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Roman Numerals

Questions and answers related to the symbols used by the ancient Romans to represent numbers. These include the numerals: I, V, X, L, C, D and M.

14,167 Questions

What is the equivalent number to LXXVI?

LXXVI is called a roman numeral.

A method of writing numbers invented by the Romans.

Each letter has a value, L = 50, X = 10, V = 5, I = 1.

Add together the values to get the answer which is 76.

How would you add together 666 and 999 in two different ways entirely in Roman numerals in both calculations?

Because of the changes made to the rules governing the original Roman numeral system introduced during the Middle Ages nowadays we would convert 999 into Roman numerals as CMXCIX which makes them almost impossible to interact sensibly with othe numerals.

But there is evidence to suggest that the ancient Romans would have calculated the equivalent of 999 on an abacus counting board as DCCCCLXXXXVIIII and then systematically reduced them to IM in written format thus facilitating the speed and ease of addition as follows:-

DCLXVI+IM = MDCLXV => 666+(1000-1) = 1665

Alternatively:-

DCLXVI+DCCCCLXXXXVIIII = MDCLXV => 666+999 = 1665

Values: M=1000 D=500 C=100 L=50 X=10 V=5 and I=1

Note: 5*I=V 2*V=X 5*X=L 2*L=C 5*C=D and 2*D=M

QED by David Gambell

What are 1999 plus 1776 and 1999 minus 1776 using Roman numerals throughout your work giving reasons why?

According to today's criteria 1999 converted into Roman numerals is considered to be MCMXCIX which makes it almost impossible for them to interact with other numerals in a logical mathematical progression.

But the Romans themselves would have actually worked out the equivalent of 1999 on an abacus counting device as MDCCCCLXXXXVIIII which can be contracted to IMM thus facilatating the speed and ease of addition as follows:-

IMM+MDCCLXXVI = MMMDCCLXXV (2000-1)+(1776) = 3775

Alternatively using an abacus counting board:-

MDCCCCLXXXXVIIII+MDCCLXXVI = MMMDCCLXXV (1999+1776 = 3775)

Subtraction:-

MDCCCCLXXXXVIIII-MDCCLXXVI = CCXXIII (1999-1776 = 223) by cancelling out the numerals

Remember that: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M

Roman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1

QED

What are the two methods of actually adding together 19 29 and 52 using only Roman numerals?

c

Additional Information:-

Under today's rules we would convert 19 and 29 into Roman numerals as XIX and XXIX which makes any form of interaction between other numerals quite difficult.

But there is evidence to suggest that the Romans themselves would have actually worked out the equivalent of 19 and 29 as XVIIII and XXVIIII then simplified them to IXX and IXXX which uses less numerals but of equal value thus making addition quicker and simpler as follows:-

IXX+IXXX = IIL (20-1)+(30-1) = (50-2)

IIL+LII = C (50-2)+52 = 100

Alternatively:-

XVIIII+XXVIIII = XXXXVIII (19+29 = 48)

XXXXVIII+LII = C (48+52 = 100)

Roman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1

Remember that: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M

Quod Erat Demonstrandum

What does lxxvill stand for in maths?

I guess you are referring to converting Roman Numerals to "normal" numbers:

LXXVIII = L + X + X + V + I + I + I

= 50 + 10 +10 + 5 + 1 + 1 + 1

= 78

How would you in concise detail subtract 1749 from 1999 using Latin numeracy?

mdccxlix minus mcx-with-line-on-topxcix

Improved Answer:-

Latin numeracy is the same as Roman numerals and the way in which we work them out today differs in the way that the Romans actually did themselves because of changes made to the real rules governing the Roman numeral system during the Middle Ages presumably to make it easier to convert Roman numerals into Hindu-Arabic numerals that were gradually being introduced into Western Europe at the time.

As a consequence of these changes today we would write out the equivalent of 1999 and 1749 as MCMXCIX and MDCCXLIX which makes any form of mathematical interaction between them almost impossible.

