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Probability
The probability of a certain event is a number expressing the likelihood that a specific event will occur, expressed as the ratio of the number of actual occurrences to the number of possible occurrences. In mathematics, it is a measure of how often an event will happen and is the basis of statistics.
14,643 Questions
The two components of distribution are?
Production and marketing
But if you're in PACyber like me, it would be "transportation and marketing."
What is the hoped for outcome with PCA?
The goal of patient-controlled analgesia is managed pain control, enhanced by a stable and constant level of the pain medication in the body. The patient is able to rest better and breathe more deeply
What are 3 outcomes as a resuly of the Reconstruction?
what are 3 outcomes as a result of Reconstruction
What is the Relationship between Acceptable risks of assessing control risk too low and sample size?
Acceptable Risk of Assessing Control Risk too Low (ARACR) is inversely related to Sample Size.
Consider this: If we do not want to allow any room for error in judgment (meaning we lower the ARACR), we must increase the sample size to ensure our results have a smaller margin of error.
(Source: "Auditing and Assurance," 14th ed., Arens Elder Beasley, 491)
How many ways can a person select 5 pictures to hang on the wall?
depends on the number of pictures to select from
If you only have 5 pictures you must select them all so there is 1 way to do it.
What is the expected number of flips of a coin to simulate a six-sided die?
Five coin flips. Any outcome on a six-sided die has a probability of 1 in 6. If I assume that the order of the outcome does not matter, the same probability can be achieved with five flips of the coin.
The possible outcomes of five flips of a coin are as follows:
5 Heads
5 Tails
4 Heads and 1 Tails
4 Tails and 1 Heads
3 Heads and 2 Tails
3 Tails and 2 Heads
For six possible outcomes.
That's going to depend on several facts which, sadly, you've chosen
not to share with us, such as:
-- How many marbles are in the pot before you add any ?
-- How many of those originals are blue ?
-- How many of the ones you add will be blue ?
-- How many will you chose ?
-- Will you keep each one you choose or replace it ?
All of these make a difference. Since we don't have any of this information,
any intention we may have to answer the question is doomed.
What is a conclusion based on evidence?
A conclusion based on evidence is called, well, a conclusion.
It could also be a deduction or a syllogism, but that is unnecessarily high-falutin, so to speak.
Two dice are rolled find the probability that the sum of observed values is equal to 13?
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
Exactly how rare is the date 09-09-09 statistically speaking?
It will happen once every 100 years.
September 9th will occur once a year, and the '09 year will happen in 2009, 2109, 2209, etc.
If we call the weight of the cat x, then the weight of the dog is 2x. We're told that the sum of the weights is 27, so 2x + x = 27. This is the same as saying that 3x = 27, so x must be 9. So the cat weights 9, the dog weighs 18.
A dog and a cat together weigh 27 pounds if the dog's weight is an odd number and if he weighs twice as much as shedoes how much does each weigh?
I know it isn't proper English but the cat is male (he) and the dog is female (she). So the cat weighs the 18 pounds and the dog weighs the 9 pounds so the dog has an odd number for it's weight.
How do you figure out mean absolute deviation?
Three steps:
- 1. Find the mean of all values
- 2. Find the distance of each value from that mean (subtract the mean from each value, ignore minus signs)
- 3. Then find the mean of those distances
What is independent probability?
An independent probability is a probability that is not based on any other event.
An example of an independent probability is a coin toss. Each toss is independent, i.e. not related to, any prior coin toss.
An example of a dependent probability is the probability of drawing a second Ace from a deck of cards. The probability of the second Ace is dependent on whether or not a first Ace was drawn or not. (You can generalize this to any two cards because the sample space for the first card is 52, while the sample space for the second card is 51.)
What are the chances of rolling 6 with 2 dice?
One cube can come up in 6 different ways.
The other one can come up in 6 different ways.
Together, the pair can fall in (6 x 6) = 36 different ways.
There are 5 different ways of rolling a 6:
1 - 5
2 - 4
3 - 3
4 - 2
5 - 1.
The probability of rolling a 6 is (5/36) = 13.89% .
The odds of a 6 are 5 in 36, or about 1 in 7, or about 6 to 1 against it.
How do you evaluate expression 43 plus 68 plus 57 and justify with each step?
do 43+57 which is 100
then do 100+68 which is 168
the answer is 168
How do you derive the exponential smoothing factor?
Lets define exponential smoothing first...
Exponential smoothing, or exponential moving average, is a running average of a set of observations, where the weight of each observation is inversely exponentially weighted as a function of how old it is. It is a relatively simple thing to do.
Given a set of observations O1, O2, O3, ... ON the running exponential moving average A1, A2, A3, ... AN can be calculated in real time, at each time N, with the expression ...
AN = AN-1 (1 - X) + ON X
... where X is a weighting factor that determines that amount of smoothing. For instance, if X were zero, then the smoothing is infinite, and O does not contribute at all to A, and if X were one, then smoothing is zero, and A follows O with no smoothing at all. In a more useful example, if X were 0.2, then the smoothing would be five, and A would follow O with a time constant of five iterations, i.e. after five iterations we would be at about 63% of one step change and after 25 iterations we would be at about 95% of one step change.
Some people swap the position of X and (1 - X) in the above equation. Its their choice, but the discussion that follows will have to change accordingly.
X is the smoothing factor. It is simply the number of iterations that you want for your time constant. If you were to model this as an electronic circuit, for instance, with a capacitor and a resistor, the exponential curve would be in the form ...
e-T/RC
... where RC was your time constant. The same thing applies here. If you evaluated the first equation once per second, with an X value of 0.2, you would have a time constant of 5 seconds. If you, on the other hand, evaluated it 100 times per second, with X being 0.002, you would still have a time constant of 5 seconds, but it would much more closely approximate the second equation, which is a continuous equation, rather than a discrete equation.
In summary, then, the smoothing factor, or X, is one over the number of iterations that you want to be your time constant.
How many possible outcomes would there be if eleven coins were tossed at once?
The answer depends on what the outcome comprises.
If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).
If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.
There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.
The answer depends on what the outcome comprises.
If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).
If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.
There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.
The answer depends on what the outcome comprises.
If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).
If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.
There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.
The answer depends on what the outcome comprises.
If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).
If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.
There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.
For the standard normal distribution the area between .79 and 2.67 is?
the area between .79 and 2.67 = .4962-.2852
= .2110
It means just what it seems to -- someone tosses a coin up and you try to guess which side will be facing up when it lands. "Heads" is the side with the person's face on it and "tails" is other side.
