Moles = Mass/Molar Mass.
Using this equation, we can take 25/(1.0 + 19) and find that it is equal to 1.25 moles.
Keep in mind that very few significant figures were used for this example (2), and that if accuracy is to be expected, as many as possible should be used.
3 moles is 3 moles.
Three moles of HF have 60,03 g.
20g
Fe2(CrO4)3 3.71 moles Fe2(CrO4)3 (3 moles CrO4/1 mole Fe2(CrO4)3) = 11.1 moles of chromate
The volume occupied by 3 moles of nitrogen gas will be different, depending on the temperature and pressure of the gas.
3 moles of ammonia is 51grams. One mole is 17 grams.
2N + 3H2 -> 2NH3 18 moles H2 (2 moles NH3/3 moles H2) = 12 mole ammonia
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
The answer is 50 moles SiO2.
The gram molecular mass of HF is 20.01. Therefore, 0.589 mole has a mass of 11.79 grams and is sufficient to form 0.589 mole of sodium fluoride* when sodium is present in excess. The gram molecular mass of sodium fluoride is 41.99, so that 0.589 grams of it has a mass of 24.7 grams, to the justified number of significant digits. __________________________ The formula unit of both hydrogen and sodium fluorides contains a single fluorine atom.
60
An 0.010 M HF solution gives pH = 2.6, so 0.0022 molesare present in 0.22 L
60 g
Here is the solution,for 1mole NH3 or ammonia,N: 14.0067 g/mol x 1H: 1.00794 g/mol x 3So approximately it is--> 17.03052 g/mol)Now multiply this into 4.5 for 4.5 moles of ammonia, --> 4.5x17.03052 =76.64g
0.36 moles of SnF2
3
The answer is 3 moles of Cu)NO3)2..
NH3 is balanced at 1:3, so in 3 moles NH3 there are 3*3 = 9 moles H atoms
When 3 moles Cu react 3 moles of copper nitrate are obtained.
The answer is 3 moles.