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Electrical Engineering

Electrical engineering is a field of engineering that deals with the study and application of electricity, electronics and electromagnetism.

23,056 Questions

How does a pylon work?

A pylon holds up the wires carrying electricity. If there were no pylons the wires would drag onto the floor and if you were to tread on them you would get electrocuted by the wires.

What is pulse transformer?

Pulse Transformer Operating Principles

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8 Operating Principles

Magnetizing (No-Load) Current

Voltage Droop

Voltage-Time Product

Kickback Voltage

Secondary Load Current

Effects of Winding Capacitance & more

The Trailing Edge

Pulse DistortionThe magnetic flux in a typical A.C. transformer core alternates between positive and negative values. The magnetic flux in the typical pulse transformer does not. The typical pulse transformer operates in an "unipolar" mode ( flux density may meet but does not cross zero.)

A fixed D.C. current could be used to create a biasing

D.C. magnetic field in the transformer core, thereby forcing the field to cross over the zero line. Pulse transformers usually (not always) operate at high frequency necessitating use of low loss cores (usually ferrites). Figure 1A shows the electrical schematic for a pulse transformer. Figure 1B shows an equivalent high frequency circuit representation for a transformer which is applicable to pulse transformers. The circuit treats parasitic elements, leakage inductances and winding capacitance, as lumped circuit elements, but they are actually distributed elements. Pulse transformers can be divided into two major types, power and signal.

An example of a power pulse transformer application would be precise control of a heating element from a fixed D.C. voltage source. The voltage may be stepped up or down as needed by the pulse transformer's turns ratio. The power to the pulse transformer is turned on and off using a switch (or switching device) at an operating frequency and a pulse duration that delivers the required amount of power. Consequently, the temperature is also controlled. The transformer provides electrical isolation between the input and output. The transformers used in forward converter power supplies are essentially power type pulse transformers. There exists high-power pulse transformer designs that have exceeded 500 kilowatts of power capacity.

The design of "signal" type of pulse transformer focuses on the delivery of a signal at the output. The transformer delivers a "pulse-like" signal or a series of pulses. The turns ratio of the pulse transformer can be used to adjust signal amplitude and provide impedance matching between the source and load. Pulse transformers are often used in the transmittal of digital data and in the gate drive circuitry of transistors, F.E.T.s, S.C.R.s, and etc. In the latter application, the pulse transformers may be referred to as "gate transformers" or "gate drive transformers". Signal type of pulse transformers handle relatively low levels of power. For digital data transmission, transformers are designed to minimized signal distortion. The transformers might be operated with a D.C. bias current. Many signal type pulse transformers are also categorized as wideband transformers. Signal type pulse transformers are frequently used in communication systems and digital networks.

Pulse transformer designers usually seek to minimize voltage droop, rise time, and pulse distortion. Droop is the decline of the output pulse voltage over the duration of one pulse. It is cause by the magnetizing current increasing during the time duration of the pulse. To understand how voltage droop and pulse distortion occurs, one needs to understand the magnetizing ( exciting, or no-load ) current effects, load current effects, and the effects of leakage inductance and winding capacitance. The designer also needs to avoid core saturation and therefore needs to understand the voltage-time product.

Pulse Transformer - Magnetizing ( No-Load ) Current, its Effects, and Its Relation to Saturation

Consider the simple pulse transformer circuit of Figure 2A and its equivalent circuit of Figure 2B.

