Probability

X=5 Y=1

X=4 Y=2

X=3 Y=3

and vice versa

I dont know. Im just answering your question. How did I get this answer?

You'll want to look up variance and standard deviation.

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1/2

There are 36 outcomes when rolling a die 2 times. They are:

1,1 2,1 3,1 4,1 5,1 6,1

1,2 2,2 3,2 4,2 5,2 6,2

1,3 2,3 3,3 4,3 5,3 6,3

1,4 2,4 3,4 4,4 5,4 6,4

1,5 2,5 3,5 4,5 5,5 6,5

1,6 2,6 3,6 4,6 5,6 6,6

The probability is zero. The largest possible sum on two dice is 12.

Infinitely many.For a start: t, tt, ttt, tttt, and so on until (?) you have infinitely many ts.

yes

Dominican republic

Without knowing how many drivers there are, this very much simplified chance cannot be calculated.

In real life each driver has a different chance of having an accident - the cost of motor insurance is dependant upon the risk (chance) that you are likely to (a) have an accident and (b) how severe that accident is likely to be; if everyone had the same chance, everyone would pay the same motor insurance premiums.

The formula depends on the experiment. For example, the answer will differ between a toss of a coin, a roll of a die, drawing a face card or not from an ordinary deck of cards.

There are 6!/2! = 360 ways.

Just one. After that you no longer have a card deck.

0

Use a direct proof;

Suppose Tom minimises the largest difference between two numbers. For this to be true, Tom must pick consecutive numbers. If Tom picks 10 consecutive numbers the maximum difference must be 9. Given that tom picks one more number, there must be two numbers who differ by 10 for all selections.

If you have tossed a fair, balanced coin 100 times and it has landed on HEADS

100 consecutive times, the probability of tossing HEADS on the next toss is 50%.

one chance in two - 50%

Z-score

variances

1 out of 6 chances

1/6 or 16.66..%

S

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