Electrical Engineering

I believe there is no simple way to calculate this based just on the transformer structure; this is best calculated once the transformer is built, on the basis of actual measurements with currents. You would have to measure input and output

currents and voltages, calculate the input and output power, and divide output power by input power. This might give a number like, say, 0.98. Subtract this from 1 (1 - 0.98 in this example), and you have the transformer loss (in this example, 0.02, or 2%).

The total effective resistance of resistors in series is the sum of the individual resistances.

Three 60-ohm resistors in series have a total effective resistance of (60 + 60 + 60) = 180 ohms.

It is not clear what exactly is being asked-for in this question.

If it could be asked again, with a bit more detail as to what part of a household 110-120 Volt circuit is required, someone may be able to give a better answer than this one.

Increases the total resistance

Yes. But by constantly throwing the breaker handle back and forth will eventually loosen the mechanical parts inside the breaker to the point where the breaker will fail. There are breakers made for the purpose of switching, usually used in big warehouses to shut off banks of lights. The price of one breaker is probably equal to the price of about 10 standard light switches.

each phase is wired to its own breaker and all three breakers are tied together so they trip simultaneously (i.e., if one goes, they all go). If there is a neutral (as in a wye configuration), it connects to the neutral bar of the system, which may or may not also be bonded to ground (depending upon how the three-phase is derived and whether the panel is in the same building, among other things).

316

The end the shaft comes out.

Only a DC motor uses direct current, and the reason is that it is the only supply available.

There are also plenty of AC motors used when there is an AC supply.

DC tends to be used for low-power devices like fans in electronic equipment.

Mercury vapour contained in an evacuated glass bulb.
Vapour warmed.
High voltage applied to electrodes inside lamp.
Vapour conducts and allows current flow, excitation causes vapour to glow brightly.
Little or no resistance, so requires a ballast in line.

What is a Panel Meter? A panel meter is an instrument that displays an input signal in either a digital or analog form. Many panel meters also include alarm options as well as the ability to connect and transfer data to a computer. OMEGA's iSeries panel meters are available with an ethernet option which allows the panel meter reading to be accessed across a local area network (LAN) or even through the internet.

directly quoted from here: http://www.omega.com/PanelMeters.html

It means that it is by itself - as opposed to being bundled with other applications for example.

A commutator less DC motor is nothing but a self controlled synchronous motor is being widely used in industries for high speed and large capacity.

P, the power in kW (kilowatts) is related to V (the supply voltage) and I (the current in amps) by the Power Law:

P = V x I

So, to get the current:

I = P / V

If you have something that uses 5 kW (which is the same as 5000 watts) and the source voltage is 120 V,

then the current drawn in amps = 5000 / 120 = 41.67 amps.

Applied with PM servo motor. Because of power generation effect when stops, it is easier to brake. (Rotator: PM Stator: Windings) The magnetic force is be made by permanent magnet and the current is used to generate torque. Then high torque and efficiency are available at low current and small size. It has no brush so there is little noise/vibration and no dirt. And high precision control is available with high resolution encoder. A Servo motor Based on the design of conventional AC Synchronous motor, with addition of an Amplifier and a feedback device.

If a capacitor will not charge, it is open, i.e. damaged.

It depends on whether it is copper or aluminium, what its cross-sectional area is, and how it is to be installed. If you know all these things, then you can look it up in the tables provided in your country's wiring regulations. In the UK, this is BS 7671:2008 Requirements for Electrical Installations.

746 watts equals 1 HP.

the one and only the main difference b/n them is a dc motor takes the electrical energy as its input and gives mechanical energy as its output where as in the dc generator takes the mechanical energy as input and gives electrical energy as its out put

In both the case we can't get 100% efficiency because total input can't be converted into output.

If you are referring to domestic electrical outlets, most regions use either 110 - 120 volts or 230 - 240 volts.

If you are asking about an actual motor it is best to read the motor's rating plate.

If you are asking how to figure out the current in Amps drawn by a motor which produces a power output of 3 horsepower (hp) this question is way too vague to be answered accurately without knowing a lot more technical details.

The current drawn will depend on (a) the type of motor and (b) the Voltage that the motor is designed to run on. Regarding motor type, is it a Direct Current motor or, if it is an Alternating Current motor, is it a single-phase motor or a 3-phase motor. If it is a single-phase motor, then is it a squirrel-cage induction motor or a commutator motor of the type often used in vacuum cleaners or power tools? Another type of alternating current motor is the slip-ring synchronous motor but that type is not often used to supply only 3 horsepower.

A very rough way to calculate a possible current draw if you know the motor's operating voltage is to use the fact that 1 hp is approximately equal to 0.75 kiloWatts. So 3 hp = 3 x 0.75 = 2.25 kW.

Now, knowing that the actual efficiency of a motor depends entirely upon its design type, we shall have to assume an efficiency factor for the conversion of electrical power to mechanical power.

If we assume the motor is only 50% efficient then, to produce 3 hp, it will have to be supplied with electrical power of at least 2 x 2.25 = 4.5 kW.

Since Power P (Watts) = V (Volts) x I (Current in Amps), the current drawn I would therefore be given by I= P/V:

At 12 Volts DC: 4,500 / 12 = 375 Amps. (This would be a typical peak starting current drawn by, say, the starter motor of a small car engine in Summer. In Winter it might get to 500 Amps or more!)

At 120 Volts RMS AC: 4,500 / 120 = 37.5 Amps RMS single phase

At 240 Volts RMS AC: 4,500 / 240 = 18.75 Amps RMS single phase

UJT is the voltage controlled device.in which only one mejority carriers are responsible for current flowing. UJT is one junction transistor and it is three terminal emitter and two base.

BJT is the current controlled device. in which both mejority and minority carrier are responsiblefor current flowing. this type of transistor consists of two junction and three terminal these are : emitter , base , collector.

Yes. It will make your motor a little faster though, so it depends on what you are powering with this motor. IE Can the piece of eguipment be ran faster?