Probability

20 * 19 * 18 * 17 = 116,280 ways

This is Permutation: nPr = n! / (n-r)!

If the first and second C are indistinguishable, then there are 554,400 permutations. If one is upper case and the other is lower case, then there are twice as many.

You can either determine the probability through fractions. ( i.e: a coin has only two sides, if flipped it will be either heads or tails; the outcome will be 1/2 to happen: so equal chance of either. )

However, you can also determine it by how likely something is to happen, e.g: if it is winter it is likely it will rain, yet in summer it is unlikely to rain.

no..........

theres 13 cards per suit...and 13 times four is????

suprise suprise its 52

Simple question, difficult answer. It depends on how many times you want the penny to land on heads. The probability of a penny landing on heads once is 1 in 2. For it to land on heads twice is 1 in 4, for three times it is 1 in 8, and so on and so forth.

250

Here's how:

1. Add the ratio: 7 + 5 = 12

2. Divide the total no. of marbles (600) by 12 = 50

3. The total no. of reds = 7 x 50 = 350

4. The total no. of blues = 5 x 50 = 250

(Total blues & reds = 350 + 250 = 600)

If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.

Possible outcomes are HH, HT, TH, TT; therefore the probability of HH is 1/4 or 0.25.

A set of probabilities over the sampling distribution of the mean.

yes, that deck will lose the cards you sold

According to Hoyle - when you cut, you must take at least 5 cards and at most 47 cards from the top of the deck.

Colorblindness is a recessive, sex-linked trait, and the gene that causes it occurs on the X chromosome. For the mother to be colorblind, she must have two copies of the gene and be homozygous recessive. The father, on the other hand, can not have the gene, because he (as a male) only has one X chromosome. So, if we let Xc represent the recessive gene for colorblindness and Xn represent the normal gene, the the mother is XcXc and the father is XnY.

All of their children will receive the recessive gene from their mother. In the males, this means that they will be colorblind, because the chromosome they get from their father will by the Y chromosome. The daughters, however, will get the Xn gene, which is dominant and will override the gene for colorblindness. Thus, all of the couple's sons will be colorblind, and none of their daughters will be.

you have 36 options:

1,1

1,2

1,3

1,4

1,5

1,6

2,1

2,2

etc

the only sums divisible by 2 or 3 are:

2,3,4,6,8,9,10,12

the total number of combinations are

1,1

1,2

1,3

2,2

1,4

2,3

5,1

4,2

3,3

4,4

5,3

2,6

6,3

5,4

5,5

4,6

6,6

which is

17/36

52 cards, 13 letters/numbers, 4 suits.

so there are 13 clubs.

7C3 = 35 ways.

The probability that 12 randomly selected people from a group of 12 men and 18 women will all be women is (18 in 30) times (17 in 29) times (16 in 28) times (15 in 27) times (14 in 26) times (13 in 25) times (12 in 24) times (11 in 23) times (10 in 22) times (9 in 21) times (8 in 20) times (7 in 19), which is equal to 8,892,185,702,400 in 2,180,547,008,640,000, which is equal to 68 in 16,675,which is equal to 0.00407796.

The probability of drawing two diamonds from a deck of cards is (13 in 52) times (12 in 51), or 156 in 2,652, or 78 in 1,327.

Actuaries, Mathematicians, Scientists, Financial Advisers, Physicians

is this a question

No. Only the king, queen and jack are the face cards.

5.8