There is no source impedance, winding capacitances, or secondary leakage inductance to worry about. With both switches open, there cannot be any primary or secondary currents flowing. Now close the primary switch. Since the secondary load is not connected, the pulse transformer's primary winding acts like an inductor placed across a voltage source. Primary current begins to flow. This is the magnetizing current ( no secondary current ) and is governed by the differential equation V(t) = L x d(I)/dt + Rp x I(t), with units of volts, henries, amps, and seconds. If the power supply has constant voltage, Rp = zero, & L = Lkp+Lm is constant, the differential equation can be solved for I(t), I(t) = Io + V x t / ( Lkp+Lm ), where Io = the initial current which equals zero. Notice that the current increases at a linear rate over time and that the rate in inversely proportional to the inductance. The current flows through Np turns creating Np x I(t) amount of magnetizing force ( amp-turns ) which in turns creates a magnetic flux density in the pulse transformer core. Eventually the increasing primary magnetizing current would exceed the magnetic flux capacity of the pulse transformer core and will saturate the core. Once saturation occurs the primary current rapidly increases towards infinity ( in theory ). In a real circuit the primary winding resistance ( and source impedance ) would limit the current. See Figure 3A below for graphical illustration. For non-zero Rp, I(t) = Io + ( V/Rp ) x ( 1 - e to the ( -Rp x t / ( Lkp + Lm )) power ). The effect of Rp is graphically illustrated in Figures 3B and 3C. Rp extends the time it takes for the unloaded transformer ( or an inductor ) to saturate. If Rp is sufficiently large, it prevents the transformer ( or inductor ) from saturating altogether. Regardless of saturation, Rp places an upper limit on the primary current value.

Pulse Transformer - Voltage Droop

For Rp = 0 the source voltage divides proportional across Lkp and Lm hence the voltage across Lm = V x Lm / ( Lm+Lkp ) = Vm. The induced secondary voltage becomes equal to Ns x Vm / Np. For Rp > zero a voltage drop occurs across Rp. The value of this drop increases in value as the primary current increases with time, hence Vm decrease over time and consequently the secondary voltage declines over time. Thus Rp and magnetizing current contribute to secondary voltage droop. Lkp does not contribute to the droop in the "no-load" case but does contribute to a lower secondary starting voltage for both the "no load" and "under load" cases. Droop is graphically illustrated in Figure 4B. Compare it against the ideal pulse shown in Figure 4A. When a droop is present in the waveform, we do not get the consistent pulse wave amplitude as on the left.

Pulse Transformer - Voltage-time product

Pulse transformers, being typically unipolar (D.C.) applications, require the primary switch to be opened ( thereby removing the voltage source ) before saturation occurs, whereas A.C. applications reversed the applied voltage before saturation occurs. Unipolar applications require that sufficient time be allowed to pass to re-set the core before starting the next pulse. This time permits the magnetic field to collapse ( reset ). The field does not completely collapse to zero value ( unless forced to zero, or lower ) because of core material remanence. A slight air gap may be used to bring remanence closer to zero value. The gap lowers the pulse transformer inductance. The flux range between remanence and the maximum flux is referred to as dB, the maximum change in flux density during the pulse duration, dt. The dB of the typical pulse transformer is less than half for that of an A.C. application because flux in A.C. applications can go from positive Bmax to negative Bmax. Operating frequency and maximum expected temperature affect the choice of maximum usable flux density value, Bmax. Saturation can be avoided by applying the following equation; dB x Np x Ac x Sf = V x dt x 100000000, where dt is the maximum time duration of the pulse, Ac is the core's cross-sectional area and Sf is the core stacking factor ratio. Units are gausses, turns, square centimeters, volts and seconds. Be aware that dt does not include reset time, tr. Maximum operating frequency equals 1 / ( dt + tr ). The voltage-time product, V x dt is quite useful. The size and cost of a pulse transformer is roughly proportional to this product.

Pulse Transformer - Kickback Voltage

In the foregoing discussion the primary switch was opened thereby interrupting the current flowing through the transformer primary. The resulting collapse in the magnetic field will induce a voltage reversal in the transformer windings. The more rapid the field collapse is, the higher the induced voltage. The transformer will try to dissipate the energy stored in its collapsing magnetic field. If the transformer was under load, the induced voltage would cause current to flow into the load. In the "no-load" case of this example, the transformer does not have any readily available place to dissipate the energy. The transformer will generate the voltage necessary to dissipate the stored energy, hence a high voltage "kickback" ( or flyback or backswing ) voltage will occur in the windings. In a real circuit the transformer will induce eddy currents in its core thereby dissipating the energy as core loss. In a real circuit the high voltages can damage the switching elements ( transistors, F.E.T.s, S.C.R.s, etc. ). Many designs include protective circuitry across the primary winding.

