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What is the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water?
Wiki User
∙ 13y ago
RMM OF NaOH= 23+16+1= 40g/mol
# mol of NaOH= 42/40= 1.05 mol
Concentration= mol/dm
1.05 mol=2.3dm3
X mol = 1 dm3
X=(1.05*1)/2.3
X=.04565M
Wiki User
∙ 14y ago
Wiki User
∙ 12y ago0.450 (mol) / 2.10 (L) = 0.214 mol/L NaOH = 0.214 M
Wiki User
∙ 12y agoNaF has an Atomic Mass of 42, therefore if you dissolve 42 grams (1 mole) of it in 2 liters of water you get a molarity of 0.5 moles/Liter.
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∙ 13y agosince molarity = (number of moles) / (volume of solution),
the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water will be 5.11 moles.
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How many grams of sodium chloride is in 0.40 moles?
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