Electronics Engineering

Series circuits , the voltage is drawn by instruments progressively from source to end whereas parallel circuits give a constant voltage through all the points connected parallel to the source hence the name.In series circuit,the more the power drawn by an instrument,the lesser the voltage available for the next instrument connected after it serially from the source. Hope this solves the question

No. The amperage isn't high enough for you to be harmed by it.

No, across the tongue it can't kill you. If someone opened up your chest and put the battery across your heart then you might be in trouble...

Possible. If you have a heart condition, pace maker, etc. then there could be problems any electrical voltage no matter how minor. Also, if the battery touches a nerve close to the surface of your tongue, it can cause other issues.

On top of that, not all batteries are made to specs, just ask Sony. With manufactures farming out to other vendors, they loose track of quality control. A battery that is not to spec will provide the jolt to seriously injure someone.

Because the meter is actually measuring the current through the resistor, and

the two quantities ... current and resistance ... are inversely proportional.

So when the meter measures more current, it has to read less resistance, whereas

higher resistance will result in less current. So the numbers for resistance have to be

printed "backwards" on the meter scale.

1)in cc configuration we use to get the low output impedence

where as in ce we use to get the high output impedence.

2)in cc amplifier we use to have the voltage gain equal to unity

where as in ce amplifier we use to have the high voltage gain.

3)in cc amplifier there is high power gai which is used for impedence matching

where as in ce amplifier due to the high voltage gain the impedence matching is

less impossible.

If the first harmonic of 1 kHz is 2 kHz, then the second harmonic is the odd order harmonic of 3 kHz.

Yes. According to Einstein's 1911 paper, a light passing near a large mass will bend towards the mass. And it can also be refracted by materials of differing indexes.

When a bulb is added in parallel to a circuit with a single bulb, the resistance of the circuit decreases.

This is because the existing bulb's operating point remains the same, due to the fact that Kirchoff's voltage law states that the signed voltages around a series circuit must add up to zero, with the two bulbs being their own series circuit. A consequence of this is that the voltage across both bulbs must be the same, i.e. that the voltage across the first bulb does not change.

The second result of adding the bulb is that the current in the overall circuit increases.

This is because the second bulb must pull some current in order to operate, yet we know that the voltage across the first bulb did not change. As a result, due to Ohm's law, the current through the first bulb did not change. And, finally, since Kirchoff's current law states that the signed sum of the currents entering a node is zero, the addition of a second load in parallel with the first load must, therefore, represent additional current.

because reverse biased current is constant upto avalanche breakdown.

1.control circuit is used for removing ripple

2.analog circuits are also used with TPS84259 negative output voltage power module to reduce the ripple

Typically digital circuits will pump a lot of fast transient currents into the ground. Since real grounds have resistance and inductance, this will produce a drop between the ground of the digital circuits and the power supply ground. This is the so called "ground bounce".

If an analog circuit ground shares ground path between the digital ground and the power supply ground, it will see this voltage drop. Depending on the common mode rejection of the analog circuit in question and the frequency components in the "ground bounce" this may or my not be an issue.

If it's an issue, the easy solution is to connect the analog ground directly to the power supply ground without sharing any of the path from digital ground to main power supply ground. This way the current spike induced drops in the digital ground don't show up in the analog ground. A good example would be ADC grounding for the digital and analog portions of the ADC chip.

My husband said without hesitation AC!! DC power comes from batteries, AC power comes from electricity((generating power))....

cmos

voltage!

measured in volts.

current X resistance = voltage

simple ohms law

Depending on the situation. The purpose of the rheostat is use to change the resistance of the circuit.

The rheostat is use to define Ohm Laws

the 2nd situation is use to find out what the fixed resistor's resistance.

3rd purpose : used to control the resistance of circuit.

eg Radio

Diffusion capacitance is the capacitance due to transport of charge carriers between two terminals of a device. - Amog This diffusion capacitance is due to depletion capacitance which is a function of forward bias applied to emitter junction of a transistor and due to diffusion capacitance which a function of transconductance of the transistor. Its value is 100 pF. Tirupanyam B.V

Although most all utility power in the world use either 50 Hz or 60 Hz, 400 Hz power systems are typically used in large aircraft. The reason for the higher frequency is that most of the power system parts, especially the 400 Hz alternator and 400 Hz motors are much smaller compared with similar 60 Hz equipment of the same power rating.

In aircraft, every pound saved in equipment weight, equates to about a five pound savings in gross weight during flight. When equipment weight is reduced, both airframe structure and fuel load can also be reduced.

As flux is inversely proportional to speed and speed is proportional to frequency

Higher the frequency lesser the flux required.Lesser the flux,lesser the core size.Lesser the size means less weight.Hence the pay load can be increased.

Also frequency above 400 hz not taken because the radiation takes place beyond this.

controlling

It has poor regulation and wastes energy.

Inductor impedance is given by jwL, where w=2*pi*frequency. Therefore as the frequency increases the impedance of the inductor increases, causing a larger current flow and a larger power dissipation across the inductor

The alternative to laser capsulotomy is surgical capsulotomy

My mobile phone (an Alcatel) charger will supply 500 mA at 5 V. So the maximum continuous power it is capable of supplying will be the product of these two -i.e. 2.5 W. Of course, it won't necessarily ever reach that value in practise.

The circuit becomes a pure resistance circuit where current and voltage are in phase with each others.

There's no such thing as a 'negative voltage' in the 'polarity' sense, only in the 'direction' sense. So what exactly are you asking?