Temperature

The highest temperature ever recorded in Dehradun, India was 41.2°C (106.2°F) in June 1998.

It is approximately 25°C.

In Fahrenheit it is approximately 78°F

It is also approximately 298 K

52.1 degrees Celsius is equal to 125.78 degrees Fahrenheit.

To convert degrees Fahrenheit to degrees Celsius, subtract 32, multiply by 5, and divide by 9. In this instance, -25 - 32 = -57 x 5 = -285 / 9 = -31.6 recurring (that is, -31.6666...) degrees Fahrenheit.

The presence of impurities typically raises the boiling point of a substance. This is due to the impurities disrupting the crystal lattice structure and reducing the ability of the liquid to vaporize, thus requiring a higher temperature to achieve boiling.

Use this equation to convert degrees Fahrenheit (ºF) to degrees Celsius/Centigrade (ºC): [°C] = ([°F] − 32) × 5⁄9

102.7F equals 39.28C

K, which stands for Kelvin is an absolute temperature scale in that it starts at 0 K and 0 K is the lowest possible temperature (a.k.a. absolute zero). Absolute zero on the Celsius scale is -273.15 C. To turn any temperature in Kelvin to degrees Celsius, simply subtract 273.15, so that in your case the answer is 55.85 C.

97 degrees Fahrenheit = 36.11 degrees Celsius

57 degrees Fahrenheit = 13.89 degrees Celsius

45 degrees Celsius is equal to 113 degrees Fahrenheit. The formula to convert Celsius to Fahrenheit is (Celsius * 9/5) + 32.

30 degrees Celsius is equal to 86 degrees Fahrenheit.

To convert from Fahrenheit to Celsius you use the equation (F-32.0) x (5/9) = Celsius. So when you plug 108 in for F:

(108-32) x (5/9) = 42.2

If you meant 108 degrees Kelvin to Celsius you use the equation C + 273 = K where C. Plugging in 108 for K we get:

C + 273 = 108 -> C = -165

40 degrees Celsius is equal to 104 degrees Fahrenheit. To convert Celsius to Fahrenheit, you can use the formula: F = (C * 9/5) + 32. So, for 40 degrees Celsius, it would be (40 * 9/5) + 32 = 104 degrees Fahrenheit.

The melting point will be lowered and broadened.

Incomplete drying of a sample may result in the presence of impurities. When impurities remain present in a sample, the melting point is both lowered and broadened. For example, if the normal mp of a substance is 104C - 106C, an improperly dried substance may contain impurities thus lowering and broadening the melting point range to something like 85C - 97C. (Note: these numbers are just arbitrarily chosen for the purpose of the example).

The record high temperature in Akron, Ohio in the last 100 years was 104°F, which was set on July 14, 1936.

The freezing point of a liquid is the temperature at which it solidifies into a solid, while the melting point of a solid is the temperature at which it changes into a liquid. These two temperatures are the same because at both points, the substance is in equilibrium between its solid and liquid form, with no net change in phase occurring.

1 ºC = 1 K

The two scales have the same size graduations but different starting points. -273.15 degrees Celsius = 0 K

0 ºC = 273.15 K

Note: these units are always capitalized as they are named after scientists ie their surnames.

No, gold is not a liquid at 2000 degrees Celsius. Gold has a melting point of 1064 degrees Celsius, so at 2000 degrees Celsius, it would definitely be in liquid form.

The highest recorded temperature in Buffalo, New York is 104 degrees Fahrenheit, which occurred on July 9, 1936.

1 degree Fahrenheit = -17.2 degrees Celsius.

NO, this is impossible. 0 K, or -273 *C can never be reached. In deep space, it can be 0.1 K or so, which is really cold. Heat 'spreads' from a hotter place to a colder, so if there were ever a place with absolute zero, some heat would immediately go there. Then, that point would probably reach a point possibly just above absolute zero.

No, this is reversed. 50 Fahrenheit = 10 Celsius.

To determine the time this will take, you need to know the rate at which heat is being added to the system. The specific heat capacity of a substance is the amount of energy required to raise the temperature of one gram of a substance one degree centigrade. For water at 25oC, the specific heat capacity is 4.184 J*g-1*oC-1. That is, if you have one gram of water, you must add 4.184 Joules of energy (heat) to raise the temperature one one degree centigrade.

The time it takes for the temperature increase to happen depends on how quickly you add the 4.184 J. Adding heat at a rate of 1 Joule/second (which is equivalent to 1 Watt), it is easy to see that it will take 4.814 seconds to raise the temperature of the gram of water one degree centigrade.

The first step to solving your problem, then, is to make your data units compatible with your known constants. We need to convert volume to mass. We do this by means of density. The density of liquid water at standard temperature and pressure is 1g/mL.

1L H2O *1000mL/1L *1g H2O/mL H2O= 1000g H2O

Then, to find the amount of energy required to change the temperature of the mass, we use the specific heat.

1000g H2O *4.184J/(g*K)= 4184 J/oC

Note the units on this last value. They give the amount of energy needed required per degree centigrade of change in the temperature. That is, it requires 4814J to change the temperature of 1000g H2O one degree centigrade. Given the time rate of heat transfer into the system, you can find the time required to make the change. If, for instance, your heat exchange rate is 5 Watts (J/s), you would have

4184 J/oC * 1 second/5 Joules = 836.8 s/oC

This value allows you to calculate the time required for any change in temperature simply by multiplying the number of degrees centigrade temperature change. For one degree, we find

836.8 s/oC *1oC = 836.8s