Pulse Transformer - Secondary Load Current Effects & Rise Time

Consider again the simple pulse transformer circuit of Figure 2A and its equivalent circuit of Figure 2B. Initally, with both switches open, there cannot be any primary or secondary currents flowing. Close the secondary load switch and then close the primary switch. Current flows through the primary winding. The L x dI(t)/dt action induces a voltage in the primary winding which opposes the source voltage. A voltage, Vsi, is also induced in the secondary winding causing secondary current to flow. The ampere-turns created by the secondary current work against the induced voltage that opposes the source voltage. Consequently, the source voltage supplies more current flow through the primary. Currents rapidly increase until either the secondary current or primary current encounters a current limitation. Examples of such limits are the secondary load and winding resistances limiting the secondary current or the source impedance and primary winding resistance and primary leakage inductance limiting the primary current. Once a limit is encountered, an equilibrium is quickly established except for the magnetizing current. The primary current has two components; Irs, the load current transformed ( reflected ) to the primary winding and Im, the magnetizing current. As in the "no-load" case, the magnetizing current starts at zero and increases over time. The pulse transformer must be "switched off" before saturation occurs.

In this example the load is resistive, there is no secondary leakage inductance, and there is no secondary winding capacitance; hence a purely resistive load current is reflected to the primary winding. The primary current is larger than it was in the "no-load" case, hence more voltage drop is expected across the primary winding resistance. Consequently less voltage, Vm, is available across Lm which results in less induced voltage in the secondary winding. Secondary current flow through the secondary winding resistance causes another voltage drop hence lower transformer output voltage. Under load, both the primary and secondary winding resistance contribute to a lower secondary voltage. The secondary winding resistance does not contribute to pulse droop.

The reflected load current, Irs, does not flow thorughthe mutual inductance, Lm, but doe flow through the primary leakage inductance, Lkp. Lkp restricts the flow of the primary current ( hence reflected load current also ). Consequently the reflected load current cannot immediately reach its full value ( nor can the secondary current ). It is effectively delayed. Until the reflected load current reaches its full value, a larger voltage drop will occur across Lkp then there was in the "no-load" case. This larger voltage diminishes in value over time. Consequently Vm exhibits a time delay in reaching peak voltage value. This delay is also seen in the secondary output voltage. This delay is known as rise time. Rise time is graphically illustrated in Figure 4B.

Pulse Transformer - Effects of Winding Capacitance, Secondary Leakage Inductance, & Core loss

Now consider the equivalent pulse transformer circuit of Figure 5.

The circuit has all the components of the circuit in Figure 2B, but also has primary winding capacitance, secondary winding capacitance, core loss, and secondary leakage inductance. Start with both switches open and no capacitive energy and no inductive energy. All currents are initially zero. Close the secondary switch then close the primary switch. The primary leakage inductance, Lkp, restricts the flow of primary current by opposing the source voltage. The opposing voltage is generated by Lkp x d(I)/dt action. Current flow ( from the source ) finds the uncharged winding capacitance, Cp to be a much easier path, hence a relatively large amount of current flows into the winding capacitance. This large amount of current could be called a surge current because it will diminish over time as the capacitance is charged. The surge causes a relatively large voltage drop across the primary winding resistance, Rp, thereby initially lowering the voltage available to Lkp and Lm. Over time, as the surge current diminishes, the voltage drop across Rp diminishes, and the voltage across Lkp and Lm reaches full ( peak ) value. The surge effectively delays the peak voltage across Lm. This in turn delays peak secondary voltage. The delay contributes to rise time, hence Cp contributes to rise time. As discussed earlier, Lpk restricts flow of the reflected load current and consequently also contributes to rise time.A similar consequence occurs with the secondary winding capacitance, Cs. Any current supplied by induced secondary voltage must charge Cs as the secondary voltage tries to rise to peak value. This delays the secondary in reaching peak voltage, hence Cs also contributes to rise time.

