Probability

What is the probability that this question makes absolutely no sense?

1/1.

or

100%

If two eggs are fertilsed you get fraternal twins whereas if one egg is fertilised and that develops into two individuals, you get identical twins.

If a random variable X has mean value m, and standard deviation s, then

Skewness = E{[(x - m)/s]3}

which can be simplified to

skewness = [E(X3) - 3ms2 - m3]/s3

and for discrete X, E(X3) = sum of x3*Prob(X = x) where the summation is over all possible values of x.

While for continuous X, E(X3) = integral of x3*f(x) where the integral is over the domain of X.

Provided the choice is totally random, because there are 52 cards in a standard pack, the chances of drawing a club is

13/52

(25%)

so, therefore the chances of not getting a club are 75% or 39/52

A thickened section on earthworms that contains male and female sex organs. After exchange of sperm takes place between two different worms, a mucus and chitin cocoon forms around the female pores and fertilized eggs are deposited.

November has 30 days, so 23 of them have 23 x 30 = 690 days.

1 in four chance.

multiples of 2: 2, 4, 6, 8. 10

number of spade with multiples of 2........... 5

number of heart with multiples of 2 ............5

number of diamond with multiples of 2........5

number of spade with multiples of 2 ...........5

===============================

total number of cards with multiple of 2.....20 cards

One could get a rolling chassis from somewhere such as Amazon or eBay. One could also purchase on from auto trader magazines and classified ads if they are advertised.

Listing all possible outcomes:
Dice 1 Dice 2 Sum
1 1 2
1 2 3
1 3 4
1 4 5
1 5 6
1 6 7
2 1 3
2 2 4
2 3 5
2 4 6
2 5 7
2 6 8
3 1 4
3 2 5
3 3 6
3 4 7
3 5 8
3 6 9
4 1 5
4 2 6
4 3 7
4 4 8
4 5 9
4 6 10
5 1 6
5 2 7
5 3 8
5 4 9
5 5 10
5 6 11
6 1 7
6 2 8
6 3 9
6 4 10
6 5 11
6 6 12

Only 3 out of the possible 36 combinations turned out to have a sum of 4. So that is 1/12

The faster mental way:
You know a standard dice has 6 sides.
In this problem, there are two die. So that means you have to multiply 6 x 6. That is 36.
So there are 36 possible outcomes.
You know 1 + 3 = 4, 3 + 1 = 4, and 2 + 2 = 4. Those are the only 3 equations that have all positive numbers that have a sum of 4 (Zero is not positive nor negative).
You have your answer. 3/36. In simplest form, it is 1/12.

When the deck is full, this probability is 4/52 (the probability of getting one of 4 aces) times 16/51 (the probability of getting one of 16 kings, queens, jacks, or tens) times 2 (the number of orders in which you could get these cards: ace first, or ace second). This comes out to 32/663, or about 4.83%. Of course, this probability changes as the game progresses: it decreases when any of the tens, jacks, queens, kings, or aces get discarded, but increases when other cards get discarded. This change is unpredictable, but its expected value is 0; this is a complicated concept to explain, but it means that on average, the probability will go up as much as it goes down. Also, the probability is still 32/663 at any point in the game if you have no information whatsoever about what cards came up before: if you forgot every card you saw, or if you just joined the game.

The political viewpoint of a newspaper can be learned by reading the editorial page.

They had altogether at first 176 marbles (Mar has 44 and Jay has 132).

It's a risk.

yea why not what would that have to do with it anybody can accomplish anything if they put there mind to it

There are no benefits in doing something that cannot be done. The standard normal distribution is not transformed to the standard distribution because the latter does not exist.

If you add 1 for the ace to 13 for Hearts cards you have 14 cards out of a 52 card pack. So the probability of selecting one of those 14 cards is 14/52 = 7/26

That is 0.2692307692307.........( recurring 69230)

Correcting to 4 significant figures that equals 0.2692 which equals 26.92%

That means that you will select a correct card in just over 1 in 4 times.

About half the time.

Assuming a pack consists of 52 cards as per normal.

Initially half the cards are red.

Probability that the first card drawn is red = 1/2.

Now there are 25 red cards left out of 51 remaining cards.

Probability that the second card drawn is red = 25/51.

Probability that both cards drawn are red therfore = 1/2 * 25/51 = 25/102

Subjective

If you assume particular events will happen with a certain prior distribution, that is Bayesian probability.

what ever sound you want it to be like blbsdfnigafjna that is a good example of the sound a rolling dice would make by dahc and nedyaj read these names backwards dice roller hahahahahahahah` dahc killed your dog/cat maybe your donkey

now can you answer my question is your dog dead

Bias and its ramifications

1/4

If we include both 1 and 50 there are 50 numbers to choose from. The numbers that are divisible by 7 in that range are 7, 14, 21, 28, 35, 42,and 49. There are 7 of them.

So the answer would be 7 out of 50, which is 14%.

We have no way of knowing the probability of any given person flipping

any given coin at any given time. But for any two flips of an honest coin,

the probability that both are tails is 25% . (1/4, or 3 to 1 against)