C Programming

#include<stdio.h>

main()

{ char ch;

clrscr();

gotoxy(5,3); printf("*Identification of Consonant and Vowel letter*");

gotoxy(5,5); printf("*Please input a letter from A-Z in order to determine");

gotoxy(5,6); printf("if it is a CONSONANT or a VOWEL*");

gotoxy(5,8); printf("Enter a Letter: "); scanf("%c",&ch);

gotoxy(5,10); printf("Letter %c is a ",ch);

switch(ch)

{ case 'A':

case 'a':

case 'E':

case 'e':

case 'I':

case 'i':

case 'O':

case 'o':

case 'U':

case 'u': printf("VOWEL."); break;

default: gotoxy(5,10); printf("Letter %c is a CONSONANT.",ch); }

gotoxy(5,15); printf("Thanks you for trying this!"); getch();

}

long float myfun();

1.take while loop in which u continue up to null in array of string.

2.once u get null pointer then take a new array of same length.

3.when u get null there ll save position no in variable i.

4.take while loop i to 0;

5.and j=0 for new array.

6.in above loop copy old array to new array in each cycle of loop.

7.j++;

8.u ll get reverse of string.

u(t)-u(-t)=sgn(t)

write the javascript code to display the reverse no. of given no. (e.g. 247 reverse of 742)

Dynamic memory allocation

Compilers ensured that there was no conflict between the Hadith and the teachings of the

Qur'an, i.e. both the Qur'an and Hadith were in conformity and taught the same lessons. It

could be added that they compared the body (matn) of the Hadith with reason, the Qur'an

and other Hadiths to ensure that they agreed with the primary Islamic teaching. Answers

could be further elaborated to state that they ensured the chain of transmitters (isnad) was

unbroken and that the transmitter was a person of sound mind, good memory and upright

character. Examples of collectors going about their work could be given to answer

You can put as many conditional tests as you want in the while loop conditional location.

As a rule, however, it is a better idea to simplify the conditions as much as possible so that the reader of the code has a better understanding of what is being accomplished.

Once you start putting multiple conditions in a while loop with ANDs and ORs together, the logic can get complex and not well understood.

int main (void)

or

int main(int a, char **p)

a condtional statement may be true or false but only in one direction

a biconditional statement is true in both directions

%hd

ANSWER A hash table is a way to find data in an array, when you have a known key and an unknown value that corresponds to the key. You use a hashing function on the key to create an index into the hash table containing the value. In the ideal case, this directly returns the corresponding value. In the usual case, a collision can occur. This means that the hashed key points to multiple possible values. A hash table is usually used on large arrays that would take a long time to search using other methods. A hash table can be very fast and use very little memory, and does not require the array to be sorted. The source code is slightly more complicated than some search methods. With a poorly designed hashing function when the hashed keys do not correspond one-to-one with the values, the secondary search after a hash collision can take a large amount of time.

yes at the moment he is.

It is very easy.

The program begins here.....

/*Program to sum and print numbers without creating variables*/

#include<stdio.h>

main()

{

clrscr();

printf("%d+%d=%d",5,2,5+2);

getch();

}

/*Program ends here*/

Now just by changing the numbers in the "printf" statement we can add, subtract, multiply and divide the numbers without using variables.

Hence the problem is solved..........

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,c;

clrscr();

printf("Enter any three numbers");

scanf("%d%d%d",&a,&b,&c);

if(a>b&&a>c)

printf("A is greatest");

else if(b>a&&a>c)

printf("B is greatest");

else if(c>a&&c>b)

printf("C is greatest");

if(a<b&&a<c)

printf("A is smallest");

else if(b<a&&b<c)

printf("B is smallest");

else if(c<a&&c<b)

printf("C is smallest");

getch();

}

integer data type

Short for traceroute: it is a utility program to check IP-routing.

When you start it, e.g: tracert www.ibm.com

No commands in C; the name of function sqrt is sqrt (include math.h; and use -lm at linkage)

You use OLE Object fields to insert documents (Word, PDF, bitmap images, etc) into records. The OLE Object itself is actually a binary data field and the only way to compare any two OLE Objects is to compare the binary data itself. This makes no sense because we normally compare documents by type, size, author, title, creation date, last modified date, and so on, we don't compare their physical representations (the binary data itself). If we want to sort documents, we must extract the properties we wish to sort by and insert them as separate fields in our records, and use those fields as our index/sort keys.

