For this you need the atomic (molecular) mass of CO. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel.
4.5 grams / 28.0 grams = .161 moles CO
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
382 g Co contain 6,482 moles.
To determine the number of moles of oxygen needed to react with 4.52 moles of carbon monoxide (CO), we refer to the balanced chemical equation for the reaction: 2 CO + O₂ → 2 CO₂. From the equation, 2 moles of CO react with 1 mole of O₂. Therefore, to find the moles of O₂ required, we can use the ratio: (4.52 moles CO) × (1 mole O₂ / 2 moles CO) = 2.26 moles of O₂. Thus, 2.26 moles of oxygen are needed to react with 4.52 moles of CO.
26,3 g cobalt is equivalent to 0,446 moles.
0,83moles glucose are burned.
4,54 L of CO have 0,182 moles.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
382 g Co contain 6,482 moles.
If 1 mole of carbon reacts, 1 mole of CO is produced according to the balanced chemical equation for the reaction. Therefore, if 1.4 moles of carbon react, 1.4 moles of CO will be produced.
To find the number of moles of CO molecules in 52g of CO, we first need to determine the molar mass of CO, which is approximately 28 g/mol. Then, we divide the given mass by the molar mass to get the number of moles. So, 52g of CO is equivalent to approximately 1.86 moles of CO molecules.
26,3 g cobalt is equivalent to 0,446 moles.
0,83moles glucose are burned.
1,4 moles carbon monoxide are produced.
From the balanced chemical equation 3Fe2O3 + CO → 2Fe3O4 + CO2, it can be seen that 3 moles of Fe2O3 react with 1 mole of CO to produce 2 moles of Fe. Therefore, if 25 moles of CO react, it will produce 25/3 * 2 = 16.67 moles of Fe.
To determine the number of moles in 382 g of cobalt (Co), first calculate the molar mass of cobalt, which is approximately 58.93 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. Moles = 382 g / 58.93 g/mol = approximately 6.48 moles of Co atoms.
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
350 g sample of CO contain 12,49 moles.