But there is evidence to suggest that the Romans would have calculated the equivalent of the Hindu-Arabic numerals of 1999 and 1749 on an abacus counting device as MDCCCCLXXXXVIIII and MDCCXXXXVIIII then probably simplified them to IMM and IMDCCL respectively which makes subtraction to be quite straightforward as follows:-

IMM-IMDCCL = CCL (2000-1)-(1750-1) = 250

Remember that in mathematics a double minus becomes a plus and that a minus multiplied by a minus also becomes a plus as does a minus divided by a minus.

Alternatively:-

MDCCCCLXXXXVIIII-MDCCXXXXVIIII = CCL (1999-1749 = 250) by cancelling out the numerals.

Latin numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1

QED

What is this in Arabic numerals MCDXLIV?

1543

Improved Answer:-

MDXLIII represents 1543 in Roman numerals but MCDXLIV represents 1444 in Roman numerals

How would you add together 14 plus 1999 plus 19 using two different combinations of Roman numerals throughout both calculations?

Under today's rules governing the Roman numeral system 14, 1999 and 19 are officially XIV, MCMXCIX and XIX respectively thus restricting any form of mathematical operations with them.

But there is strong evidence to suggest that the Romans themselves in the past would have probably calculated the above numbers in either of the following formats:-

Abridged Version:

IXV+IMM = MMXIII (15-1)+(2000-1) = (2013)

MMXIII+IXX = MMXXXII (2013)+(20-1) = (2032)

Unabridged Version:

XIIII+MDCCCCLXXXXVIIII = MMXIII (14)+(1999) = (2013)

MMXIII+XVIIII = MMXXXII (2013)+(19) = (2032)

Remember that: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M

Roman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1

QED

What are twenty or more advantages of the now defunct ancient Roman numeral system?

These numbers have hardly any advantage. About the only one I can think of is that it makes some things look old-fashioned. It is only for this reason that they are sometimes used for chapter numbers or similar things.

What are two different ways of actually adding together 1999 64 and 99 entirely in Roman numerals knowing in advance that it must be MMCLXII giving reasons why?

Due to changes made to the real rules governing the Roman numeral system introduced during the Middle Ages, presumably to make it easier to convert Roman numerals into Hindu-Arabic numerals that were increasingly becoming the dominant numeral system in Western Europe at the time, today we would convert 1999, 64 and 99 into Roman numerals as MCMXCIX, LXIV and XCIX respectively which restricts collective mathematical interaction amongst them.

Furthermore the ancient Romans under no circumstances whatsoever wouldn't have converted the equivalent of 64 as LXIV because this could be construeded as an act of henious blasphemy against their most powerful of gods Jupiter which translates into Latin as IVPPITER and it is for the same reason that they always wrote out 4 as IIII instead of the abridged version of IV.

Nevertheless irrespective of todays modern notation of Roman numerals inasmuch that there is overwhelming evidence to suggest historically that the Romans would have probably calculated the aforementioned numbers in either of the following formats:-

IMM+ILXV = MMLXIII => (2000-1)+(65-1) = 2063

MMLXIII+IC = MMCLXII => 2063+(100-1) = 2162

Alternatively:-

MDCCCCLXXXXVIIII+LXIIII = MMLXIII => 1999+64 = 2063

MMLXIII+LXXXXVIIII = MMCLXII => 2063+99 = 2162

Note: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M

Values: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1

For more larger and complicated calculations the Romans would have made use of an abacus counting device.

QED by David Gambell

How do you write as a numeral 6057?

what kind of numeral if roman than VIVVII

Another contributor's answer:

6057 is already a numeral set out in Arabic numerals.

Do you mean Roman numerals? If so then the answer is:

VILVII but with an horizontal bar above each of the first two numerals to indicate multiplication by a thousand.

So: 6000+50+5+2 = 6057

How would you actually add together 1914 and 99 in two different ways entirely in Roman numerals with examples and explanations?

Nowadays, because of changes made to the real rules governing the original Roman numeral system introduced during the Middle Ages, we would now convert the equivalent of 1914 and 99 into Roman numerals as MCMXIV and XCIX respectively which doesn't seem to make sense because it inhibits their ability to mathematically interact with each other in some kind of logical order.

