Hello young chap, so I heard you were wondering what the solubility of sulfur dioxide at 40 degrees Celsius is in grams. Well, I'm here to help.
So I like to break this kind of stuff down to the shrimp. So you have to just imagine a beluga whale...and a narwhal. Got the visual? Okay good. So now there's a lot of algae and other things floating on top of the water and the beluga whale really wants to eat it, however something is stopping it. Something like a mermaid. So usually people might picture a mermaid that's beautiful and majestic...but NO. This mermaid is very freaky and alien like. So basically, the beluga is forced to murder this mermaid and it's entire family (you know, just to be safe) and it begins to eat the yummy aquatic plants. However, on the corner of it's eye, it spots some sulfur dioxide swimming with a narwhal. Now, the beluga whale suddenly feels its adrenaline rush throughout its veins for he was jealous. Just two days ago he asked the sulfur out on just one date, however he was rejected. Now he sees this strange narwhal walking around with his girl. The beluga whale attempts to attack the narwhal at a 40 degree angle, however sulfur dioxide pulled out its Celsius out of the grams and stabbed the beluga whale until the entire sandbox was filled with blood. Narwhal was in complete shock. Sulfur dioxide was now curious as to how much this Celcius could have weighed if it was capable of murdering this beluga whale and it got 54 g/kg. This solved all of the mysteries of the world.
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There is 1 molecule of sulfur in sulfur trioxide so there is 1 mole of sulfur in 1 mole of sulfur trioxide
We assume 100 grams of compound and change % to grams. Get moles. 40 grams S (1 mole S/32.07 grams) = 1.247 60 grams O (1 mole O/16.0 grams) = 3.75 Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value. 3.75 mole O/1.247 mole S = 3.00 SO3 ------- is the empirical formula
The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
40*4=160g
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There is 1 molecule of sulfur in sulfur trioxide so there is 1 mole of sulfur in 1 mole of sulfur trioxide
0.09375 moles. Calcium's molar mass is 40, so mass/molar mass (3.75/40) gives 0.09375.
We assume 100 grams of compound and change % to grams. Get moles. 40 grams S (1 mole S/32.07 grams) = 1.247 60 grams O (1 mole O/16.0 grams) = 3.75 Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value. 3.75 mole O/1.247 mole S = 3.00 SO3 ------- is the empirical formula
The answer is 2337,59 g NaCl.
The reaction equation is 2 NaHCO3 + H2SO4 = 2 CO2 + 2H2O + Na2SO4. This means that for every mole of sulfuric acid, two moles of NaHCO3 are needed. 150 grams of H2SO4 is 1.53 moles, so 3.06 moles of NaHCO3 are required.
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
There are 3.275 moles of calcium in 131 grams as relative atomic mass of calcium is 40. Therefore there are 1.972 x 1024 atoms.
mass divided by molar mass gives moles: 20 g NaOH / 40 g.mol-1 = 0.5 mol NaOH
Molarity = moles of solute/volume of solution 0.450 M = m/200ml = 90 millimoles, or, what we need; 0.09 moles 0.09 moles NaOH (39.998 grams NaOH/1 mole NaOH) = 3.60 grams of NaOH needed