Probability

It depends on whether you are playing poker or baccarat (21).

It can be divided into even piles of:

• 52 piles of 1 card each.
• 26 piles of 2 cards each
• 13 piles of 4 cards each
• 4 piles of 13 cards each
• 2 piles of 26 cards each
• 1 pile of 52 cards.

They are:HHH,

HHT, HTH, THH,

HTT, THT, TTH,

TTT.

chronological order

There are two possible results:

If there are only 10 cards in the stack

Out of the possible outcomes of drawing two cards, 4 outcomes have a sum of 9.(1+8, 2+7, 3+6, 4+5)

The total number of potential combinations are 10 potential choices for the first card and 9 for the second or 10x9=90

The odds of drawing the desired total (9) is 4/90 or 1 in 22.5

If there are more than 10 cards in the pile (several runs of 1-->10).

There are still a limited number of 2 card combinations that sum to 9:

1+8, 2+7, 3+6, 4+5

The number of combinations of cards that can be drawn are 10 potential choices for the first card and 10 for the second or 10x10=100.

The odds of drawing the desired total (9) is 4/100 or 1 in 25

You said "a" six sided dice. Though the singular is "die".

If you mean one die, the odds are 1 in 6 of it turning up five, or about 16.6%.

If you meant two dice, the odds are four out of thirty six, or 1/9th, or about 11%.

78 on an average scale of tests

2^2^2^2

* * * * *

Actually, the conventional notation is

either 2*2*2*2 or 2^4 = 16

1/68 inch, presumably.

The probability distribution function (pdf) is defined over a domain which contains at least one interval in which the pdf is positive for all values.

Usually the domain is either the whole of the real numbers or the positive real numbers, but it can be a finite interval: for example, the uniform continuous distribution.

Also, trivially,

the pdf is always non-negative,

the integral of the pdf, over the whole real line, equals 1.

A and B are independent events if the probability of their intersection equals the product of their individual probabilities, which is mathematically expressed as P(A ∩ B) = P(A) * P(B). This means that the occurrence of event A does not affect the occurrence of event B and vice versa. If this equation holds true, then A and B can be considered independent.

First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.

A R&B group that sang "My Beautiful Balloon."

90/270 but when it is 3.33333 the 3 is repeating

There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.

However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of the other two being boys is 0.2672.

It depends on the specific test.

try the mobius's circle..its a good topic

1/7

Very definitely, YES. It will be raining - somewhere on earth at any given moment of time.

classroom

?

There are 3 odd numbers and 6 possible outcomes so 3/6 or 50% chance it will be odd.

It is impossible to place a value on such a coin without seeing it. If it is in mint condition, or is uncirculated, it's value will be much higher, though I will say that it absolutely has some value, as do all error coins. Taking it to a trustworthy coin dealer is the best way to determine the specific value.

8!=8*7*6*5*4*3*2*1=40320 ways