Secondary leakage inductance, Lks, restricts secondary current flow just like Lkp restricted primary current flow. Lks also delays the secondary peak output voltage, hence it also contributes to rise time.

Core loss resistance, Rc, provides a relatively small current shunt path across Lm just like the reflected secondary load current does. It has the same effect but the effect is much smaller.

To summarize, Winding capacitances and leakage inductances act to increase rise time. ( They also generate trailing edges which is discussed later. ) They may also contribute to spurious oscillations. In a typical pulse transformer design, core loss does not have much effect.

Pulse Transformer - The Trailing Edge

For an ideal pulse transformer, once the primary switch is opened the secondary pulse should immediately end. This does not happen. The pulse transformer tries to dissipate the energy stored in Lm and in the parasitic components Cp, Cs, Lkp, and Lks. The inductance will induce voltages as their magnetic fields collapse. The capacitor charge will drain, but will not drain instantaneously. The capacitances may temporarily supply current to the inductances. As a result, there is a sloped decline of the secondary output voltage after the primary switch is opened. This sloped decline is referred to as the "trailing edge". Some combinations of capactiance and inductance could produce spurious oscillations ( known as ringing ). A trailing edge is graphically illustrated in Figure 3B.

Pulse Transformer - Pulse Distortion

Ideally the output pulse waveform should be identical in shape to the input pulse waveform except for a desired amplitude change due to the "step-up" or "step-down" turns ratio. Any other deviation is considered to be distortion. Rise time, droop, trailing edges, and spurious oscillations are all considered to be signal distortions.

Figure 3B illustrates all of these distortions.

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What is the household AC electrical power service in the US?

In short: 240/120 V @ 60 Hz frequency.

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In the US, lighting and low-power appliances run at 120 volts plus or minus 10%; meaning 108 volts to 132 volts at 60 cycles per second called hertz (Hz). To get the actual figures for your locality it is best to ask a local licensed electrician or your local electricity supply company.

However, US houses get 240 volts at 60 Hz at the panel. If all the wall outlets were fed with that 240 volts you'd have the lower current and higher power advantage of the European 50 Hz system and it would be safer too, since each "hot" would still be only 120 volts from ground, which reduces the shock hazard compared to some European 230 volt receptacles or socket outlets.

However the most important difference is how the Neutral wire is connected:

240 volt 50 Hz service

Please note: there is no 50 Hz service in countries which use a 60 Hz, such as the US and Canada. The following information is given just for comparison purposes.

A 240 volt 50 Hz appliance can have up to 3 wires altogether:

  • one single 240 volt "live" or "hot" wire;
  • a neutral wire;
  • a safety "earth" or "ground" wire but this is not required if the appliance is of the type known as "double insulated".

The hot wire feeds alternating voltage from the power station to the load and, because the voltage is alternating, the load draws an alternating current. Then the neutral wire returns the current to the power station to complete the circuit.

240 volts 60 Hz service

An appliance that is designed to be connected to strictly 240 volts 60 Hz is connected with only a two-wire cable plus a safety ground wire. (For example 240 volt 60 Hz base board heaters use that.)

The only time a cable with three wires plus safety ground is used is if 120/240 volts is needed in the equipment. (For example kitchen ranges or washing machines which have time clocks or programmers that require only a 120 volt feed.)

Thus an appliance designed to run on a 240/120 volt 60 Hz supply can have up to 4 wires altogether:

  • two 120 volt 60 Hz live "hot legs" which run in opposing phase to one another: when one hot leg goes "+" (120 volts positive) the other leg goes "-" (120 volts negative);
  • a neutral wired as a "central" common current return conductor:
  • a safety "ground" wire but this is not required if the appliance is of the type known as "double insulated".

One of the two hot wires feeds a 120 volt alternating voltage from the power station to the 120 volt load - the clock or programmer - and, because the voltage is alternating, that load draws an alternating current. Then the neutral wire returns the current to the power station to complete the circuit.

