If the reaction is just between O2 and Al, the balanced equation would be:
3O2 + 4Al -> 2Al2O3
By using the coefficients of the equation, we see that from 3 moles of O2 we get 2 moles of Al2O3. To find out how much this is in grams, we need to find the molar mass of Al2O3 . This is just the sum of the atomic masses of each atom that makes it up. (Use a Periodic Table to find atomic masses) So we get:
26.98*2+16*3= 102.0
One mole equals 102g, so the 2 moles produced by the reaction would amount to 204g.
The mass in grams of 3 moles of oxygen atoms is 48.
Not many! 5.0 grams CaBr2 (1 mole/199.88 grams CaBr2) = 0.025 moles CaBr2
Multiple the moles of K2SO4 by the molecular weight of 174.2592 grams. That should equal 210.85 grams.
moles = weight in grams / molecular weight = 72 / 180 = 0.4 moles
For this you need the atomic mass of Au. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.355 grams Au / (197.0 grams) = 1.80 moles Au
just short of a mole. moles is mass/molar mass. mass is 42, molar mass is 44. 42/44
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
2Al + 3O2 --> 2Al2O3 0.78 moles O2 (2 moles Al2O3/3 moles O2) 0.52 moles Al2O3 produced ===========================( assuming oxygen limits )
1.5 moles of O2 react with 2 moles of Al 2Al + 1.5 O2 = Al2O3.
so you find the ratio of Aluminum to Oxygenin this case it is 2:3and then because the total mole is 2.16for aluminum:2.16/5*2 = 0.864for oxygen:2.16/5*3 = 1.296hope this helped :D
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
234 grams
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
Well to find how many grams are in moles you would eventually multiply the mole by the molar mass. The molar mass of aluminum oxide would be 101.96 ( you would find that by multiplying the atomic mass of al by 2 and o by 3 and adding them together). But the molar mass of Oxygen is just about 48 (rounded to 16 instead of 15.9994)5.75 moles of Al2O3 X 48 g oxygen/1 mole of Al2O3=276 g oxygen in 5.75 mole Al2O3
10.25L
Number of moles = weight (in g) / molecular weight = 6.80 / 101.961 = 0.0667 moles or 66.7 milli moles.
16 grams of oxygen how many moles is 0,5 moles.