Statistics

Bar chart consists of "x" axis 7 "y" axis which are been represented at the left vertical side & the bottom side respectively. To study the bar graph we have to first see what information is that chart telling u about 7 then see the units [if any]. And then to read the graph we first have to draw a parallel line from the top of the graph & joining to the x-axis. On the x-axis there r some measurements. Form that find the one {measurement} on which the line which u have drawn from the bar. Do the same with the y-axis too. And then u get the answer.

they are all measures of central tendency.

They tend to occur over pockets of magma and along the edges of tectonic plates

Truly there can be no diffence in either for they still are a pure form of energy.

There is one large spade in the middle. And one spade below each A on the card. So there are three spades.

no

It depends upon whether you use a 12 hour clock with am and pm, or a 24 hour clock. The 12 hour clock has just 1 set of 12 consecutive numbers, 1 2 3 4 5 6 7 8 9 10 11 12. The 24 hour clock has 13 sets of 12 consecutive numbers.

how many no.s are there from 1-56? 56

so u have to take 5 no.s at a time from 56 no.s

considering taking same digit more than once in a no.

it should be 56p5=458377920

The probability of getting 5 on one toss of a pair is 1/9. The most probable number of fives you will get after 42 tosses is 4 or 5.

Add the probabilities of getting 5 four, five, six, seven, eight etc times out of 42 tosses. By the time you get to 15 times, the probability will be very small and you can quit adding them up.

The probability of rolling 5 four times is (1/9)^4*(8/9)^38*42!/(38!*4!)

= 119,930*1.524*10^-4*1.138*10^-2

= 0.20803

The probability of rolling 5 five times is (1/9)^5*(8/9)^37*42!/(37!*5!)

= 8.507*10^5*1.6935*10^-5*1.2804*10^-2

= 0.18447

I am not going to continue this because it would take half the night, but you get the idea.

There is an easier way to do this that just occurred to me. It will give the same answer. Here it is:

Add the probabilities of getting 5 zero, one, two or three times, and subtract that from 1.

The probability of never getting five is (8/9)^42 = 0.007105

The probability of getting 5 only once is (1/9)*(8/9)^41*42 = 0.037304

The probability of getting 5 twice is

(1/9)^2*(8/9)^40*(42*41*/2) = 0.095591

Now YOU compute the probability of getting 5 three times. Add that to the probabilities above and subtract the sum from one. You should end up with a number around 0.6.

That will be the answer.

The mean is the average; the total of the members of the set divided by the number of members n the set.

6

Any time

Expressed as a percentage, 25/88 x 100 = 28.409 recurring (that is, 28.4090909...) percent.

Since there are six sides on a die, the odds of rolling a 4, or any digit for that matter is 1/6

It is 97.

It is an equation and the value of n is 5

Therefore: I/10 = 1/10

432 + 759 = 1191

a bar graph

nCr = n!/r!(n-r)! = 4

I'm using the combination formula where the place of the digits is not important No if the place

for instance the combination 312 is the same as 213.

But I think you are asking for a permutation instead where the placements of the digits are also important. So it would actually be 4!/(4-3)! or 24.

In a permutation the place is significant

i.e. 312 and 213 are distinct even though they have the same 3 digits.

the spin quantum number has only two possible values__(+ 1/2 & -1/2)

non

Because they are both measures of the same characteristic - the central tendency.

In a civilized culture whose citizens are accustomed to fundamental human rights

and the rule of law, one must hope that it's vanishingly small.

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