Important conclusion

There is a 240 volt voltage difference between the neutral and the hot conductor in the 50 Hz system and only a 120 volt voltage difference between the neutral and each of the hot conductors in the 60 Hz system.

That is why an appliance designed to be connected onto the 50 Hz system cannot be used safely on the 60 Hz system without first having a proper technical inspection done, followed by any necessary modification work done to ensure that the appliance can be operated safely because, in the main breaker box, at the point where the 60 Hz "neutral" gets connected to the ground, this difference will cause serious problems!

A licensed electrician or electrical engineer would be able to consider whether or not a particular large appliance, that was manufactured to work on 50 Hz-only, could be modified to run safely at the higher 60 Hz frequency. However it won't usually be worth the expense of doing the work because it would be more cost-effective to buy (new or secondhand) an equivalent large appliance designed to work on 60 Hz.

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In the U.S. it's 120 volts AC running at a frequency of 60 Hz. It was increased from 110 volts in the 1950s.

The historic reason for 110 volts is the Direct Current (DC) power systems created by Thomas Edison. It is believed he chose 110 volts because that is what his light bulb worked on. Later, these systems were converted to Alternating Current (AC), so you didn't need a power plant on every street corner, but the voltage level wasn't changed, so existing lighting didn't need to be replaced. (At that time they didn't care if they got AC or DC.)

An interesting question is why the rest of the world did not wind up using 110 volts. How did 220/230/240V get started over there?

The US system theoretically could be made as good as the European system (slightly better than, actually) with no infrastructure change except to houses themselves. US houses get 240 volts at the panel through the Black and the Red hots. If wall outlets were all fed with 240V you'd have the lower current and higher power advantage of the European system and it would be safer too, since each "hot" would still be only 120V from ground (not 240V) which keeps the reduced shock hazard advantage. If the wiring has been done correctly it should be impossible for someone to touch both Black hot and Red hot at the the same time by accident.

It was Thomas Edison who promoted the use of (then) 100 volts as some tragic experiences in the early days of power distribution showed that 100 volts was not usually lethal for a shock. Remember that in the early days, single un-insulated wires were strung though ceramic insulators, both exterior and interior, and so there were many more shock hazards present. Each splice was made by wrapping one wire around the other one and soldered. The use of junction boxes was non existent. As technology advanced good, long life, insulation was wrapped around the conductors.

Scroll down to related links and look at "Household AC electrical power in different countries around the world - voltages, frequencies and plug types - Worldmap for AC Voltage and Frequency - Wikipedia".

What is component selection of auto transformer starter?

An Auto transformer motor starter is a device intended to start AC asynchronous motors, instead of connecting the electric motor directly to the electrical grid, it will connect it to the grid in more than just one step.

Hence, it will behave as an electro mechanical soft starter.

Although it is the "older" method of starting motors, it is still widely used due to its simplicity.

The list of parts needed to "make" an "Auto Transformer Motor Starter" is composed from:

1. Auto transformer itself

2. 3 contactor (electrically sized to fit the motor)

3. Two timers, defining when the contactors will "close".

Prime movers for power generating operation?

A "prime mover" is part of a generator - specificially the thing that's causing the generator to spin (such as a turbine). It is called the prime mover because it is what is causing the generator's rotation.

What is the difference in a 5spl hp and a 5 hp electric motor?

"5SPL" horsepower means "5 special use" horsepower, the real world meaning of which is "not really 5" horsepower, you usually see these motors on air compressors sold for home or very light industrial use. They will make close to 5 horsepower intermittently for a brief time right before the compressor kicks off . A good "5" horsepower motor will make 5 horsepower for as long as you have electricity for it.

Physically the difference is 25 to 30lbs. Monetarily, the difference is about $100 to $150.

