Trigonometry

i would suppose so trig is just a series of forms and proves to find an unknown or a know factor.. trig can and has been used to measure distance and height before so i would have to say yes you can.. as long as you have all the given factors needed

sin is short for sine, cos for cosine, tan for tangent. These functions are defined in several ways; one way is with a unit circle - a circle with radius 1, in which angles are measured starting on the right, and then counterclockwise. In this case, the sine is the y-coordinate on the circle - as a function of the angle. For example, for an angle of 0°, the y-coordinate is 0; for an angle of 90°, the y-coordinate is 1. Therefore, the sine of 0° is said to be zero, and the sine of 90° is said to be one. Similarly, the cosine is the x-coordinate. The tangent of x is the ratio of sine x / cosine x. - Note that in advanced math, angles are often measured in radians instead of the (rather arbitrary) degrees.

An altitude.

The sine of an angle in a right triangle is opposite/hypotenuse, where opposite is the only side that is not adjacent to the angle you want to find the sine of, and the hypotenuse is the side opposite the right angle in the triangle.

Just find opposite/hypotenuse.

The sine ratio plays an important part in the refraction of light at the interface of two media through which the light travels - such as the interface between air and the glass of a lens.

try using my formula....

ar=a(1/2)^2t

therefore, 57(.05) = 57(1/2)^2t

and 57s cancels out, .05 = 1/2^2t

log .05 = log .5^2t

divide log .5 from both sides,

4.32 = 2t

t = 2.16, therefore 126 seconds or 2 minutes and 6 seconds

The answer depends on what other information is available to you.

The largest angle will be opposite the longest side which is 14 cm and by using the cosine rule it works out as 106.23 degrees rounded to two decimal places and its area is 0.5*9*8.5*sin(106.23) = 36.726 square cm to three decimal places.

The problem with trying to learn things is that sometimes you do not have the experience, or the readiness, to learn them. When the teacher has a particular thing to teach and there is not any other way that the work can be done then their comments can seem like they don't listen. I have heard comments like this about different teachers and it often has to do with not agreeing with a student request to change the assignment or expectation. Most teachers are there because they do want to pass on the information, so the thing is to figure out what you need to ask to get what you need.

cos(2x) = 1 - 2(sin(x)^2), so sin(x)^2 = 1/2 - 1/2*cos(2x).

my answer is 5

almost all kind of engineer

Ok, im not positive about this but here is what i got. (ca=cos(a),sa=sin(a),cb=cos(b)ect)

ca=1/3 | ca^2=1/9 | sa^2=1-ca^2 | sa^2=8/9 | sa=.943

Sin(a)=.943 Cos(a)=.333 Tan(a)=2.832

sb=-1/2 | sb^2=1/4 | cb^2=1-.25 | cb^2=3/4 | cb=-.866

Sin(b)=-.5 Cos(b)=-.866 Tan(b)=.577

Tan(a+b)=(Tan(a)+Tan(b))/(1-2.832*.577)

Tan(a+b)=3.41/-.634

Tan(a+b)=-5.376

So that's what i got. If you have any questions or if you got a different answer you should email me. actually email me regardless, i want to see if i got it right. allonbacuth@gmail.com

The ladder forms the hypotenuse (r) and the wall forms the vertical (y) of a right triangle. sin theta = y / r the angle at the bottom is (90 - 32) = 58

sin 58 = 20 / r

r = 20 / sin 58 = 23.583568067241928552025478405751 feet

ladder must be about (rounding) 23.6 feet long.

2sin2(6x) + 3sin(6x) + 1 = 0

Solving the quadratic,

sin(6x) = -1 or sin (6x) = -0.5

sin(6x) = -1 => 6x = 45+60n degrees for integer n

sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.

2sin(x), or 5.4cos(y), tan(z)

Negative cosine

f(x) = sin(x)

f'(x) = -cos(x)

If they put their mind to it, it is not difficult.

It is the hypotenuse

yes

If it's a right triangle, use pythagorean's theorem (a2+b2=c2) to solve it. =

If it's an oblique triangle, use the law of sines or cosines (see related link)

A relation is a mapping between two sets, a domain and a range. A function is a relationship which allocates, to each element of the domain, exactly one element of the range although several elements of the domain may be mapped to the same element in the range.

Angular displacements measured in radians or stradians, lengths of lines measured in units of length.

Using trigonometry its smallest angle is 43.84 degrees and its area is 18.2 square cm

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Using the cosine rule to find the angle:

a² = b² + c² - 2bc cos A
→ cos A = (b² + c² - a²)/(2bc)
→ A = arccos ((6.4² + 8.2² - 5.7²)/(2 × 6.4 × 5.7)) ≈ 43.8°

Area = ½ × b × c × sin A ≈ ½ × 6.4 cm × 8.2 cm × sin 43.8° ≈ 18.2 cm²