Electronics Engineering

kumar

impulse response is exponential increasing with respect to time.

Voltage can be calculated using Ohm's Law:

Voltage = Current (A) x Resistance (Ω)

Voltage = 4A x 3Ω = 12 Volts


Therefore, the battery is a 12 Volts.






The power dissipated is Voltage x Current



Power = 4A x 12V = 48 Watts

increased Back emf

Series circuit.

• Digital (numeric)
• Analog (voltage or current)
• Discrete (individual switch/relay closures)
• Analog (frequency or phase)
• Serial
• Analog (polyphase syncro or servo)
• etc. application specific classifications of input

"Rated current" is the current the device (motor or transformer?) is designed to handle at full load. "Tripping current" is the current where a protective device (fuse, breaker) will open to protect the device from overload/overheating. "Tripped current", may be the current the tripping device measured prior to making the decision to trip, if you are reading this from a digital protective device like a relay or OCR.

type of inverter

A transmission system is employed with pilot relaying schemes for protection. Pilot is a channel which transmits the information from one end of the transmission line to the other.The information is normally an electrical quantity that is measured at both the ends. The different pilots used are wire pilot, carrier-current pilot and microwave pilot.

Solkar system ( reyrolle) is a scheme employing the wire pilot. It is commonly called the balanced voltage or opposed voltage scheme. It operates on the principle of current differential protection.

Further details in Protection and Switch gears by Badri Ram and Viswakarma.

A tank circuit is typically a combination of 'capacitive' and 'inductive' circuits that exchange 'energy' back and forth. An inductor stores energy as a magnetic field, wheras a capacitor stores energy as a charge across plates. Ideally, the exchange between them would go on forever (back and forth like a game of hot potato) however, a slight replenishing signal is needed practically. By selecting the proper values of components, the rate, or frequency, of exchange can be determined.

Hideous intelegent dummie get it that's you

Okay. Resistance by ohms law is given by R = V/I

But Power P = V * I

Dividing R/P = 1/ I 2

Or R = P / I squared

For a constant power, resistance is inversely proportional to I squared and not simply proportional to.

Fibre optic cables are far superior than metal cables.

There are many reasons for the statement above. Fibre-optic cables are flexible and transparent 'tubes' or 'wires' that transmit information over longer distances and at higher bandwidths than metal cables can. Moreover, fibre-optic cables lose less information that the metal cables do when information is transmitted. Finally, fibre optic cables are immune to electromagnetic interference.

For the 2010 Winter Olympics in Vancouver, a lot of money was contributed in order for the fibre-optics connection to be established from Whistler to news and radio stations. In the end, the data transfer quality was superb and extremely reliable.

The power output can remain constant, but the forces acting against the projectile will affect its range. The mass of the projectile and the amount of charge can be considered constants unless range changes.

The elevation will then need to factor as a constant and the amount of charge will need to change accordingly.

It depends on what is easier to change.

First, the question doesn't say if the resistors are in series or parallel, or series-parallel. Second, the current given is zero, which can only be true if the circuit has no applied voltage. (It's turned off.) This will be true regardless of the circuit configuration. We were told the "middle resistor" in the question, but that's still a bit "iffy" for us. We need to know how it's wired. Since we don't, we'll look at the three possibilities. If all three resistors are in series, the total resistance is the sum of all the resistors. It's this: Rt = R1 + R2 + R3 ... or Rt = 3 + 3 + 3 = 9 ohms A shortcut can be applied when identical resistors are in series. The total resistance will be the value of one multiplied by the number of them in series. In this case, 3 x 3 = 9 ohms. If the resistors are all in series, the total resistance is this: Rt = 1 / ( {1 / R1} + {1 / R2} + {1 / R3} ...) or Rt = 1 / ( {1/3} + {1/3} + {1/3}) = 1 / (3/3) = 1 / 1 = 1 ohm We can shortcut that when we have identical resistors in parallel. The total resistance will be the value of one of them divided by the number that are in parallel. So we'd have: Rt = (3 / 3) = (1 / 1) = 1 ohm If two are in series with one across them in parallel, the total resistance is found for each individual parallel branch and then the parallel branches (which have been reduced to a single equivalent resistance) can be taken into the parallel resistors equation and the total equivalent resistance calculated. In this case, one branch has two series resistors of three ohms. The total for that branch is 6 ohms, which we find by just adding them up. Now we have a 6 ohm (equivalent) resistor in parallel with a 3 ohm resistor. Take them into the equation and calculate. It's like this: Rt = 1 / ({1/6 } + { 1/3 }) = 1 / ({ 1/6 } + { 2/6 }) = 1 / ( { 3/6 }) = 1/ (1/2) = 2 ohms

Antarctica holds very little capcity

In a series circuits, you simply add the the values of each resistor and that is you answer. i.e. - 200 + 86 + 91 + 180 + 150 = 707 ohms

current carriers

If the modulation index is greater than 1 (more than 100% modulation) the modulated carrier signal is periodically reduced to zero. This does not effect the transmitter but at the receiver these "dead carrier" intervals result in dropouts in the audio stream from the loudspeaker producing a distorted output that is difficult to understand.

E = U R U = E/R = 460/92 = 5 Amperes

yes

In electronics, various tools and equipment are essential for design, assembly, and testing. Common tools include multimeters for measuring voltage, current, and resistance; oscilloscopes for visualizing electrical signals; and soldering irons for joining components. Other important equipment includes function generators for producing waveforms, power supplies for providing voltage, and breadboards for prototyping circuits. Additionally, specialized tools like wire strippers, pliers, and screwdrivers are vital for handling components and assembling electronic devices.

Adding a DC source to a square wave signal will alter the base line of the wave without changing the peak-to-peak value.

For example, if a square wave has a +4V baseline and a +2VDC source is introduced, the resulting square wave will have a +6V baseline. This of course will also affect the high and low peaks of the signal. Assuming that our example has a high peak of +9V and a low peak of -1V (with a total of 10V peak-to-peak), the added +2VDC source would result in a high peak of +11V and a low peak of +1V; however, the total peak-to-peak value remains unchanged at 10V peak-to-peak.