Volume

The short answer is 28.9 grams or 1.02 ounces.

But it depends on the temperature and pressure of the air, the helium, and possibly also what's holding the helium.

The upward force on the helium is called the buoyancy. The weight it can "pick up" is the buoyancy less the weight of the helium itself.

At sea level pressure, air has a density of 1.2 g/L at an 'normal' pressure.

Helium is of course less dense, at 0.1786 g/L.

1 (cubic foot) = 28.3168466 L

So the net buoyancy is (1.2 g/L - 0.1786 g/L) * 28.32 L = 28.9 g.

The helium's container matters because some containers are compressible. Eg a rubber balloon will expand as it rises or shrink as it falls. This can affect the buoyancy.

0.833 cups is equivalent to 5/6 cups. To convert decimal fractions to common fractions, you can multiply the decimal by a power of 10 to make it a whole number. In this case, 0.833 multiplied by 100 gives 83.3, which simplifies to 5/6 when divided by 10.

To convert cups to fluid ounces, you can use the fact that 1 cup equals 8 fluid ounces. Therefore:

To convert cups to fluid ounces, we use the conversion factor: 1 cup = 8 fluid ounces.

So, for 3.4 cups: 3.4cups×8fluid ounces/cup=27.2fluid ounces

3.4cups×8fluid ounces/cup=27.2fluid ounces

Therefore, 3.4 cups is equal to 27.2 fluid ounces.

To elaborate further: Milliliters (ml) and microliters (µl) are both units of volume commonly used in scientific measurements. The relationship between them is straightforward, as 1 milliliter (ml) equals 1,000 microliters (µl). This means that every milliliter contains 1,000 smaller microliter units.

Conversion Process:

To convert any value in milliliters to microliters, you simply multiply by 1,000 because: [ 1 , \text{ml} = 1,000 , \text{µl} ] For example, to convert 0.46 ml into microliters: [ 0.46 , \text{ml} \times 1,000 = 460 , \text{µl} ]

Explanation:

• Milliliters are a common metric unit used for measuring larger volumes of liquids.
• Microliters are a much smaller unit, used when precision in tiny amounts of liquid is required, such as in laboratory settings.

By multiplying the milliliter value by 1,000, you're breaking the volume down into microliter units. So, 0.46 ml becomes 460 microliters, which is a smaller but more precise expression of the same volume.

Well, honey, if we're talking about South African 1 rand coins, which have a diameter of about 20 mm, you could fit approximately 375 coins into a 2-liter Coke bottle. But who's got time to count all those coins? Just toss 'em in and see how many you can squeeze in there!

Well, honey, 0.5 liters is the same as 500 mL, so yes, it's more than 300 mL. It's like asking if a kitten is smaller than a tiger - one's a cute little thing, and the other could eat you for breakfast.

To compare 32 quarts to 9 gallons, we need to convert both measurements to the same unit. Since 1 gallon is equal to 4 quarts, 9 gallons is equal to 9 x 4 = 36 quarts. Therefore, 32 quarts is smaller than 36 quarts, so 32 quarts is not bigger than 9 gallons.

10 US gallons is about 37.854 liters.

50cc = 50mL 10.1 tsp 3.38 tbs 1.69 oz 0.211 cups

Oh, dude, you're hitting me with the conversions now? Alright, so 106 cubic inches is about 1732.8 cc's. But like, who really measures things in cubic inches these days anyway? Just Google it next time, man.

1 cup

The density of sand varies depending on what minerals the grains of sand are made of, and wet sand is denser than dry sand. As a rough rule of thumb, a litre of dry sand weighs about 1500 grams.

Well, darling, 9 liters is equivalent to 9000 milliliters, so 8997 milliliters is technically less than 9 liters. But hey, who's counting those extra 3 milliliters anyway? Just grab yourself a drink and call it a day!

To determine if 2.7 liters is more than 27 decaliters, we need to convert the units to the same measurement. Since 1 decaliter is equal to 10 liters, 27 decaliters is equal to 270 liters. Therefore, 2.7 liters is less than 27 decaliters.

1.7 ounces is approximately 1/2 of 3.4 fluid ounces.

Oh, what a happy little question! To find out how many 250ml are in 18L, we need to convert the liters to milliliters. Since 1L is equal to 1000ml, 18L is equal to 18,000ml. Then we just divide 18,000ml by 250ml to find there are 72 of those little 250ml containers in 18L. Isn't that just delightful?

1 gallon = 4 quarts

1 quart = 0.25 gallon

There are approximately 5.07 8 oz glasses in 4000 mL.

To convert gallons to liters, you can use the conversion factor that 1 gallon is approximately equal to 3.78541 liters. Therefore, for a barrel of oil containing 42.0 gallons, the equivalent volume in liters would be 42.0 gallons * 3.78541 liters/gallon ≈ 158.99 liters. If 1 liter is equal to 1.06 quarts, then you can also convert the volume from liters to quarts by multiplying 158.99 liters * 1.06 qt/L ≈ 168.52 quarts.

Without some indication of density for comparison, it is impossible to convert millilitres to kilograms.

To calculate the amount of nitrogen gas required to raise the pressure in a pipe, we need to follow these steps:

1.	Calculate the volume of the pipe in cubic feet.

2.	Apply the Ideal Gas Law to determine how much nitrogen is needed to achieve the desired pressure.

Step 1: Calculate the Volume of the Pipe

The formula for the volume of a cylinder (which is the shape of the pipe) is:

V = \pi \times r^2 \times h

where:

•	 r  is the radius of the pipe (half the diameter),

•	 h  is the length of the pipe.

Given:

•	Diameter of the pipe,  d = 8  inches,

•	Length of the pipe,  h = 400  feet.

First, convert the diameter to feet:

d = \frac{8 \text{ inches}}{12 \text{ inches per foot}} = 0.6667 \text{ feet}

The radius r is half of that:

r = \frac{0.6667}{2} = 0.3333 \text{ feet}

Now, calculate the volume:

V = \pi \times (0.3333)^2 \times 400 \approx 139.3 \text{ cubic feet}

Step 2: Apply the Ideal Gas Law

The Ideal Gas Law in terms of volume and pressure is:

PV = nRT

Where:

•	 P  is the pressure,

•	 V  is the volume,

•	 n  is the amount of gas (in moles),

•	 R  is the ideal gas constant,

•	 T  is the temperature.

To find the additional volume of nitrogen required to increase the pressure to 20 psi, we’ll compare the initial and final states of the gas assuming temperature and the amount of gas are constant.

Using the relationship between pressure and volume at constant temperature and gas amount:

\frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2}

Since temperature T and n (number of moles) are constant, we can simplify it to:

P_1 \times V_1 = P_2 \times V_2

Assuming the initial pressure P_1 is 0 psi (no pressure), the entire volume of the pipe must be filled with nitrogen at the final pressure of 20 psi. Hence, the amount of nitrogen required is equal to the pipe’s volume at that pressure.

Thus, 139.3 cubic feet of nitrogen gas is required to raise the pressure in the pipe to 20 psi, assuming no initial pressure.

The volume of a 5,000-foot long pipe with a 6-inch diameter is: 981.75 cubic feet.