Sometimes we really do need to use binary data as a sort key, but we cannot use an OLE Object to store that data because OLE Objects cannot be used as sort keys. Instead, we must use the built-in binary data field which can be indexed and sorted. Binary data fields can be fixed-length (binary) or variable length (varbinary). Note that OLE Objects are variable length with a theoretical limit of 1 GB, which is yet another reason why they are unsuitable for indexing. The fixed-length binary field has an upper limit of 510 bytes, making it ideal for indexing and sorting small amounts of binary data.

Unfortunately, the built-in binary data fields cannot be created using the table designer for no practical reason other than Microsoft decreed that you couldn't. Instead you must use DDL or VBA/DAO. Using DDL, the following will create a binary and a varbinary field. For completeness, I've also included an OLE Object field:

CREATE TABLE tblBinTestSQL (

Id counter NOT NULL PRIMARY KEY,

VarbinaryColumn varbinary(100) NULL,

BinaryColumn binary(100) NULL,

OLEColumn Longbinary NULL

);

Here's the VBA/DAO method of achieving the same thing:

Public Sub CreateBinaryColumns()

Dim td As DAO.TableDef

Dim db As DAO.Database

Dim fd As Field

Set db = CurrentDb

Set td = db.CreateTableDef("tblBinTestDAO")

Set fd = td.CreateField("ID", DataTypeEnum.dbLong)

fd.Attributes = fd.Attributes Or dbAutoIncrField

td.Fields.Append fd

Set fd = td.CreateField("BinaryColumn", DataTypeEnum.dbBinary, 100)

fd.Attributes = fd.Attributes Or dbFixedField

td.Fields.Append fd

Set fd = td.CreateField("VarbinaryColumn", DataTypeEnum.dbBinary, 100)

td.Fields.Append fd

Set fd = td.CreateField("OLEColumn", DataTypeEnum.dbLongBinary)

td.Fields.Append fd

db.TableDefs.Append td

End Sub

Once you have at least one table with a binary or varbinary field, you can simply copy that field to other tables. You can also modify the properties of those fields in table designer; you just can't use table designer to create those fields.

Any base that is itself a power of 2 is easily converted to and from binary. With base 4, each digit represents 2 bits. With base 8 (octal), each digit represents 3 bits. And with base 16 (hexadecimal), each digit represents 4 bits. Thus two hexadecimal digits represent an 8-bit binary value. This is convenient because we typically refer to a unit of computer memory as an 8-bit byte, thus every byte value can be represented using just 2 hex digits. If we had a system with a 9-bit byte we'd use 3 octal digits instead. A 24-bit value can either be represented using 6 hex digits or 8 octal digits.

To convert a hexadecimal value to binary, we simply consult the following table (note that 0x is the conventional prefix for a hexadecimal value):

hex = binary

0x0 = 0000

0x1 = 0001

0x2 = 0010

0x3 = 0011

0x4 = 0100

0x5 = 0101

0x6 = 0110

0x7 = 0111

0x8 = 1000

0x9 = 1001

0xA = 1010

0xB = 1011

0xC = 1100

0xD = 1101

0xE = 1110

0xF = 1111

Here, hexadecimal digit 0xF has the binary value 1111, thus 0xFF would be 11111111. Note that the bit patterns are in the same order as the hexadecimal digits. Thus 0x0F becomes 00001111 and 0xF0 becomes 11110000.

Knowing this, we can easily convert binary values into hexadecimal, we simply divide the binary value into groups of 4 bits and convert each group to the corresponding hex digit. Thus 101101001100 becomes B4C (1011=B, 0100=4 and 1100=C). If there aren't enough bits, we simply pad the first group with leading zeroes.

We can use a similar technique to convert between octal and binary, we simply divide the bits into groups of 3:

octal = binary

00 = 000

01 = 001

02 = 010

03 = 011

04 = 100

05 = 101

06 = 110

07 = 111

Note that a leading 0 is the conventional prefix for octal values. Thus binary value 100010 would be written 042 in octal to avoid confusion with 42 decimal.

A flow void in the brain refers to an area on an MRI scan where blood flow is absent or significantly reduced, typically seen in blood vessels. This phenomenon is often characterized by a dark appearance on T2-weighted images, indicating the presence of high-velocity blood flow or the absence of blood in certain regions. Flow voids are commonly associated with normal vascular structures, such as arteries and veins, but can also indicate pathological conditions, such as vascular occlusions or malformations. Identifying flow voids is crucial for diagnosing various neurological conditions.

Program to print one & zero Alternatively

#include
#include
void main()
{
int i,j,n,k=1;
clrscr();
printf("Enter the Iteration Value : ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
{
printf("%d",k);
if(k==1)
k=0;
else
k=1;
}
printf("\t");
}
getch();
}

Output :
Enter the Iteration Value : 5
1 01 010 1010 10101