Electrical Engineering

Efficiency of any electrical machine is maximum when the load on that machine is such that the variable loss ( copper loss) is equal to constant loss (eddy current loss, hysteresis etc).the same applies to dc machines too.

the moter used in mixi is sharped motor

The SIL=(KV LL / Zo), where the V(LL) is the receiving end voltage in kV and Zo is the surge impedance in ohms. when the line is loaded over its SIL, it behaves like a shunt reactor - absorbing Mvar from the system, and when is loaded less its SIL it behaves like a shunt capacitor, supply Mvar back to the system.

So to increase the Surge Impedance Loading (SIL), we need to decrease the the surge impedance of the line, and that can be done by introducing series capacitors (capacitors in series with the transmission line) or shunt capacitors (capacitors in parallel with transmission lines), which means providing Mvar to the system and reducing the Mw.

hopefully that helps

Assuming the generator is in good condition and designed to be connected to a power grid. A generator can be connected by ensuring the generator is at very nearly the same speed as the grid (typically very slightly faster) and is generating a similar voltage. When the phases of the generator and grid align, the circuit breakers can be closed and the generator will become locked to the grid. If the generator is connected to the grid without being in phase, the difference in phase will allow significant current to flow and in some situations can actually be worse than a direct short circuit. As a result of this power companies use sophisticated equipment to ensure that generators can be safely connected to the grid without damage.

Household, camping and most industrial generators are not designed to be synchronised with the grid and should not be connected to a grid system.

It's approximately the inverse of the voltage- or turns-ratio:

Very unlikely unless you create a short of some type with the probe.

If two circuit elements (e.g., two resistors) are in series (a series circuit), the current has to pass first through one, then through the other. If they are in parallel, the current has a choice, through which of the elements it passes.

As this relates to EE, the electrons are already in there.

A 2 form C relay has a common coil so, no, we can not respectively control the throws of a 2 form C relay. The two throws operate together.

a resistor

A: BY adding resistance to one or all branches will reduce the voltage drop across any branch. But also the current will be reduced accordingly

No

ANSWER: lead is poisonous to humans on a grand scale. like mercury It collects and add up.

certainly putting solder the mouth is bad. Lead replaces calcium

The question isn't very clear. You don't need an op amp to decrease a signal amplitude by 50% / 3dB / .5. You could use a carefully set up voltage divider. But if you are in need of a buffering circuit for either the input or the output, an op amp is a cheap, well designed, and easy to use solution.

you dont need round the clock attendants or valets

you tend to need more expensive labor to fix the machines tho

these can be part timers since we have cell phones now

possibly cheaper than live parking attendants but response time is a LOT slower

you can regulate either, it depends on the requirements of your circuit.

It is the tendency of alternating current to flow more in the outer part of the conductor than in the centre. This reduces the effective cross-section area of the conductor. For this reason conductors with a diameter of more than about 30 mm are uncommon.

Line current = 10MW / 500kV = 20A

Assuming the 1000 ohms is the resistance of the entire transmission line, end to end.

Power loss = line current ^ 2 * line resistance = 20A ^ 2 * 1000 ohms = 400 KW

The total kW load is only a guide to the solar panel capacity. Any energy generated by the solar panel will reduce the energy you draw from the grid, which leads directly to less CO2 output at the power plants. But the power plant is still needed for when there is a cloudy day. When it's cloudy the solar panel output is drastically reduced, although they still produce power, as the salesmen are keen to emphasize, but what they don't tell you is that the power output is reduced by about 95%.

Also, in many countries, if your panels generate excess electricity you sell it back to the grid, so the capacity of the panels is not critical.

jaa kai book mai dekkoo

All VPHS students

The calculation of greatest fault current of system is required for calculation of the capacity of the switchgear or bus bar or cable. The source of the supply will be the consideration.The MVA/kVA capacity of the transformer or generator which is the source. The simple equation to find the short circuit current is 1.1 x V L I = --------------- Amps √ 3 x Z I - short circuit current Line voltage is multiplied by 1.1 to take care of 10% rise in voltage Z Impedance in ohms % Z x10 x kV 2 Z = --------------------- kVA Detailed calculation method is available in www. ecmweb.com You must read it if you are really interested to learn the subject. There are so much reading material on the subject in the net itself Similarly read this link http://books.google.co.in/books?id=yiT9Doq8TRwC&pg=PA184&lpg=PA184&dq=short+circuit+calculation+of+bus+bar+&source=web&ots=L1ww-bULxl&sig=Ker1LfRB8E9pWC5-fKnyNqPi_K0&hl=en#PPA184,M1

When Corona Discharge occurs it forms ozone and nitrogen oxides. These combined with moisture to prduce nitric acid, which is destructive to most dielectrics and certain metallic compositions, resulting in corrosion. In addition, the high energy in some discharges results in mechanical, electrical, and thermal damage. SC

I have included to related links. The 3 largest producers of petroleum are Saudi Arabia, Russia and the US. However, the US consumes its production. The countries with the largest reserves of oil are Saudi Arabia, Canada and Iran.