Elements and Compounds

What is the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water?

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2010-05-21 19:44:05
2010-05-21 19:44:05

since molarity = (number of moles) / (volume of solution),

the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water will be 5.11 moles.

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2020-06-10 22:01:54
2020-06-10 22:01:54

Hi

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Anonymous
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2020-04-14 15:21:28
2020-04-14 15:21:28

5.1

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Related Questions


Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------


Molarity = moles solute/ Liters solution


Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ==================


This depends on the mass of sodium chloride dissolved in a known volume of water.


The molarity of sodium chloride in a solution containing 0.50 mol of sodium chloride in 500 mL of water would be 1M. 0.50 moles in 500mls means there are 1.0 moles in 1 liter.





Molarity is moles/liter, so in order to find the moles of a substance in a given volume, simply multiply molarity with volume (in liters). n=M*V


Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------



2 moles in 0.5 liters will mean 4 moles in 1 liter. So the molarity is 4 molar.


Molarity = moles of solute/Liters of solution ( find the moles ) 2.36 M NaCl = moles NaCl/5.08 Liters NaCl = 12.0 moles


Pretty concentrated! ( I assume you mean 2.3 Liters )First get the moles of sodium chloride.456 grams NaCl (1 mole NaCl/58.44 grams)= 7.803 moles NaCl==============Now,Molarity = moles of solute/Liters of solutionMolarity = 7.803 moles NaCl/2.3 Liters= 3.4 M NaCl solution----------------------------


0,45 L of 2,5 M sodium chloride solution contain 65,7 g salt.


Get moles sodium sulfate first.15.5 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.1091 moles Na2SO4Now,Molarity = moles of solute/ Liters of solution ( 35 ml = 0.035 Liters )Molarity = 0.1091 moles Na2SO4/0.035 Liters= 3.1 M Na2SO4 solution==================


Molarity (M) = mols/liters. In this case:M = 2.0 moles / (.200) Liters = 10 Molar.


Molarity = moles of solute/Liters of solution Find moles NaCl 9 grams NaCl (1 mole NaCl/58.44 grams) = 0.154 moles NaCl Molarity = 0.154 moles NaCl/1 Liter = 0.2 M sodium chloride -------------------------------


Having the Molarity, concentration, helps. Molarity = moles of solute ( gotten from the grams put into solution ) divided by Liters of solution. Then. - log( Molarity of compound ) = pH ====( if basic subtract from 14 )



Sodium chloride solution is not an indicator.


The solution of sodium chloride is an electrolyte.


Salt in water is sodium. Ringer's lactate solution (sodium lactate solution and Hartmann's solution), is a mix of sodium chloride, sodium lactate, potassium chloride, and calcium chloride in water. Sodium Chloride is a mix of sodium and chloride.


The sodium chloride solution of sodium chloride in water is homogeneous.


Yes, ions of sodium (+) and chloride (-) in solution.



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