Electronics Engineering

You need to calculate the equivalent resistance. For instance, if the three resistors are connected in series, simply add all the resistance values up. Then, you calculate the current (in amperes) using Ohm's Law (V=IR); that is, you need to divide the voltage by the resistance.

No it alternates the power from the circuit/circuits.

Bias is a permanent voltage, applied to the input of an amplifier device, in order to make it work in the correct area of an amplification curve. Valves (thermionic tubes) and semiconductors (transistors) both use bias in their grid or base connection. A negative swing in the input could put the control input below the working of the device and cause it to switch off. This is undesirable as it will show as distortion. The bias raises the zero point, so that the signal will not turn the device off.

The conducter molecules are expanded causing a loss of conductivity resulting in resistance. also the molecules are moving more making it difficult for the current to navigate rush hour traffic.

It depends on many factors.!! Mainly it depends upon the type of the conductor. i.e., How many valance electron is there in the conductor. As many as valance electrons as much current flows through the conductor. Length of the material should be less as much as possible and the Area (i.e., Cross section) should be increased. So the conductivity will obviously increased. By sticking in to the basics Resistance of the material should be very low. For an Ideal superconductor the resistance is ZERO as we all know. So more current flows through the conductor.

A: It just tell you the resistor has a +- % tolerance in its value. Like a 1000 ohms +-5% it can be off + or - that much.

That has being the standard for forever however that band is disappearing since most resistors are made +-5% as a rule.

A. ownership of the pipeline

B. emergency phone number

C. information about the pipeline contents

polarity is of major importance in dicect current circuits.

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When using meters please remember that a volt meter does not connect into a circuit, the leads are placed across the component that you are measuring. It is an amp meter that connects into the circuit, becoming part of the circuit, to measure the current flowing through that circuit.

Multimeters measure AC in two primary ways... The older style meter uses a diode, capacitor, and resistor to measure the peak voltage of the AC signal. They then compensate their calibration to read in a close approximation of what the RMS value will be. Problem is that this only works well for true sinusoidal waveforms - if the waveform is triangular, for instance, the indicated value will not match the RMS value. The newer style meter, if it states that it is a true RMS meter, will sample the input waveform and actually calculate the RMS value. This is done by adding up the squares of the input, and then taking the square root of the result. That is a much better approximation of how much power the waveform can deliver.

Applications of Voltage shunt feedback amplifier?

Without load there is no current so it is impossible to measure it.

The sinusoidal wave is harmonically pure, i.e. it only has one frequency in the frequency domain. If it were not harmonically pure, i.e. if it were not sinusoidal, it would be more difficult, if not impossible, to demodulate it at the receiver.

The 'm' in dBm means the power is referenced to 1mW. So, the power in dBm equals 10 times the log of the power in mW, or P(dBm) = 10*log(P(mW)/1mW). For example, 1W = 1000mW, so 10*log(1000/1) = 30dBm.

One relationship is that both can flow in vacuum.

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The most basic jet pump has a round pump chamber containing an impeller. The outlet to the well is large and the outlet to pressure tank is small. When the pump is primed and switched on it will suck water in and expel it at a higher rate. They are very susceptible to air leaks -every connection MUST be airtight.

A therm is used by gas companies to convert the volume of gas used to the equivalent of heat. It then calculates the actual energy used.

A: If there is resistance within the device it will cause to dissipate some of the energy as heat. The rest will continue

Work is usually measured in joules, which are a unit of energy. Work/time is called power and is usually measured in Watts (joules/second) other common units of power include Horsepower and ft*lbs /sec.

in short, is is power, which is measures in watts.

It is not 'Cutting voltage' but it is Cut-in voltage'. It is the voltage at which the diode turns ON. For silicon it is 0.7v. After reaching 0.7V diode current starts increasing rapidly for little increase in voltage.

That depends on actual circuit impedances and without knowing them cannot be answered in any way. But if all the circuit impedances are purely resistive, there will be no change in current flow with any change in frequency.

actually a diode is forward biased by at least 0,7 volts.so what it means is that when it is removed that 0,7 voltage drop on the diode is eliminated thus increasing ripple voltage

Resistance (Ohms) = Potential Difference (Volts) / Current (Amps)

So, 12/0.25 = 48 Ohms.