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9.982 is the answer because you take the given mole and multiply it by the mass of N. So it would be 0.713 mol x 14.00 = 9.982 g
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How many Molecules are contained in 0.900 mol O2?
5.418E23 molecules
How many atoms are there in 0.850 mol of ammonia?
There are 6.02 x 1023 NH3 molecules in 1 mole of NH3.Therefore 0.850mol of ammonia would have 0.85 x 6.02 x 1023 molecules of NH3.In each NH3 molecule there are 4 atoms (one N and three H atoms).Therefore the number of atoms in 0.850mol of NH3 is4 x 0.85 x 6.02 x 1023 = 2.05 x 1024
How many moles of nitrogen are required to produce 18 mol of ammonia?
18 mol of NH3 (ammonia) contains 18 mol of N atoms. 1 mole of N2 (nitrogen gas) contains 2 mol N atoms. so 9 mol N2 is used to produce 18 mol NH3.
How many molecules of ammonia are contained in 10 moles of ammonia NH3?
1 mol of any substance contains 6.02 x 1023 constituent particles. This is the avogadro constant. So in 10 moles of NH3, there would be 10 x 6.02 x 1023 = 6.02 x 1024 NH3 molecules.
How many molecules are there in 1.00 mol of H2O2?
There are 6.022 x 10^23 molecules in 1.00 mol of H2O2. This number is also known as Avogadro's number.
How many molecules are in 0.0650 mol NH3?
There are 3.92 x 10^22 molecules of NH3 in 0.0650 moles because one mole of NH3 contains Avogadro's number of molecules, which is 6.022 x 10^23.
How many molecules are in 75g of N2O3?
To find the number of molecules in 75g of N2O3, you first need to calculate the number of moles using the molecular weight of N2O3 (76.01 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many Molecules are contained in 0.900 mol O2?
5.418E23 molecules
Number of N atoms in 0.410 mol NH3?
I actually have this problem in my chemistry book too. This is what is given in the "Solutions to Red Exercises" book that went along with the text: Analyze. Given: mol NH3, Find: N atoms Plan. mol NH3---> mol N atoms---> N atoms Solve. 0.410 mol NH3 * 1 mol N atoms/ 1 mol NH3 * 6.022*10^23 atoms/1mol = 2.47*10^23 N atoms Check. (0.4)(6*10^23)=2.4*10^23. I hope this helps.
How many grams of NH3 can be produced from 2.08 grams of N2?
To determine the grams of NH3 produced from 2.08 grams of N2, you need to set up a balanced chemical equation for the reaction. Assuming the balanced equation is N2 + 3H2 -> 2NH3, you would calculate the moles of N2, then use stoichiometry to find the moles of NH3 produced. Finally, convert moles of NH3 to grams using the molar mass of NH3.
How many moles of NH3 are produced when 1.2 mol of H2 reacts?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
How many atoms are there in 0.850 mol of ammonia?
There are 6.02 x 1023 NH3 molecules in 1 mole of NH3.Therefore 0.850mol of ammonia would have 0.85 x 6.02 x 1023 molecules of NH3.In each NH3 molecule there are 4 atoms (one N and three H atoms).Therefore the number of atoms in 0.850mol of NH3 is4 x 0.85 x 6.02 x 1023 = 2.05 x 1024
N2 plus 3H2 -- 2NH3 If you produce 55.5 grams of ammonia how many grams of nitrogen will you need?
To determine the grams of nitrogen needed, calculate the molar mass of ammonia (NH3) which is 17 grams/mole. Then, use the mole ratio from the balanced equation (1 mol N2:2 mol NH3) to find the mass of nitrogen required which is 16.5 grams.
HOW many grams pf ammonia are in 387x1021 molecules?
Assuming that this ammonia gas is at STP, you can use Avogadro's number to gind the number of moles of gas:(387 x 1021 molecules) x (1 mol / 6.02x1023particles) x (17.03 g / 1 mol) =110 g NH3
What is the molecular mass of NH3 when The atomic mass of N is 1401 gmole and the atomic mass of H is 1008 gmole?
Molecular mass = sum of all atoms masses = 1(molN/mol NH3)*14.01(g/mol N) + 3(molH/mol NH3)*1.008(g/mol H) = 17.03 g/mol NH3
How many grams of NH3 are needed to provide the same number of molecules as in 0.55 grams of SF6?
molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
How many moles of nitrogen are required to produce 18 mol of ammonia?
18 mol of NH3 (ammonia) contains 18 mol of N atoms. 1 mole of N2 (nitrogen gas) contains 2 mol N atoms. so 9 mol N2 is used to produce 18 mol NH3.