However, notwithstanding the aforementioned inasmuch that there still exist historical evidence to show that the ancient Romans would have worked out the equivalent of 1914 and 99 on an abacus counting device as MDCCCCXIIII and LXXXXVIIII respectively and then systematically abridged them to ICMMXV and IC in written format thus facilitating the speed and ease of addition as follows:-

ICMMXV+IC = MMXIII => (2015-101)+(100-1) = 2013

Alternatively:-

MDCCCCXIIII+LXXXXVIIII = MMXIII => 1914+99 = 2013

Values: M=1000 D=500 C=100 L=50 X=10 V=5 and I=1

Note: 5*I=V 2*V=X 5*X=L 2*L=C 5*C=D and 2*D=M

QED by David Gambell

How do you add together 1666 and 1999 in two different ways using Roman numerals?

The real rules governing the original Roman numeral were changed during the Middle Ages presumably to make the system more compatible with the Hindu-Arabic numeral system that was slowly being introduced into Western Europe at the time. So as a consequence of these changes nowadays we would convert 1999 into Roman numerals as MCMXCIX which inhibits their ability to interact sensibly with other numerals.

But there is historical evidence to suggest that the ancient Romans would have worked out the equivalent of 1999 on an abacus counting device as MDCCCCLXXXXVIIII and then systematically reduced them to IMM in written format thus facilitating the speed and ease of addition as follows:-

MDCLXVI+IMM = MMMDCLXV => 1666+(2000-1) = 3665

Alternatively:-

MDCLXVI+MDCCCCLXXXXVIIII = MMMDCLXV => 1666+1999 = 3665

Values: M=1000 D=500 C=100 L=50 X=10 V=5 and I=1

Note: 5*I=V 2*V=X 5*X=L 2*L=C 5*C=D and 2*D=M

QED by David Gambell

How would you precisely work out in two different ways the sum of 1499 plus 19 plus 99 using only Roman numerals throughout both calculations giving reasons why?

With great difficulty because in accordance with the rules and regulations governing todays Roman numeral system that were introduced during the Middle Ages nowadays we would convert 1499, 19 and 99 into Roman numerals as MCDXCIX, XIX and XCIX respectively which makes arithmetical operations with them quite difficult if not impossible at all.

But notwithstanding todays configuration of Roman numerals inasmuch that there is evidence to suggest that the ancient Romans would have probably calculated the equivalent of these numbers in either of the folllowing formats:-

IMD+IXX = MDXVIII => (1500-1)+(20-1) = 1518

MDXVIII+IC = MDCXVII => 1518+(100-1) = 1617

Alternatively:-

MCCCCLXXXXVIIII+XVIIII = MDXVIII => 1499+19 = 1518

MDXVIII+LXXXXVIIII = MDCXVII => 1518+99 = 1617

Remember: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M

Roman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1

Note that if we added I to MCCCCLXXXXVIIII it would then become MD so in order for it to retain its original value we must subtract I from MD therefore it follows that:-

MCCCCLXXXXVIIII = IMD = 1499

QED

What are the two ways of adding together 14 19 49 and 99 in step by step stages using Roman numerals?

Due to changes made to the Roman numeral system during the Middle Ages today we would write out the equivalent of 14, 19, 49 and 99 into Roman numerals as XIV, XIX, XLIX and XCIX respectively in which mathematical interaction amongst them is almost impossible.

But there is strong historical evidence to suggest that the ancient Romans would have probably calculated the equivalent of these numbers in either one of the following formats:-

IXV+IXX = XXXIII => (15-1)+(20-1) = 33

XXXIII+IL = LXXXII => 33+(50-1) = 82

LXXXII+IC = CLXXXI => 82+(100-1) = 181

Alternatively:-

XIIII+XVIIII = XXXIII => 14+19 = 33

XXXIII+XXXXVIIII = LXXXII => 33+49 = 82

LXXXII+LXXXXVIIII = CLXXXI => 82+99 = 181

Note: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M

Values: M=1000, D=500, C=100, L-50, X=10, V=5 and I=1

QED by David Gambell