Probability

The first step is to establish a sampling frame. This is a list of all teachers in the domain that you are interested in.

Next you allocate a different number to each teacher.

Then you use a random number generator to generate random numbers. You select each teacher whose number is generated. If the teacher has already been selected for inclusion in the sample, you ignore the duplicate and continue until you have a sample of the required size.

What is the probability that any of the offspring between individuals with the genotype AABbCcddEE will have the genotype AABBCCddEE

First you have 3 blues out of 13 cards, so the first card has probability 3/13. Then you have 2 blues out of 12 cards, so the second card has probability 2/12 or 1/6. The probability of both being blue is the product of these probabilities:

P(two blues) = P(first blue) * P(second blue) = (3/13) * (1/6) = 3/78 or 1/26

Subjective

If you assume particular events will happen with a certain prior distribution, that is Bayesian probability.

Assuming a pack consists of 52 cards as per normal.

Initially half the cards are red.

Probability that the first card drawn is red = 1/2.

Now there are 25 red cards left out of 51 remaining cards.

Probability that the second card drawn is red = 25/51.

Probability that both cards drawn are red therfore = 1/2 * 25/51 = 25/102

About half the time.

There are no benefits in doing something that cannot be done. The standard normal distribution is not transformed to the standard distribution because the latter does not exist.

If you add 1 for the ace to 13 for Hearts cards you have 14 cards out of a 52 card pack. So the probability of selecting one of those 14 cards is 14/52 = 7/26

That is 0.2692307692307.........( recurring 69230)

Correcting to 4 significant figures that equals 0.2692 which equals 26.92%

That means that you will select a correct card in just over 1 in 4 times.

4

There is insufficient information for us to answer this question. Please edit the question to include more context or relevant information. It would be useful to know which lottery from which country the question refers to.

The only probable ion to form from Lithium is the Li+ ion.

The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.

The disputed election for President of US, between Albert Gore and George W Bush.

You cannot. It has a characteristic bell-shaped curve but so does a Student's t with enough degrees of freedom. There are other distributions which, with suitable choice of parameters can be made to look very similar to the Normal curve.

The queen on a standard modern deck of Anglo-American playing cards depicts no one in particular, and is most likely a distorted version of older versions of European cards.

Older sets of cards typically varied based on the origin of the card. Face cards typically depicted historical figures of religious or political importance.

Source: Wikipedia

Around 65-70%. I am a expert on the subject and have preformed many experiments where I have someone type random letters and see the outcome. Most of the time it is right somehow.

2 & 124, 4 & 122, 6 & 120, 8 & 118.... etc

In a standard deck of 52 cards - the probability of drawing any single card of two suits is 1:2 or 50%.

It is 1 (a certainty) if you roll it often enough. For a single roll of a fair die, the probability is 1/6.

3:8

Approximately, it is one half.

derivative classification

subjective

All the cards that are diamonds have an i in, so that's 13. Of the other suits, there are 3 fives, 3 sixes, 3 eights, 3 nines and 3 kings. So in total, there are 28 cards with an i in. The probability of getting a card with an i is therefore 28/52. This can be simplified to 7/13