Electrical Engineering

The practical exercise does not have an exact answer. The idea is that the student will do something in real life to put the theories he or she has learned into practice. To that end, all answers will be different.

typically the ratio is on the current transformer

it will say something like 100:5 witch means 5a meter becomes 100A full scale

the 5 instead of a 1 gives you a hint about the capacity of the transformer

its 20:1 so you could use it to make a 1A meter into a 20A

but making a 10A meter into a 200A may lead to problems (accuracy or power)

Conductance is reciprocal of resistance. Hence, G=1/R. Calculate now

Infinity.

Yes. A shorted condenser will load the electrical supply and prevent the starter from creating the mechanical force necessary to turn over a motor.

the impedence should be complex conjugate of an equivalent impedence of the network when viewed from the terminals of the load.

i.e; Z=R-jx

burn or burst

An alternator's terminal voltage shouldn't drop 'sharply' when subjected to a lagging power-factor load. After all, most practical loads are inductive and it wouldn't do for an alternator's terminal voltage to drop 'sharply' for what is a normal load.

Nevertheless, in common with most voltage sources, there will be a moderate drop in its terminal voltage due to the internal voltage drop caused by the load current passing through the impedance of the armature windings.

Perhaps surprisingly, however, there may be an increase in terminal voltage when supplying a leading power factor, the reason for which can be demonstrated using simple phasor analysis of the alternator's induced e.m.f. and internal voltage drop -this cannot be shown here, but there are lots of websites which demonstrate this.

The reason is that internal voids within the insulation will discharge as the voltage rises; once discharged, they will not do so again at some higher voltage. if all voids become discharged, theoretically the plot of tan delta versus voltage would level off to a horizontal line. In effect, tip-up becomes "negative".

By multiply current supply and voltage

if that 144 is the peak voltage

if its a sine wave the rms voltage is that voltage divided by sqrt(2)

if not a sine wave (modified) you must find the area under the curve

by integrating a cycle of that wave shape (root mean squared)

Generators generate and transformers step up or step down the voltage

1 & 3

There are losses in d.c. transmission lines, due to their resistance. But there are no reactive losses. So, d.c. transmission lines have less losses in comparison to an equivalent a.c. transmission line.

ewan ko...................... ikaw ba alam mo

A 'centre tap' refers to a connection midway along the length of a transformer winding. In North America, the 240-V secondary winding of a distribution transformer is centre tapped, and grounded, thus providing the neutral. Each outer terminal of that winding is then at a potential of 120 V with respect to the centre tap. This enables US and Canadian residences to have both 240 V and 120 V supplies. 240 V is then used for high power appliances, such as ranges (cookers), while 120 V is used to supply lower-power appliances, such as kettles, toaster, etc.

RMG

m1123

The poorest insulator would be the best conductor, which is one of the noble metals.

Bakelite is a fairly good insulator, not too long ago electrical fittings were made from it.

4160/120 = 34.666666 to 1

What is current carrying capacity of 50x8 mm copper flatbusbar.

Cost per unit of electricity depends the type of generation used. ie:- thermal hydel, nuclear etc. hydel electricity is cheaper and now a days it cost less than Rs.10 per unit in India. whereas thermal electricity cost less than Rs. 20 per unit

street lights are connected in parallel mostly because if any lamp stops glowing but the other lamps continue their glow

An ADC has a measurable input voltage range that it can produce valid samples for. For example, an ADC may be able to produce 16 bit samples on the range [-.5V,+.5V]. A 16 bit range will give codes from [-32,768,32,767], which are equal to the [-.5V,+.5V] input range. If an input goes outside of the valid voltage range (but still within allowable electrical ratings), the ADC will 'saturate', in which it will continue to feed out the maximum or minimum 16 bit values. This will continue until the input comes back into the measurable range.