Statistics

1/4? ...

Broadcast.

I think of it this way. Take it as two unique 6-sided dice, then you have 36 possible outcomes (6 times 6). Two of these outcomes will add to equal 3 (2 & 1, and 1 & 2), so there are 34 [36-2] outcomes which don't sum to 3. The probability is 34/36 or about 94.44 percent chance.

If you're asking what the probability you don't roll AT LEAST three is, the only roll on two normal dice less than three is two, and there's only one way to roll it: 1,1. So the probability of not getting AT LEAST three on two fair dice is 1/36.

List the numbers from least to greatest. Count in from both ends the same times and you will note there is no middle number, but 2 middle numbers. Take the average of the 2 middle numbers and that is the mean of the set.

4 possible kings out of 52 cards.

1/13

There are 500 of them ... too many to list here.

one

The factors of 780 are: 1, 2, 3, 4, 5, 6, 10, 12, 13, 15, 20, 26, 30, 39, 52, 60, 65, 78, 130, 156, 195, 260, 390, 780

slovin did

Wish I knew, that is where we got them also and have been looking for a new source since. Please let me know if you find someone.

3/13=0.23 or 23%

or

12/52=0.23 or 23%

Venus is the second planet from the sun.

yes

The common prime factors are 2 and 3

6.042 %

The correct ratio is not 1.414 but sqrt(2), which is an irrational number.

To round a number to the nearest tenth, you first need to consider all numbers at place value tenths and higher. In this case, that's 20.3. Then you look at the next digit along. If it's 5, 6, 7, 8 or 9 you round up, otherwise you leave the number as it is. In this case, the next numbers a 7 so we need to round up. This gives 20.379 to the nearest tenth as 20.4

1/4

It is the value of integers, rather than their position.

For example, the first three cardinal numbers are: ONE, TWO and THREE.

Their ordinal counterparts are: FIRST, SECOND and THIRD.

to find the mode, you have to look for the # that shows up the most times....for example.....some #s could be 90,81,100,100,86,and 12...the mode would be 100.

9876543210

I'll answer your question literally before guessing at what you really meant.

The probability of rolling a 10 is not influenced by what was done before, assuming perfect dice, of course. So the fact they were rolled 50 times before makes no difference, the probability remains 1 in 12.

But maybe you meant, "What is the theoretical possibility of rolling a 10 at least once in 50 throws?"

To figure that out, you work out the opposite and then take 1 minus that.

You ask yourself, "What is the probability of NOT rolling 10 in 50 throws?"

Now that's easy. The odds for any one throw is 33/36 (there are 3 ways to throw 10: 4&6, 5&5, 6&4). So the odds of no 10 in 2 throws is (33/36)x(33/36) and for 50 throws, it is (33/36) to the 50th power.

That is an extremely small number, so the opposite (chance of at least one roll or 10) is almost a sure thing (1 - (33/36)50).

873 is.

Mathematicians delve into the most complex and difficult logic and math problems. They also help the financial, biotech, energy and engineering industries and governement agencies beside education jobs where they occupy chairs as professors.

In academy, a B.A. or B.S. in Mathematics cannot pursue professions outright since he still needs some kind of specialization which is mastered after an extended period of post-graduation studies.