Probability

An action modified by perhaps is less likely than the action modified by probably.

1.It Meant Music Performed For Dancing The Polka...

2.a A Bohemian Dance With 3 Steps And a Hop In Fast Time...

The total number of combinations are 6 x 6 or 36. Each of these combinations is equally likely. You can make a table with six rows and six columns to see all combinations. Two combinations, (1,2) and (2,1) will satisfy getting a one on one die and a two on the other one. Therefore the probability = 2/36 or 1/18.

probability of hitting a white key 7/12, probability of hitting a black key 5/12. Assuming all key have an equal possibility of being hit.

genetic drift

make it out of 100, so 40 times 2.5 equals 100 and 18 times 2.5 equals... 45 so its 45 percent

A six-sided die only goes up to 6. Therefore, when rolling two, you can get a total of 2 times 6, so 12 is the highest number possible, and you cannot roll a fourteen.

The probability of drawing a five or a jack from a standard deck of 52 cards is 8 in 52, or 2 in 13, or about 0.1538.

If 10 out of 26 are girls, then the probability of randomly choosing a boy is 16 out of 26, or 8 out of 13, or about 0.6154.

This is a combination problem because you have to assess a subgroup without a particular order. I find it easiest to first deduce what the total number of arrangements are and then subtract from there.

Firstly, There are a total of 9 balls getting assigned to a group of 4. So, to get our total, we use 9C4, which equals 9!/(4!*5!)=126. This means there are a total of 126 arrangements regardless of order. However, this number also includes the combination of 4 like-colored balls we're told to avoid.

To calculate the number of arrangements for 4 like-colored balls we set up a separate subgroup for each color. For red balls the possible arrangement are 5C4, which is 5!/(4!*1!)=5. For blue balls the possible arrangements are 4C4, which is 4!/(4!*0!)=1 (remember that 0!=1). So the total number of like-colored arrangements is 5+1=6.

Now we just subtract the exceptions from the total to get the answer...126-6=120

Assuming a 6 sided die, a roll of 2 gives a maximum value of 12. So the probability of getting a 16 is zero.

1 means the event is certain to occur.

Drawing hearts are pretty simple, but seeing as were over the Internet anyway, I can't draw it for you, so no. Go onto Google Images and look them up so you can copy them.

Since hearts and clubs consist of 1/2 of the deck of cards, the probabilility of getting hearts or clubs on a single pick from a well shuffled standard deck of cards is 1/2.

There are 52*51*50*49*48*47*46*45*44... (and on, and on and on) *3*2 arrangements of 52 cards, assuming that cards are not allowed to repeat (ie, once drawn, they are removed from the deck)

Assuming you mean from a standard 52-card deck of four suits, there is a 4/52 chance of first dealing an ace, a 4/51 chance of secondly dealing a king and a 4/50 chance of dealing a queen. Together, these mean there is a 64/132600, or 8/16575 or 0.04826546% chance of dealing the desired cards in order.

Identical twins are genetically the same, because they come from the same fertilized egg/sperm cell zygote, which happens to split into two viable zygotes.

Fraternal twins, however, come from two different egg/sperm cell zygotes, that are concurrently fertilized and remain viable.

Between the numbers of 0 and 1, 0 being never and 1 being definite

In mathematical terms, mean is the average of all numbers, and rang is the difference of the highest and lowest numbers in the set. Control limits refers to the lines drawn on statistical charts.

Impossible, you can't get 1-6 with only 5 dice.

The classic one is the coin toss problem. How many head and how many tails on a certain number of tosses.
For example we toss a coin 4 times and call a success the result of the coin landing with the head showing. The binomial variable is the number of heads n the four coin tosses, which can take on the values 0, 1, 2, 3, or 4. The probabilities of the possible outcome can be calculated using the binomial theorem.
Here they are:
P(X = 0) = 1/16

P(X = 1) = 1/4

P(X = 2) = 3/8

P(X = 3) = 1/4

P(X = 4) = 1/16

P = 0.5n (n!/(n-x)!x! )

When the sample is drawn, it is placed back where it was taken from and if subsequent draws are made, it could be selected again.

The probability is certain or 1. The max you can roll is 12 so it is certain the sum will be less than 13.

There are 4 eight cards, and 12 face cards including the Jack, Queen and King.

So 4 +12 =16, which is the number of eight and face cards you have in a standard deck.

To find the probability, we will have 16/52 = 0.308