Why waveguides are used in radar?
A: Radar is an piece of equipment that require extreme hi frequency the wave are so small that wire does cannot control the emission so wave guides are used like rectangular pipes to guide the waves around with minimum losses. Radar even though is classified as electronics it boils down that physics are more necessary then understanding electronics
What are the future scope of fiber optics?
The future scope of fiber optics is promising with advancements in technology driving faster data transmission, increased bandwidth capacity, and improved connectivity. Fiber optics will continue to be essential in supporting high-speed internet, 5G networks, cloud computing, and other emerging technologies that rely on reliable and efficient data transmission. Additionally, fiber optics will play a crucial role in expanding broadband access to underserved areas and supporting the growth of smart cities and IoT applications.
Can impedence inversion be obtained by a short circuit stub?
No, impedance inversion cannot be achieved with a short circuit stub. A short circuit stub will have a low impedance at the point where it is connected, which will not invert the impedance at that point. Impedance inversion can be achieved using techniques such as a quarter-wave transformer or a transmission line with specific impedance characteristics.
If they were not evacuated of all outside air, the filament will burn up in seconds because the air Will cause Resistance, thus the filament will burn brighter and brigther tyring to burn off the air until it opens. (blown bulb)...
Can you perform a voltage drop test on AC as in DC?
Yes, you can perform a voltage drop test on AC circuits similar to DC circuits. However, you need to use specialized equipment designed for measuring voltage drop in AC circuits, which takes into account factors like impedance and phase difference. The principles of voltage drop testing remain the same, where you measure the difference in voltage between two points to identify any resistance or impedance in the circuit.
Do electrons flow from the positive to the negative terminal of a wet cell?
Electrons have a negative charge. For that reason, electrons will always flow in the opposite direction of the current, which flows from positive to negative.
Electrons will therefore move from a negative terminal to a positive terminal when we look at the load on a cell. Within the cell, the electrons will flow from the positive terminal to the negative terminal.
What unit do you get when you multiply coulombs by volts?
A charge equivalent to 1 V is equal to 1 J/C (that's Joules per Coulomb). There is no way, however, to do a straight conversion from volts to Coulombs as they measure slightly different properties.
Hope that helps! Happy Physics!
Maximum power is transferred from a source to a load when the load resistance is equal to?
A:is equal to the source
What is the difference between short to Battery and Open Load?
Related to a battery and open load is the battery just sitting there without anything connected. A short is a very low resistance attached to the tow terminals of the battery. For example, a wire connected across the battery terminals would constitute a short.
Why terminal voltage of a self excited shunt generator decreases with an increase of load?
The terminal voltage of a self-excited shunt generator decreases with an increase in load due to an increase in voltage drop across the internal resistance of the generator. As the load current increases, the drop across the internal resistance also increases, reducing the output voltage available at the terminals. This effect is known as voltage regulation and is a common characteristic of self-excited shunt generators.
Why do you experience a shock in an open circuit?
You don't experience a shock in an open circuit. The only time that you can get a shock from an open circuit is when you act as a switch and close the circuit or you ground the circuit hot side to ground with your body. Current has to flow to give you a shock.
Is Singapore's power grid AC or DC?
Singapore's power grid mainly operates on AC (alternating current) like most countries around the world. AC is preferred for long-distance power transmission as it can easily be converted to different voltage levels for distribution.
What is audible range of human being?
For humans it is from 20 Hz to 20000 Hz
Elephant - 16 Hz to 12,000 Hz
Cow - 16 Hz to 40,00 Hz
Cat - 100 Hz to 32000 Hz
Dog - 40 Hz to 46000 Hz
Rabbit - 1000 Hz to 1,00,000 Hz
Bat - 1000 Hz to 1,50,000 Hz
Dolphins - 70 Hz to 1,50,000 Hz
Seal - 900 Hz to 2,00,000 Hz
What is quantity represented by the base unit second?
The base unit second represents time in the International System of Units (SI). It is defined as the duration of 9,192,631,770 cycles of radiation corresponding to the transition between two energy levels of the cesium-133 atom.
When do charges move in an electrical system?
when a external force acts on the system then the bond between the atoms in the system are excited and pass to conduction band now the excited carriers runs along the system this called flow of current
Charges move in an electrical system when it is closed and a power source is connected to it.
What does ac-dc travel charger model CT-886004A go to?
The AC-DC travel charger model CT-886004A is designed to be compatible with a variety of electronic devices that require charging on-the-go, such as smartphones, tablets, or portable gaming devices. It typically comes with multiple connectors and adapters to fit different device models.
How does the graph vary between voltage and current?
