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25g / 250ml is 100g per litre. I'll let you know how to finish it. You need to divide by the molecular weight of your compound. I don't think C6H12O16 can actually exist. You may mean glucose, but that is for you to decide. It has been explained how to finish off the math in one step anyway.
Wiki User
∙ 10y ago
Wiki User
∙ 9y agoThere is not enough information to answer. We need the concentration of the hydrochloric acid to determine the number of moles of HCl. The volume of the acid itself is insufficient because the concentration is not specified. We would expect that a more concentrated 25ml sample of the acid have a larger number of moles of HCl.
Wiki User
∙ 15y agowe know that molarity M=no of moles of solute/vol of solution in litres therefore M=(25*1000)/(36.5*239) M=2.865 g/mol ANS.
Wiki User
∙ 14y ago25 mL HCl x 1L/1000mL x .200 moles HCl/1L HCl=.005 moles HCl
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How many moles of NaCl are formed from the reaction between 1.4 moles of HCl and 2.8 moles NaOH?
1.4 moles - the HCl is the limiting ingredient
How would you find the answer to this question How many moles of HCl can be formed when moles of hydrogen gas react with chlorine?
For each mole of hydrogen gas (H2) reacting with chlorine gas (Cl2), you will get 2 moles of HCl. H2 + Cl2 = 2 HCl
How many moles of sodium hydroxide are used for the tiltration if 17.65 mL of a 0.110 M sodium is needed to titrated 25.00 mL of a hydrochloride acid solution?
I need to see the balanced equation to work!NaOH + HCl --> NaCl + H2O ( good, all one to one )Now, find molarity HCl ( sodium, or sodium hydroxide; no matter )(17.65 mL)(0.110 M NaOH) = (25.00 mL)(X M HCl)= 0.07766 M HCl-------------------------now,Molarity = moles of solute/Liters of solution ( 25.00 mL = 0.025 L)0.07766 M HCl = X moles/0.025 Liters= 0.001942 moles HCl---------------------------------------formal set up, though not needed0.001942 moles HCl (1 mole NaOH/1 mole HCl)= 0.00194 moles sodium hydroxide used=============================
How many moles of potassium chloride are formed from 7 mol of HCl?
7: Molecules of HCl and KCl have the same number, 1, or chlorine atoms per mole; therefore, if HCl reacts completely with potassium, the same number of moles of potassium chloride as the number of moles of hydrogen chloride present will be formed. (For an ionic compound such as KCl, the term "formula unit" is preferable to "mole", but the mathematical consequences are the same.)
What is the molarity of the solution produced when 85.6 g of hydrochloric acid HCl is dissolved in sufficient water to prepare 0.385 L of solution?
Molar mass of HCl = 1 + 35.5 = 36.5 Number of moles of HCl = mass / molar mass = 85.6 / 36.5 = 2.345 moles Molarity = number of moles / Volume = 2.345 / 0.385 = 6.091 M
How many moles of HCl and needed to react 2.4 moles of Al?
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
How many moles are in 2 grams of HCL?
2 g HCl are equivalent to 0,0548 moles.
How many moles of HCl are present in 0.250 L of 0.400 M HCl?
Molarity = moles of solute/liters of solution, so... 0.400M HCl (X mols HCl/0.250L ) = 0.100 moles HCl
How many moles of NaCl are formed from the reaction between 1.4 moles of HCl and 2.8 moles NaOH?
1.4 moles - the HCl is the limiting ingredient
How many moles of solute are in 50 mL of a 12 M HCl solution?
Molarity = moles of solute/Liters of solution ( 50 ml = 0.05 Liters ) 12 M HCl = moles HCl/0.05 Liters = 0.60 moles HCl
How many moles of HCL are in 2.5 L of 0.5 M solution ?
1.25 moles HCl
How many moles of HCl are on 10 grams of substance?
The answer is 0,274 moles.
How many moles of HCL are there in 108 grams of the substance?
The answer is: 2,96 moles.
How many moles are in 8.63 mL of HCl?
It depends on the concentration of HCl in the solution.
How much caustic soda is required to neutralize a 25ml HCl solution at pH 3?
One step at a time.1/103 = 0.001 M HCl, so.....Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters )0.001 M HCl = X moles HCl/0.025 Liters= 2.5 X 10 - 5 moles HCl========================now, balanced eqiationNaOH + HCl --> NaCl + H2O ( all one to one )( now drive reaction towards mass NaOH )2.5 X 10 - 5 moles HCl (1 moles NaOH/1 mole HCl)(39.998 grams/1 mole NaOH)= 10 -4 grams caustic soda needed==========================
How many grams of HCl are needed to obtain 1.0 liter of a 0.22 M HCl solution?
First.Molarity = moles of solute/Liters of solution0.22 M HCl = X moles/1.0 L= 0.22 moles HCl--------------------------Second.0.22 moles HCl (36.458 grams/1 mole HCl)= 8.0 grams hydrochloric acid needed===========================
