Electrical Engineering

you can either check that there is a smell

if there is a liquid bottle in your air freshner than see if there is any liquid left

25 kV.A for a permanent load; more if the load is variable.

With six wires, 3 connections on u1 v1 w1

And 3 connections on U2 v2 w2

The motor connections are linked out at the controller via contractors

It depends what you mean by an '11-kV transformer'; do you mean a primary transformer (33/11-kV transformer) or a distribution transformer (11-kV/400-230-V transformer). Differential protection IS offered on primary transformers.

For all intents and purposed the VA rating is the same as the wattage rating of appliances. VA is an electrical classification for Volt Amps. The formula for watts is, Watts = Amps x Volts.

The winding function of an electric motor is a description of how the number of conductors in the windings around the motor changes with position.

Inventions are normally protected by applying for a patent.

What effect will be there on the motor (Induction) output power when a 100kW 50hz motor is connected to a 60hz power supply.

S = 1/R

Where S = Conductance in Siemens

R = Resistance in Ohms

If R is in Mega Ohms, S will be in Micro Siemens

(110V outlets and 120V outlets are practically the same for this discussion. I will refer to them as 120V. Same with 220V/240V outlets.) For your 120V source I assume you plan to use a standard US 120V 15A outlet. This outlet can provide a maximum of 15A at 120V. This means the outlet can provide 1,800W of power. ( Volts x Amps = Watts ) This is the maximum amount of power this outlet can provide, no more. Also, this is assuming nothing else is drawing power off the circuit this outlet is on. If you try to pull 1800W from an outlet and plug anything else into this circuit, the breaker will blow. Your oven is designed to run off a 50A 240V circuit. Let's say, for argument, it draws 40A at 240V. This means your appliance requires 9,600W of power to run correctly. This is over 5.3 times the absolute maximum amount of power your 120V outlet can provide. There is no way you can run this appliance off this outlet. You have a larger problem here than the voltage difference. Probably not advisable. One of the way transformers are rated is by the maximum wattage the transformer can safely accommodate. Electric ranges (or any appliance used to heat or cool) consume much more energy and require a much higher wattage rating than most other appliances. Unless you know the wattage rating of your transformer and are certain it can safely provide for your electric range, you should NOT use a step-up transformer with your range. Bear in mind that the wattage requirement for any electric range may vary greatly from model to model and varies even more with the demand placed on the range. For example, wattage required by one burner set to 'low' is much less than the same burner set on 'high'. Even more current and wattage is required to run 2 burners, 3 burners, etc... As you can see, there are many variables. The safest situation would assume that the range will always operate at it's maximum capacity (i.e. All burners on and set to high, cooling fans set to their highest level, any light bulbs on, both upper and lower oven heating elements turned on if applicable, any other accessories turned on and operating at their highest setting) and therefore should have a transformer at least 20% higher in capacity than the range at maximum consumption. The maximum wattage rating of the range should be printed on the manufacturers label, the Underwriters Laboratories(UL) label, or in the product installation/owner's manual. If wattage is not specifically given then use this formula to calculate wattage: Watts= Volts x Amps. I think a good question to ask yourself before doing this is, "Am I cool with my entire house burning down?" If your answer is, "No." then you probably need to pay an electrician to run a proper 220/240v line. A modern oven/range combination can easily consume 12,000-15,000 watts. As a comparison, a large hair dryer can consume as much as 2,000 watts. A 15,000 watt step-up transformer easily costs over a thousand bucks. So, unless you happen to have one lying around it's probably cheaper to hire the electrician anyway. One last tip: If the transformer doesn't weigh over 100 pounds, don't even think about it. Transformers are heavy. The bigger, the heavier. Here's a good website: http://www.voltageconverters.com/commercial_transformers.html

I think they decided that it was just more user friendly and more fool proof than numbers. (747's hydraulic systems are numbered)

The color coding of the hydraulic lines is a European practise. The Boeing designs and most US designed a/c have their hdraulic systems numbered. The color code is really just a way to Identify the separate systems in the documentation and the cockpit procedure as well as physically on the hydraulic tubing.

You are not moving!

You don't.

Basically, service loads are those applied loads which have not yet been factored. Also known as "working loads"

There is a thousand milliamps in an amp. So it would be 5.4AH.

A large amount of energy, calculated as the voltage difference across the wire, will be expended in that section of wire. This would most likely cause it to glow and/or create a lot of heat, which could possibly melt the wire and break the circuit (this is the principle any fuse is based on - a fuse is a low resistance wire that has a low melting temperature, so a "large" current will cause the fuse to heat excessively, melting the conductor).

A light bulb is exactly this - a "high resistance" wire (or filament), where relatively large current is pushed through a very small cross section of wire, causing it to glow.

If you look at the reflection coefficient curve as a function of frequency, it follows a counter-clockwise direction about the Smith chart. You should see a loop, and at the "top" of the loop, that is the oscillation frequency.

They both have in common an open-loop gain greater than one, however. So the curve will be outside the Smith chart.

An ammeter measured how many amperes of current are flowing in an electrical circuit.

1.73 is the square root of the whole number 3, (rounded off to two decimals), and is used in virtually all 3 phase calculations.

The centre of the (secondary of the) centre tapped transformer is zero volts because that is the point in the circuit on which you based your measurement. If you were to connect the reference meter lead to the end of the winding, then the centre tap would have voltage on it. Its all a matter of perspective, i.e. reference.

It also happens that the centre tap is usually grounded and, since you usually connect the meter's reference lead to ground, if you connect the meter's reading lead to the same point, you would logically expect there to be a zero volts differential. Its the same as connecting the two leads together.

In the model manipulation section (dark red) click on "load" then choose the model you want to include. Done with MikuMikuDanceE v726.

Ohm's Law has nothing whatsoever to do with power. Power is measured in watts.

Good question because a huge amount of energy comes out of the condenser. Unfortunately the heat is at a relatively low temperature so it can't really be used for very much except space heating.

There is not much demand for space heating round a power plant. Obviously the energy is used to keep the workers warm in the buildings of the power plant but that uses only a tiny fraction of the available energy.

Some factories use a system where they have their own power plant to generate the electrical power they need, and the waste heat is piped round the factory to keep the workers warm. This is a very efficient use of the fuel and is called CHP - combined heat and power.

When the present glut of fossil fuels expires there will be more incentive to develop ways of using energy more efficiently.