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Statistics
Statistics deals with collecting, organizing, and interpreting numerical data. An important aspect of statistics is the analysis of population characteristics inferred from sampling.
36,755 Questions
What happens when there is no median in a set?
There's is always going to be a median. Never is there not going to be a median.
What is the median to 8 numbers?
Sort the numbers, and pick the number in the middle. In this case, since you have an even number of numbers, take the average of the two numbers in the middle.
How many 3 number combinations?
That depends on a few factors:
A) How many unique digits can go into each slot?
B) Can a number be repeated? (eg. is 112 invalid because the 1 is used twice?)
C) Does order matter? (eg. is 123 the same as 132)
Assuming n=10 digits and r=3 slots
If repeats are allowed, then we get 10 possible items in the first slot. Since repeats are allowed, we also have 10 in our second slot, and 10 in our third. We don't have to cancel any out because of their ordering.
10 * 10 * 10 = 1000 = 103 = nr
If repeats are not allowed (let's say we have a bag of 10 pieces, each with a number on it. Once you've used a piece, you can't use it again), we can put any of 10 digits in the first slot, any of the 9 remaining in the second slot, and any of the 8 remaining in the third slot:
10 * 9 * 8 = 720 = 10!/7! = n! / ( n - r )!
If order doesn't matter, you'll need to cancel out any combination that is already represented, and there are formulas for that, but explaining it here might be a bit beyond the scope of the question. You'll find a more detailed lesson in combinations and permutations here:
See link below for more lessons on combinations and permutations
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Factor that is changed it is a dependent variable or independent variable?
Its the independent one; because you change it, the dependent variable will be affected.
How many six are in a deck of cards?
4:
6 of Spades
6 of Diamonds
6 of Hearts
6 of Clovers
Four (4). One of each suit.
What is the mean of 18 23 39 10 17 16 and 15?
sum = 138
sample size = 7
138 / 7 ~= 19.714285714285715
How do you calculate the skew?
Skew applies to the average difference between two timing states of a single signal as it transit from low to high and high to low. Skew is frequently refereed to as the Pulse Width Distortion (tpHL-tpLH). When multiple independent and equal device types are used for parallel data transmission, the skew of each device is important since the max and mix Skew can establish the maximum data rate.
What is a three digit number starting with 3 that is a multiple of 7?
301, 308, 315, 322, 329, 336, 343, 350, 357, 364, 371, 378, 385, 392, 399.
How do you hide local variables in c and give precedence to global variables inside the function?
Hi, I would like to answr the question.So, if you want the to give more precedence to global variables with respect to a local one.Just add a pair of curly braces in the local variable and by doing so u can access global variable.
What are the odds of rolling any three pair of numbers using 6 dice?
The odds of rolling any number in one roll of one die is 1 in 1. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll is 1 in 1 times 1 in 6, or 1 in 6.
Now, look at the second pair of dice. The odds of rolling any number other than a number on the first pair is 5 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not the pair in the first roll is 5 in 6 times 1 in 6, or 5 in 36.
Now, look at the third pair of dice. The odds of rolling any number other than a number on the first two pairs is 4 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not one of the first two pairs is 4 in 6 times 1 in 6, or 4 in 36.
To compute the total odds of rolling three pairs of numbers using 6 dice, simply multiply these odds together. That is 1 in 6 times 5 in 36 times 4 in 36, or 30 in 7776. Reducing that to lowest common fraction, you get 5 in 1296.
(This calculation assumes that the three pairs are different. If two or three of the pairs are allowed to be the same, the computation is different.)
