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Mathematical Constants
Intriguing, ubiquitous, and at times mysterious, numerical constants set the allowable limits for all universal phenomena. Whether your questions involves π, Avogadro's number, Planck's constant, the atomic mass unit, or any of the other multitudes of immutable numbers used in science, this is the category where they should be asked.
2,332 Questions
Who worked with Transcendental numbers foundation for proof of pi?
According to Wikipedia, Legendre and Euler specualted that pi might be transcendental. This was finally proven by Ferdinand von Lindemann.
What characteristics does an abnormal impedance phlebography have?
If a clot is present, the pressure in the calf veins will already be high. It does not become sharply higher when the pressure cuff is tightened. When the pressure cuff is deflated, the clot blocks the flow of blood out of the calf vein.
What is the phone number of the Graham Public Library in Graham?
The phone number of the Graham Public Library is: 336-570-6730.
What is the value of gas constant-R when T298.15?
In atmospheres.
0.08206 L*atm/mol*K
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What is avogadro s number used to determine?
The number of basic particles - atoms of molecules - of a compound in one mole of the substance.
200 + 150 + 19 = 369
Who tried to get the first calculation of pi?
The ancient Babylonians from around 1700 BC used pi = 3.125. The name of the person who calculated that value was not recorded.
What is Phi and give its concept and how to work out algebraically?
Phi is the Golden ratio.
It is a way of dividing a rectangle such that the ratio of the two sides of the whole rectangle are the same as the ratio of the sides of the smaller rectangle.
Using measurement units such that the small rectangle is 1*f, therefore the larger one is f*(f+1). f is actually phi, but this browser is not so good for Greek letters.
Equality of the ratios imply that 1/f = f/(f+1)
Cross-multiplying, f2 = f + 1
therefore f2 - f - 1 = 0
Using the quadratic formula, f = [1 + sqrt(1 + 4)]/2 - the other root is negative and so not appropriate for a length.
Therefore phi = f = [1 + sqrt(5)]/2 = 1.61803 (approx).
A visual answer:
10,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000, 000,000,000,000,000,000,000,000,000,000,000,000,000
Answer:
Consider the simpler case that ten thousand is a one followed by 4 zeros. Four is no more divisible by 3 than 100 so your concern is the same. Ten thousand is 10,000 - obviously it exists, has four zeros, and obviously ten thousand is a real number. The grouping of zeros into packages of three after a number is a method of establishing the magnitude of the number more quickly. After a 1 three zeros is a thousand. six a million, nine a billion and so on. The one can be augmeneted with a zero to give us 10 (ten) or two zeros (100) to give us one hundred. So a googol can be described as either 1 followed by 100 zeros or 10 followed by 99 zeros. As counting out a hundred zeros is a pain and a source of confusion most scientific or math types would write it as 1x10100 or 10100 or 10 to the power 100 (all the same thing). Before you get worried about that zero count. 102 is a hundred (100) so the number of the exponent just indicates the number of zeros following the 1 in the written out format.
What is the result of the addition of two pure imaginary numbers?
An imaginary number.
Think of imaginary numbers as being on a vertical line while real numbers are on a horizontal line. (the lines cross at zero).
Adding and subtracting won't change the axis.
How do i compare and contrast adioh and inventory turns calculate the adioh of cost of goods?
adioh calculation
-2.07/225,000 divide both, numerator and denominator, by 9 = -.23/25,000
multiply both, numerator and denominator, by 4 = -.92/100,000
since the denominator is 10^5, move the decimal place in the numerator 5 places to the left - inserting 0s as required = -0.0000092
Your 94 Ford Explorer XLT V6 is running at 3000 revs when speed is at 65 mph is this normal or high?
DO NOT mess with your idle air control, whoever posted that last answer did not read your whole qestion, i have a 94 ford explorer 4x4, at 65 i run 2500 rpms, your torgue converter isn't going into lockup mode, most likey cause is a selnoid inside the transmission shorted out, or your computer,note that this will over heat your transmissoin when your driving freeway speeds, if your driving these speeds on a daily basis this will reduce the life of your transmissoin.
