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How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
How many moles of hydrogen must react to produce 68 grams of ammonia?
To calculate the moles of hydrogen needed to produce 68 grams of ammonia (NH₃), we start with the balanced chemical equation for the synthesis of ammonia: N₂ + 3H₂ → 2NH₃. The molar mass of ammonia is approximately 17 g/mol, so 68 grams of NH₃ corresponds to 68 g / 17 g/mol = 4 moles of NH₃. Since 3 moles of hydrogen are required for every 2 moles of ammonia, the moles of hydrogen needed is (4 moles NH₃) × (3 moles H₂ / 2 moles NH₃) = 6 moles of H₂. Therefore, 6 moles of hydrogen must react to produce 68 grams of ammonia.
How many moles s are present in 1 g of ammonia?
1 g of ammonia (NH3) is equal to 0,059 mol.
What would be the Mass of 3 moles of ammonia and calculate the number of ammonia molecules?
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
How many moles of nitrogen would be needed to completely react with 12 moles of hydrogen according to the balanced equation given below?
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
How many moles in 0.75 moles of ammonia?
this is a easy one. There are only 0.04166 moles.
How many moles of ammonia is 170000grams?
To find the number of moles in 170000 grams of ammonia, you need to divide the given mass by the molar mass of ammonia. The molar mass of ammonia (NH3) is about 17 grams/mol. Therefore, 170000g ÷ 17g/mol ≈ 10000 moles of ammonia.
How many moles of ammonia are produced from 12.0 moles of hydrogen?
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
How many moles are present in 1 g of ammonia?
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
How many moles of water vapor can be produced from 2 moles of ammonia?
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
How many moles of ammonia can be produced from 18 moles of hydrogen?
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
How many moles of ammonia are produced from the reaction of 90.0 L of nitrogen?
8,038 moles of ammonia were produced.
How many moles of hydrogen atoms are contained in 3 moles of ammonia?
Since ammonia has a chemical formula of NH3, it contains one mole of nitrogen and three moles of hydrogen per mole of ammonia. Therefore, 3 moles of ammonia contain 3 moles of nitrogen and 9 moles of hydrogen atoms.
How many calories are in a 136g avocado?
A single 136g avocado (approx. 4.8oz) has 227 calories.
How many molecules of ammonia NH3 are present in 0.522 moles of ammonia?
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