If you walk into a sears or Kmart store you will see portable appliances known as Vacuum cleaners. the ones for rugs are rated in Amps.

the ones for yards or shops are rated in HP

If we talk of the shop Vac model that says 6.5HP

it has a #18 120V cord on it.

the blade configuration indicates 15A

if the motor is 90% efficient and the blower (turbine) 100% efficient this will require about 45A thru said #18 cord

it has another figure that says 210 MPH which MAY be for the speed of the air in the 2" outlet this would require 0.2 HP

if its for using the attachments using the 1" hose this would indicate 0.05HP.

Faber College (John Belushi) may have originated this

it is special double secret HP so it reads 6.5HP rather than 6.5 Spl HP

What is the use of mylar capacitor?

myler film /myler capacitor is specially designed for low inductance and low resistance,so it has an prpoperty of fast discharging energy

Capacitor as a storage devices or components?

A capacitor is a device that stores electrical energy in an electric field. It is a passive electronic component with two terminals.

We're JYH HSU(JEC) Electronics Ltd (or Dongguan Zhixu Electronic Co., Ltd.), an electronic components manufacturer. You may google search "JYH HSU" to find our official website.

What is the purpose of the flux shifter in a low voltage circuit breaker?

A trip rod on the circuit breaker is spring loaded and held by a permanent magnet in the "armed" position; the flux shifter, when energized due to an overcurrent event, creates a magnetic field opposite the permanent magnet field....this neutralizes the magnetic field, releasing the trip rod.

How many constraints should be taken in optimal placement of capacitor problem for voltage improvement using Particle swarm optimization?

Four constraints should be taken in optimal placement of capacitor problem for voltage improvement using the Particle Swarm Optimization.

How is an ammeter connected in a circuit in order to read the current flowing in the circuit?

In series with the circuit and never in parallel. The reason being that it will cause the circuit total resistance to drop which will make the circuit draw excessive current. That's a short circuit actually.

What is the setting in air circuit breaker?

"The setting" is not clear. There can be lots of stuff in a breaker control cabinet that could be deemed to have a "setting".

How do you calculate current load for 24 V DC?

There are three formulas to calculate current. They are I = E/R, I = W/E and I = the sq. root of W/R. As you can see there is one value missing in your question so it can not be answered.

What size of an inverter generator would you need to run a MacBook Pro?

Look on the AC power adapter and read its rating in watts. You will need an inverter with at least that output capacity.

How do you determine reactive power in three phase?

Total 3-phase real power = sqrt(3) x VLL x ILL x cos (theta) = 3 x Vp x Ip x cos (theta)

Total 3-phase reactive power = sqrt(3) x VLL x ILL x sin (theta) = 3 x Vp x Ip x sin (theta)

where: ?LL denotes line-to-line and ?p denotes phase-to-ground quantities

Therefore, S = sqrt( P2+Q2) =

= sqrt[32 x Vp2 x Ip2 x cos2 (theta) + 32 x Vp2 x Ip2 x sin2 (theta)]

= sqrt[32 x Vp2 x Ip2 x {cos2 (theta) + sin2 (theta)}]

= sqrt[32 x Vp2 x Ip2 x {1}]

= 3 x Vp x Ip (works for the line-to-line case, as well)

Hope this helps,

Chris

Why tunnel diode are used in negative resistance region?

because that the tunnel diode is a standard pn junction diode in many respect

except its highly doped pn junction so it has some characteristics in the negative resistance region another that its a standard diode

Why does electric current flow into circuits?

It may not be correct to say that an electric current will "flow into" circuits. Electrons move in a circuit in response to an applied voltage. And these electrons are alread in the circuit and available to support current flow if a voltage is applied.

It may be more correct to say that electrons leave the negative terminal of a voltage source, and electrons enter the positive terminal of that voltage source. The electrons in the circuit that are availble to support current flow will "shift over" to create the current flow. Remember that the phenomenon of current flow in a wire is the "shifting over" of electrons in the wire. It's not about electrons going into one end of a wire and those same electrons coming out the other end.

Use the link to the related question for more information that might help make things clearer.

How are motors and a generator different?

Motors convert electrical energy into mechanical energy and generator converts mechanical energy into electrical energy