Statistics

6m/1.4s = 4.29M/S

sachin is the most popular player

popular among 1 billion and more

ghazi

It's not a known word In English. Did you mishear "apprenticeship"?

Yes.

Sara get's a different life. Her name becomes Lucy Smith and she is a fn of horses.

5

It allows you to visualize and compare trends of data over intervals of time.

toes or fingers are also called digits.

7

There are 10 decimetres in one metre. Therefore, 54 decimetres is equal to 54/10 = 5.4 metres.

it mean's me

a square

182= 324

square root 18= 4.242640687...

1 and 9 are square numbers that are factors of 18.

Every time you count things, you recite a list of integers.

They can, so the question is irrelevant.

One variable must react to the other. If represented by a graph, a visible trend will appear and a "trend line" should easily be visualized and determined.

(1/2)3 = 1/8.

Perpendicular.?

Here's one way to do it:

#include <stdio.h>

int main(int argc, char *argv[]){

int n;

for( n = 1; n < 100; n++){

if(n % 10 == 1) printf("%i ", n);

}

return 0;

}

And here's a more efficient way to do it:

#include <stdio.h>

int main(int argc, char *argv[]){

int n;

for( n = 1; n < 100; n += 10){

printf("%i ", n);

}

return 0;

}

The product of 36 (= 9 X 4) by any integer will be integrally divisible by both 4 and 9. The smallest integer by which 36 can be multiplied to yield a product with five digits is 278, for which the product is 10,008. The largest integer by which 36 can be multiplied to yield a product with no more than five digits is 2777, for which the product is 99,972. Therefore, the product of 36 multiplied by any integer from 278 to 2777, inclusive, satisfies the requirements stated in the problem. 36,000 and 46,656 are examples.

Assuming you can't repeat the numbers, there are:

56*55*54*53*52 = 458,377,920 permutations.

If order doesn't matter (as in a lottery ticket), there are:

(56*55*54*53*52)/(5*4*3*2*1) = 3,819,816 combinations.

No. The range is the maximum value less the minimum value. If all the values are different, the maximum must be different from the minimum. Consequently, the max minus min must be greater than zero.

The total marbles are 60, your mathematical expectation of getting a single blue marble in one try is therefore 17/60. If you grab 7 random marbles, the mathematical expectation is 7 times 17/60. This is the expectation, in an actual experiment you will get more or less than that, but it should be fairly close to the calculated value. (Note that the mathematical expectation in this case isn't even an integer.)

7,9,10,11,13 Assume the data list from smallest to largest is A,B,C,D,E. Then from the info given C=10 since 10 is the median. Also the range of the data is 6, so that means that E-A = 6. Since the mean of the data is 10 then (A+B+C+D+E)/5 = 10 or A+B+C+D+E = 50 You can substitute the value for C and E = 6+A (since the range is 6) to get A+B+10+D+(6+A) = 50 or simplified: 2A + B + D =34 Now since the median of the data is 10 the value of B will be less than 10 and A will be less than B. The value of D will be greater than 10 and E will be greater than D. To figure out the data list use trial and error. Start by picking a value of D > 10. Start with 11. From the equation above you have 2A + B + 11 = 34, now pick a value of B < 10. Start with 9 and substitute to solve for A. 2A + 9 + 11 = 34 or 2A = 14 and A=7 So A=7, B=9, C=10, D=11 and E=6+A or 13. To check see if these numbers equal the mean of 50. (7+9+10+11+13)/5 and it does. If it didn't work then you'd have to go back and pick values of B, D again until it does. Hope that helps.

Yes, it can.