Amount of Fe = (2.71x1024)/(6.02x1023) = 4.50mol
The Atomic Mass of Fe is 55.8
Mass of Fe = 4.50 x 55.8 = 251g
251.33 grams of iron.
251 grams
251.33
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
Quite a few! 147 grams calcium (1 mole Ca/40.08 grams)(6.022 X 1023/1 mole Ca) = 2.21 X 1024 atoms of calcium ----------------------------------------
Avogadro's Number, 6.022 x 1023 gives the number of atoms in one mole. Calcium has an average atomic weight of 40.08 gmol-1 So one mole weighs 40.08 grams. 115 grams of Calcium will have (6.022 x 1023 / 40.08)*115 = 1.73 x 1024 atoms.
118.7 is close to the 118.96 grams per mole (mass) of tin. So we can call that one mole. 1 mole is equal to 6.022x10^23 (avogadro's number which is the number of atoms per mole of an element).
450.3915Calcium Carbonate (CaCO3) has a molar mass of 100.087 g/mol.4.5 mol * 100.087 g/mol = 450.3915 (because the mol's cancel leaving you with grams)
341 grams scandium (1 mole Sc/44.96 grams)(6.022 X 1023/1 mole Sc) = 4.57 X 1024 atoms of scandium =====================
1 mole C = 6.022 x 1023 atoms 2.408 x 1024 atoms C x 1mol/6.022 x 1023 atoms = 3.999 moles C
2.3 X 1024 atoms / 6.022 X 1023 atoms/mole X 107.87 gm/mole of silver = 412 grams
There are 3.275 moles of calcium in 131 grams as relative atomic mass of calcium is 40. Therefore there are 1.972 x 1024 atoms.
1.88 X 1024 molecules SO3 (1 mole SO3/6.022 X 1023)(80.07 grams/1 mole SO3) = 250 grams sulfur trioxide ===================
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
31.8 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C)= 1.59 X 1024 atoms of carbon===================
Quite a few! 170 grams ammonia (1 mole NH3/17.034 grams)(6.022 X 1023/1 mole NH3) = 6.01 X 1024 atoms of ammonia ========================
The atomic weight of Li is 6.941 g/mol The mass of the sample is 55.2 g This means that: 55.2/6.941=7.95 moles (rounded number) Multiplying this with Avogadro's number (6.022*1023) 7.95*6.022*1023=4.79*1024 atoms. There you have your answer.
Fairly heavy! 1.14 X 1024 atoms of iodine ( 1 mole I/6.022 X 1023)(126.9 grams/1 mole I) = 240 grams of iodine -------------------------------
64 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S) = 1.2 X 1024 atoms of sulfur ====================
To convert mass to atoms:Find the atomic mass of the element in the substance. You can find atomic masses on the periodic table. Ex. Lithium's atomic mass is 6.9 grams (round if you need to)Then find the mass of the substance in grams. Ex. you have 18.2 grams of a sample of Lithium.The mass of the sample is multiplied by 6.02 * 1023 and divided by the atomic mass.Ex.mass of sample in grams * (6.02 * 1023 atoms) / (atomic mass) = # atoms in grams18.2 grams * (6.02 * 1023 atoms) / (6.9 grams) = 1.59* 1024 atomsThe number 6.02 * 1023 is Avogadro's Constant which is the amount of atoms (or molecules) in one mole.