Probability

natural sampling uses what?

As a decimal: 0.375

Or, treating this as a rational number: 6/16, 12/32, 9/24, ...

1

It depends on whether they are being arranged in a line or a circular pattern.

In a line: 15*14*13 = 2730 ways.

In a circular pattern : ABC, BCA and CAB will be the same pattern, only rotated. So the answer is 15*14*13/3 = 910 ways.

For each birth, you have two choices - either a boy or a girl. Then, the probability for a certain birth to obtain a choice is ½.

Using Binomial Theorem, we have (10 choose 8)(½)8(½)² = 45/1024.

23 or 8 outcomes. In any experiment with two outcomes, if you do the experiment n times there are 2n outcomes.

This about each time you roll the coin have two possible outcomes, H or T.

So if you roll it 2 times, you have 4 possible outcomes. HH, HT, TH or TT.

Do it one more time and you have 8 outcomes.

HHH, HHT, HTH, THH

TTT TTH THT HTT

Notice there are

1 outcome with 3 heads, 1 with 3 tails

3 with two heads

3 with two tails

This pattern follow the binomial theorem.

The coefficients of the binomial (H+T)3

are 1 3 3 1. The same numbers as we have above!

You multiply the possibilities so 6 possibilities of the dice and the 10 possibilities of the spinner so in total there are 60 possible outcomes for this situation.

smiles

It is called a normal distribution.

The kurtosis of a distribution is defined as the fourth central moment divided by the square of the second central moment. Unfortunately, this browser converts Greek characters to the Roman alphabet so I cannot use standard forms of equations but:

Suppose that for a random variable X, E(X) = m (mu)

and E[(X - E(X))2] = V = s2 (sigma-squared)

then

Kurtosis = E[(X - E(X))4]/s4.

Excess Kurtosis is then Kurtosis - 3.

If excess kurtosis < 0 the distribution is platykurtic. They have a peak that is lower than the Normal: the peak is flat and broad. The tails of the distribution are narrow. Uniform distributions are platykurtic.

A mesokurtic distibution has excess kurtosis = 0. The Gaussian (Normal) distribution - whatever its parameters - is mesokurtic. The binomial with probability of success close to 1/2 is also considered to be mesokurtic.

If excess kurtosis is > 0 the distribution is leptokurtic. Leptokurtic distributions have a high and narrow peak. A good example is the Student's t distribution.

ratio and gambling

these muscle groups either extend a joint, extensors) or contract the joint (flexors).

triceps extend the elbow joint, biceps bend the elbow joint.

"Dandy" Don Meredith

P(Rain) = 0.4

P(No Rain) = 0.6

P(Rain on 3 out of 5 days) = 5C3x(0.6)^2x(0.4)^3 = 0.2304

P(Rain on 4 out of 5 days) = 5C4x(0.6)^1x(0.4)^4 = 0.0768

So P(Rain 3 or 4 out of 5 days) = 0.2304 + 0.0768 = 0.3072

there are 36 possible combinations in two single die tosses. The odds of any one combination is then 1:36

The mean deviation of a set of observations is always zero and so conveys no information whatsoever!

A. B. P. Lever has written:

'Inorganic electronic spectroscopy' -- subject(s): Electron spectroscopy, Spectrum analysis, Physical inorganic chemistry, Physical and theoretical Chemistry, Inorganic Chemistry

'Inorganic Electronic Structure and Spectroscopy'

He doesn't think it is very funny.

Since there is no cube, the answer must be 0.

It depends on why the other half are disappearing!

For it is a very magic number which has many kinds of meanings.

2

The first dice can show any of the eight numbers.

If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from.

So the probability is 7/8 or 0.875 or 87.5% chance.

true A compound event consists of two more outcomes or simple events