Electrical Engineering

3 amps

Resistances in series act just as if they were one single resistor. The value of the single resistor is the sum of the individual resistors connected in series ... Ra + Rb + Rc etc. When several resistors are in series, the effective total is greater than the biggest one. Resistance in parallel act just as if they were one single resistor. The reciprocal of the value of the single resistor is the sum of the reciprocals of the individual resistors connected in parallel ... Total effective resistance = 1 divided by (1/Ra + 1/Rb + 1/Rc + etc.) When several resistors are in parallel, the effective total is less than the smallest one. Once you figure out the effective value of the series- or parallel-combination of many resistors, you handle them as if they were one single resistor, and you can work with the voltage and current: Current through any resistance = (Voltage across it) divided by (its resistance).

Yes, the ECU is per default configured for supporting all the assessories available for that model. If it does not in your particular car either the ECU of the idle speed control valve is defective. Best regards Torben Machon

150000va divided by (600volts X 1.732) = 144 amps

That is used as a switching device. They are very common in Inverter circuits and can switch up to 1000's of amps.

The timing should allow the motor to get up to full RPM in the star configuration before switching to delta configuration. Depending on the motor size and inertia loading it will be from 5 to 10 seconds.

A little more than 6 volts RMS, or 17 volts peak to peak (can get -6 and +6 voltage this way using a full wave rectifier).

The voltage will depend strongly on your design - are you using circuitry that clamps the output voltage to a specific value (you should!). If you are doing this, I would find the cheapest transformer that meets the current capacity you need that has an output near the 6 volts you want.

The voltage is the same across all branches.

If this is a homework related question, you really should consider trying to solve it yourself before looking at this answer. Otherwise, the value of the lesson, and the reinforcement provided by the assignment, will be lost to you.

To calculate the current flow in one element of a parallel circuit, knowing the resistance of each element, consider the net resistance first.

Two resistors in parallel, R1 and R2, have a net resistance of R1R2/(R1+R2). For 50 ohms and 10 ohms, this is 8.333 ohms.

Now, consider the voltage across the resistors. By Ohm's law, voltage is current times resistance. For 12 amps and 8.333 ohms, you get 100 volts.

Now, consider the current through one resistor, By Ohm's law, current is voltage divided by resistance. For 100 volts and 50 ohms, you get 2 amps.

All of that said, now to the easier method...

Resistors in parallel form a current divider, just like resistors in series form a voltage divider. You have two resistors, 10 ohms and 50 ohms, with 12 amps going through them. The current through the 50 ohm resistor is the ratio of the other resistor divided by the sum of the two resistors. This is 12 amps times 10 / (10 + 50), or 12 amps times 1 / 6, or 2 amps.

You charge all capacitors the same way - you apply a current across them. The equation is dv/dt = i/c.

If it is a 240 volt conditioner it will stop. If it is a 120 volt conditioner it will stop if it is on the leg that has been lost.

made in china by workers who don't know what the heck they are doing,.

This is a 'chicken and egg' situation. The current passing through your body is determined by the voltage applied across your body, together with the resistance of the current path. So whilst it is true that it is the current that harms you, the voltage has to be high enough to cause the necessary amount of current to flow. In other words, it is equally valid to say that it is the voltage level that causes electrocution.

An analogy might be, which kills you: the height through which you fall, or hitting the ground? Obviously, hitting the ground is what kills you, but the height from which you fall determines how hard you are going to hit the ground.

As far as damage to electrical circuits is concerned, excessive voltage is responsible for insulation breakdown, while current is responsible for components to overheat. So high current will most certainly damage those components.

No. As temperature increases, resistance of semiconductors decrease.

This is because semiconductors have a small energy gap between their valence band and conduction band (in the order of 1 eV). Electrons must exist in the conduction band in order for the material to conduct but electrons exist in the valence band naturally. The electrons gain thermal energy for surroundings and jumps the energy gap from valence band to conduction band and hence, the SC material more readily conducts. As temperature increases, electrons can gain more thermal energy, more electrons can enter the conduction band and hence, resistance decreases.

In theory ... on paper where you have ideal components ... a capacitor all by itself doesn't have

a time constant. It charges instantly. It only charges exponentially according to a time constant

when it's in series with a resistor, and the time constant is (RC). Keeping the same capacitor,

you change the time constant by changing the value of the resistor.

Actually, electric utilities object to a lagging power factor, but it does not really matter if its leading (capacitive) or lagging (inductive). The problem is that true vs apparent is less than unity - that's the definition of power factor - and this causes the indicated power (KW) to be less than the actual power (KVA) by a trigonometric relationship between KW and KVAR (kilo volt-amperes reactive). That energy is still required to be provided, and this requires facilities in excess of what is indicated by the power meter.

its because of transformers . they work with pulse

When the resistance in all four are equal

A formula for 60 Hz with reasonable ventilation:

Imax = 7.73 x A^0.5 x p^0.39

A is the cross-section area in sq. mm and p is the circumference of the busbar's cross-section in mm.

So for a busbar of 100 mm x 5 mm the maximum current is 1391 amps.

50 hz is better .At this freq several losses in motors and power sys r reduced a lot when compared to 60 hz .also in 60hz sys the laminations must made thinner increasing initial cost.the advantage of 60 hz is ,we know that in present turbo alternator sys speed obtained is much higher than 3000rpm so this can utilised upto 3600rpm in caseof 60 hz sys

Yes. I think that is a definition of current.

The most common use of pF in electronics is to denote a picofarad, which is 1x10-12 Farads. The Farad is the base unit of measurement for capacitance.

A diesel powerplant uses the diesel power cycle for energy generation.

A diesel power plant is one using a diesel engine to run a generator coupled to it.

A generator produces power when it rotates.

Need to know which fuse u want to find out... There are quite a few different fuses in the fuse box. 10A 20A 30A, fuse for fan, fuse for Engine, fuse for horn?