Probability

When the Draw 2 card is played, the next player only draws two cards; his turn is forfeited.

The next player after the one who drew may play the Wild Draw 4 and declare the color, but only if he does not have a card of the same color as the Draw 2. If the next player, the potential victim of the Wild Draw 4, doesn't believe that he didn't have a card of the same color as the Draw 2, that player may challenge. At that point the one who played the Draw 4 must show his cards. If the challenger was right, the one who played the Draw 4 picks it up, plays a legal card, and draws four cards. If the challenger was wrong, he must draw two extra cards in addition to the four.

88

It is used in many optimization problems.

it means that you want to do most either in liesure time or regular time.

HAZARD

45%

There are 10 choices for the first number, 9 for the second and 8 for the third. 10*9*8=720 possible combinations.

118.872

4

77.45%

Suppose that each time the game is played you win an amount X, with probability p or lose an amount Y with probability (1-p). To start with it is assumed that you cannot draw a game. Then each time the game is played you expect to win X with a probability p and lose Y (= win -Y) with probability (1-p).

Therefore, the expected gain for you, each time the game is played, is

X*p - Y*(1-p).

The game is fair if this value is 0. If it is greater than 0 the game is biased in your favour. Otherwise it is biased against you.

You can easily incorporate multiple outcomes - such as with a lottery: a bigger win for getting more numbers.

If X(1), X(2), ... X(n) are the n pay-outs to you (remember that what you pay will be a negative number), and P(1), p(2), ... p(n) are their respective probabilities where the sum of all the p(r) = 1, then your expected win per game is

X(1)*p(1) + X(2)*p(2) + ... + X(n)*p(n)

and the game is fair if this is 0.

A barge is the shape it is because it need to be able to push tons of things to anywhere if it wasnt that shaoe it wouldn't be ableto do anything

Odd-

3/12 ---> 1/4

Prime-

3/12 ---> 1/4

They are the same

3 out of 7

there can be only three combo's ------ head n tail,,,,,,,, tail n tail,,,,,,,,,,,,,, head n head

Describe how the Swap() instruction can be used to provide mutual exclusion that satisfies the bounded-waiting requirement.

11/16

M=0

n=0

m*n=0

Two sixes rolled on dice are commonly referred to as "double sixes." In many games, rolling double sixes can have special significance, such as providing an advantage or allowing an additional turn. In the game of craps, for example, it can be a winning roll.

Most games both, Some games only one, but you chose. BUT THE VALUE IS 1 OR 11

The area is 0.008894

It is 4/11.

Discrete controller

Look up the formula in a book of elementary statistics or on the web. The browser that we are required to use is not suitable for providing an answer.