If the graph is for Ohmic components e.g resistor or wires
-Constant gradient
-V is proportional to I
The second graph is for Non-Ohmic components
e.g Filament lamps/diodes
-(v is NOT proportional to I)
-Gradient is high at the origin (0,0) and low at the top due to an increase in resistance
Hope this helps!!
I couldn't put the pictures on, but just google a Filament lamp graph and they will come up :)
What will happen if you run a transformer at no load?
Yes, a plugged in transformer uses power with no load on it.
No transformer (or any electrical device, for that matter) is ideal, so there are always losses. There is parasitic capacitance, etc. that leads to power draw, particularly between the laminations. Plus, while the laminations are supposed to be insulated from each other, there is leakage current, and this causes power draw due to the tertiary transformer winding, that is partially shorted, which the laminations represent.
Another Answer
This simple answer is practically none.
The primary winding of a transformer draws a very small current (<5% of rated full-load primary current) when the secondary is open circuited (i.e. when the transformer is not supplying a load). Practically all of this 'no-load primary current' is responsible for the magnetic field set up within the core, and it lags the primary voltage by very nearly 90 electrical degrees, which means that the resulting power is practically entirely reactivepower (expressed in reactive volt amperes), and the amount of true power (expressed in watts) is negligible -for a small transformer, probably unmeasurable. For large power and/or distribution transformers, of course, the amount of true power involved is indeed measurable, and contributes to the overall losses in an utility system.
It's 'true power' (not 'reactive power') which determines the rate at which energy is consumed. I suspect what you are really asking is how much ENERGY (true power multiplied by time) a small unloaded transformer uses, then the answer is negligible to the point of being unmeasurable. So it is safe to say that you can leave your transformer plugged in continuously without adding a measurable amount to your electricity bill.
What happens when a relay is operated beyond its rated voltage or current?
Generally speaking, a relay is an electrically operated switch. As such, there are two sets of ratings associated with a relay. The operating voltage will be specified, and the ratings of the contacts are also set down.
As regards exceeding the operating voltage, this will cause excessive current to flow in the relay when it is energized. If the voltage is not significantly higher than the rating, and if the relay is not operated often or for long, it will function normally, but probably with a shorter life. At some point, excessive operating voltage will cause the coil in the relay to fail.
Operating a relay to energize an electrical circuit with a higher voltage or current than the relay is designed for will shorten the life of the contacts in the relay. Higher voltage and current will quickly burn the contacts and destroy them. This is particularly true if that voltage or current is significantly higher than the ratings set by those who designed and constructed the relay. Things might work for a short time, but not for long.
What component of a motor changes induced AC voltage into a pulsating DC?
its commutator..which converts ac produced by and motor to pulsating dc ...
more the commutator divide more accurate dc..means less pulse in dc
Does an Ohmeter that has an infinite reading indicates an open circuit?
Yes, an infinite reading on an Ohmmeter usually indicates an open circuit. This means that there is a break in the circuit, preventing the flow of current and resulting in the high resistance reading.
What is 2.561 K equals how many ohms?
To convert temperature to resistance, you will need to know the specific material's temperature coefficient of resistance. This coefficient determines how much a material's resistance changes per degree temperature change. Without this information, it is not possible to accurately convert temperature to resistance.
Is oxidized copper in liquid phase considered an electrolyte?
No, oxidized copper in liquid phase is not considered an electrolyte. An electrolyte is a substance that can conduct electricity when dissolved in a liquid. Oxidized copper, while it may contain ions, does not exhibit the same electrical conductivity properties as typical electrolytes.
What is maximum secondary coil voltage?
The maximum secondary coil voltage is determined by the turns ratio between the primary and secondary coils in a transformer and the input voltage applied to the primary coil. It can be calculated using the formula: V_secondary = V_primary * (N_secondary / N_primary), where V is voltage and N is the number of turns in each coil.
Placing a voltmeter into a circuit will raise the circuit resistance?
Usually a volt meter is placed across a component to measure the voltage drop across that component. Doing this places the volt meter resistance in parallel with that component's resistance, which will always lower the total resistance. Since the volt meter resistance is usually very large relative to the resistance of the element being measured, the total resistance does not change significantly.
The formula for total resistance of two parallel elements is: Rtot = (R1*R2)/(R1+R2),
as R1 (the volt meter) >> R2, Rtot ~= (R1*R2) / (R1) = R2
If a volt meter is placed into a circuit instead of around an element of that circuit, it will raise the resistance of the circuit, load the circuit with, and interrupt "normal" operation of the circuit (normal operation = how things would be without the meter in place). More importantly, the volt meter would then be measuring the voltage developped across itself (instead of an element of the circuit), which is not the point of this tool / this would be a misapplication of a volt meter.