Electrical Engineering

Resistors and MOSFET/ transistors are two different animals, sory but

The gain of a common-emitter amplifier is collector resistor divided by emitter resistor, or hFe, whichever is less. Since hFe depends on temperature, designing the amplifier to be dependent on resistance ratio makes it more stable. As such, the emitter resistance serves to stabilize the amplifier.

E coils, or E coil springs, are typically used in various mechanical applications, such as automotive suspension systems, mattresses, and furniture. They are not a biological entity with a natural habitat, but rather an engineered product designed to provide support and flexibility. Their "habitat," in a metaphorical sense, would be any environment where they are utilized to absorb shock or provide structural support.

A: If you know the total resistance and total voltage then you know total current flow for the circuit, this current will be same for every resistor in series however the voltage drop will change for each resistor . So measuring the voltage drop across the resistor in question and divide by the total current will give you the resistor value.

If a circuit is being changed, first make a modified drawing to fulfill the requirement. Once you have the correct modified drawing, get the wiring changed. test the circuit for safety and functionality to ensure what you have done is correct. Compare the modified drawing against the standards you followed.

A 100 horsepower electrical motor would consume 74,600 watts.

hp or power is torque/time (rotating motor)

3000# can be lifted 10' in a minute with 1Hp

30,000# can be lifted 1' in a minute with 1Hp

1000 tons can be lifted 1' in an hour with 1 hp

Actually they just stay there.

Seriously, power lines start from a power station (thermal, hydel, nuclear, etc.) and extend to consuption areas. major Substations in say (a state) is connected to substations in towns or town areas. There can be several levels of substations. From the lowest level substation the lines connect to houses, offices, commercial entities, etc.

An overloaded circuit is an electric circuit that is carrying more current than it is designed to handle, creating a danger of fire through overheating. This often occurs when too many appliances are connected to a circuit at one time.

This question cannot be answered as asked. you would need to know also the voltage and phasing.

Assuming we are dealing with 120-volt, single phase, 11,500 watts would be 55-running amps.

Assuming we are dealing 208-volts, three phase, 11,500 watts would be 32 running amps

and assuming we are dealing with 250-volt three phase, 11,500 watts would be 26.5 running amps.

I hope I have answered your question.

Ripple voltage is a voltage with an impure wave that isn't stable at all. Usually when you overload an AC to DC converter, it tends to do that.

In a single phase system the neutral wire is the return path of the circuit and may be near ground potential, in multiphase systems it carries the unbalanced current.

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In a single phase system where only one "hot" wire supplies current to the load, the "neutral" wire completes the circuit and carries the current flowing from the load back to the power station.

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As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.
Before you do any work yourself,
on electrical circuits, equipment or appliances,
always use a test meter to ensure the circuit is, in fact, de-energized.

IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOB
SAFELY AND COMPETENTLY
REFER THIS WORK TO QUALIFIED PROFESSIONALS.

yes, with additional circuitry. an opamp wired as a differentiator followed by an opamp wired as a comparator can provide short timing periods. an opamp wired as an integrator followed by an opamp wired as a comparator, plus some other circuits left as an exercise to the reader can provide long timing periods.

If the internal capacitors are separate, I mean that there are 4 terminals, a separate positive and negative for each internal cap then you can connect them in two ways. If you connect them in parallel (positive to positive and negative to negative) you just add the values together, so if each is 100UF they total 200Uf and the voltage you can apply is whatever is rated on the body. If you want to increase the voltage so you can apply higher voltage you connect them in series, one of the negatives connects to the others positive and the remaining inputs are connected to the circuit (and if each is equal in value) you divide by two so they would only be 50UF in capacitance but the total voltage you can apply is double the rated level on the body. If the caps are of different values it gets more complicated, you have to calculate the C total buy using the following formula: 1/C total = 1/C1 + 1/C2. Then the voltage dropped across each cap is proportional to the values you calculated above. Remember, the total voltage will be dropped across the caps proportionally so if the caps are rated at 50V for example and they are not equal values, you can't connect them up to 100V because the larger of the caps will have more than 50V across it because of the mis-matched value of each.

In electrical systems, "RM" typically refers to a "relay module." A relay module is an electrical device used to control a circuit by interfacing input signals with high-power output components. It helps in automation and protection of electrical systems by allowing them to be controlled remotely or automatically.

A DC to AC inverter takes a DC voltage input to a AC voltage output. So if you have a 12v battery and need to run a 120v AC tool or something. All you need to do is plug a inverter to your battery and plug your 120v tool the the inverter. Takes all there is too it.

good question - Understand a nerve ok - I like to use an old Oak Tree for example that has no dead leaves - Now the Tree has many branches like a nerve

Now we pluck this tree from the earth and hold it upside down - follow me - and we suspend it upon another old oak tree with no leaves on the earth. So The big Old Oak Tree above is upside down with it's many branches and the other oak tree is on the Ground - the Two trees almost touch but don't - cause of the wind and the atmosphere perhaps even the fog - Now you see the Dendrites and The Nervous System withing the Great Cerebral Commisure - the synapse will be the fog and the humidity on our little jest or journey in time depends on our chemical balance within our synapse that is the wind between the tree

Motor run delta connection because in delta connection it is less ampere needed and it sometimes it change the wye connection because of the available suply

The expression for the current (I) is simply the voltage (V) divided by the total impedance (Z).

In your example its (40+j25) V divided by (R + / - j) Ohms.

We aren't given the dc resistance of the inductor so assuming it is zero.

Resistance of resistor is 20 Ohms.

Reactance of inductor is 2 * Pi * Freq * Inductor value in Henries. gives

2*3.14*79.5*0.6 = 299.7 Ohms.

So total impedance Z is (20+j299.6) Ohms....say (20+j300) Ohms

Now Complex series current I = V/Z = (40+j25) V / (20+j300) Ohms

Rather than taking surds we simplify to polar form here.

V = (40+j25) = 47.17 Volts at phase angle 32 degrees

Z = (20+j300) = 300.7 Ohms at phase angle 86.2 degrees

So current is 47.17 V /300.7 Ohms and phase angle is (32 degrees - 86.2 degrees)

I = 0.157 Amps at angle -54.2 degrees

Changing this to rectangular form gives (0.092 -j0.127) Amps

Power = (current) times (voltage)

Current = (Power) divided by (voltage)

Voltage = (Power) divided by (current)

Typically fault currents are high at buses. I'm assuming you're referring to fault current from a particular source is low at a specific bus. Fault current will drop off as more resistance is added between the source and the fault (ohms law). This is why fault currents are typically high at a bus - you often have many lines coming into a bus from multiple sources, so the apparent impedance from these sources is less (less resistance).

The power factor measures the phase difference between a current and a voltage waveform. Power factor ranges from zero to one. A power factor of 1 is for a pure resistive load. Power factor decreases for loads like motors with high inductance. Power factor comes into play when determining the watts used by a device. Watts = Volts x Amps x PF. So ideally for efficiencies sake, you want to keep the PF as close to one as possible.

Scaler. Its vector counterpart is the electric field.

Capacity to the equivalent of the battery is reduced - that is, you'll run out of charge quicker but the voltage delivered will still be the same.

I asked this very question to my professor in electronics 101 in college! He explained to me the load side of the transformer if not connected to any load is open. This is a great

resistance to completing the circuit. This is transferred to the primary side of the transformer as a great resistance thus no current flow.