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The nitrogen iodide is NI3.
106.7 grams
10.8 grams silver (1 mole Ag/107.9 grams)(6.022 X 1023/1 mole Ag) = 6.03 X 1022 atoms of silver =====================
The formula N2O5 shows that there are 2/5 as many nitrogen atoms as oxygen atoms in the compound. Therefore, the number of nitrogen atoms required is (2/5)(7.05 X 1022) or 2.82 X 1022 atoms. The gram atomic mass of nitrogen is 14.0067 and, by definition, consists of Avogadro's Number of atoms. Therefore, the mass of nitrogen required to react with the specified amount of oxygen to produce the specified compound is 14.0067 [(2.82 X 1022)/(6.022 X 1023] or 0.656 grams of nitrogen, to the justified number of significant digits.
Let us do this in two parts for clarity. Find atoms in tin first. 10 grams tin (1 mole Sn/118.7 grams)(6.022 X 1023/1 mole Sn) = 5.07 X 1022 atoms of tin ----------------------------------- 5.07 X 1022 atoms (1 mole Pb/6.022 X 1023)(207.2 grams/1 mole Pb) = 17 grams of lead ------------------------------ I can see two other ways to do the conversion string, one longer and one much shorter. See if you can find them.
The nitrogen iodide is NI3.
Quite a few! 8.2 X 10^22 atoms of N2I6 (1 mole N2I6/6.022 X 10^23)(789.42 grams/1 mole N2I6) = 107 grams of N2I6 (Would have been peanuts without all that iodine! )
Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag
Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C
The mass is 2.86 grams but the weight will be 0.028 Newtons.
106.7 grams
2.13 g (6.02 x 1023 atoms) / (1.01 + 79.91) = 1.58 x 1022 atoms
107.5 g N2I6
10 grams lead (1 mole Pb/207.2 grams)(6.022 X 1023/1 mole Pb) = 2.9 X 1022 atoms of lead -----------------------------------
10.8 grams silver (1 mole Ag/107.9 grams)(6.022 X 1023/1 mole Ag) = 6.03 X 1022 atoms of silver =====================
divide the amount of particles given in the question by avagado's number to get the amount in moles. 3.01 x 1023 / 6.022 x 1023 which is about 0.5 moles. them multiply the amount of moles by the mass of Nitrogen to get it in grams. 0.5 x 14 = 7g
3.5 grams Na (1 mole Na/22.99 grams)(6.022 X 1023/1 mole Na) = 9.2 X 1022 atoms of sodium ===================