X, XX, XXX, XXXX, L, LX, LXX, LXXX and LXXXX

100 to 900: C, CC, CCC, CCCC, D, DC, DCC, DCCC and DCCCC

1000 and 2000: M and MM

To select any numerals simply write them out in descending order as in the examples: 1776 = MDCCLXXVI and 1666 = MDCLXVI

Note that sometimes it's possible to abridge numerals thus using less numerals but of equal value as the following examples show:-

4 = IIII => IV (5-1)

9 = VIIII => IX (10-1)

19 = XVIIII => IXX (20-1)

49 = XXXXVIIII => IL (50-1)

1999 = MDCCCCLXXXXVIIII => IMM (2000-1)

The way we write out Roman numerals today is because the real rules governing the Roman numeral system were changed in the Middle Ages presumably to make Roman numerals more compatible with Hindu-Arabic numerals that were being intoduced into Western Europe at the time.

QED by David Gambell

What is 1767 plus 9 added in two different ways and 1767 minus 9 subtracted in two different ways but working out all calculations from start to finish in Roman numerals?

Nowadays we think that the equivalent of 9 in Roman numerals is only IX whereas in fact IX is an abridged version of VIIII in ancient Roman numerals thus facilitating the conversion and calculations of the given Hindu-Arabic numerals into Roman numerals in several ways as follows:-

MDCCLXVII+VIIII = MDCCLXXVI => 1767+9 = 1776

MDCCLXVII+IX = MDCCLXXVI => 1767+(-1+10) = 1776

MDCCLXVII-VIIII = MDCCLVIII => 1767-9 = 1758

MDCCLXVII-IX = MDCCLVIII => 1767-(-1+10) = 1758

Note that in mathematics that -(-1+10) is equivalent to +1-10 and so -(-I+X) is equivalent to -VIIII