Probability

evens says 4 * 6 = 24 rolls required for 4 shows

so 4 shows in 16 = 16 : 24 = 5 to 8 against

1,2,3,4,5,6 are the possible outcomes. There's a 1/6 chance for each.

A z-score is a means to compare rank from 2 different sets of data by converting the individual scores into a standard z-score. The formula to convert a value, X, to a z-score compute the following: find the difference of X and the mean of the date, then divide the result by the standard deviation of the data.

It's called a "Discard all" card.

- When played, you must discard all cards of the color of the discard all card

(E.g: If the top card on the discard pile is a blue 4, the player may play a blue discard all card and discard all their blue cards.)

100%

yes you can but you can not end with a 2,5 or 8 ..

By definition, the probability of an event is always some number between 0 and 1. Sometimes we think of these as percents. For example, if something has a probability of 25%, the probability is simply 25/100, or .25.

By this definition, nothing can have probability 3 or 1.2, or any negative number whatsoever. Only probabilities between 0 and 1 (inclusive) are allowed.

Each independent trial has a 1/2 probability that a heads will result. So for a sequence of 4 heads you have 1/2 x 1/2 x 1/2 x 1/2 = 1/16

It is an impossible event - which has probability zero.

1 - 2 answers

2 - probabilty of success remains constant

3 - outcomes of trials are independent

4 - random variable of interest is the number of successes in a fixed number of of trials

Yes.

Your question is actually meaningless without context. But allow me to propose one. Let us say that the question is, 3.5 billion is what percentage of the current total human population of nearly 7 billion people. The answer then is nearly 50%.

You are not a Jedi.

As the number of times that the experiment is conducted increases, the experimental probability will near the theoretical probability - unless there is a problem with the theoretical model.

Unless the vas deference has herniated also, the chances are almost zero.

26 of them.

Whether or not the "and" events are independent.

0.2884615

it is very possible to have two or more misscariages one after the other, i had a misscariage in June at 9 weeks pregnant and am now 7 weeks pregnant and the same thing is happening again, it is now November! hope that has helped good luck xx

You mean the PROBABILITY?

It's 13/52*13/51 = 13/204

Since the probability of having a son is about 1/2, the probability of the first 4 children being boys is about (1/2)4.

It is possible to have an event that causes more than one hazardous process to occur. An example is the landslide in Myanmar. Because of the heavy rains, a flood and landslide can both occur. Another example can be seen in the game Sim City. If there is an earthquake in the town, the earthquake can cause fires by the power lines.

For 71.5 and 67: σ=3.182