Electronics Engineering

From ohms law, I = V/R hence Voltage and Resistance can affect the value of current, both peak and average.

Also with a rectifier circuit other factors can affect the peak current such as frequency and capacitance

Craig - AUT

The effective value of an AC = AC/√2.

Example: the effective value of 8.5 V AC is 6.01 V, because 8.5/√2=6.01

Hope that helped :)

It can be either a Bipolar Junction Transistor (NPN or PNP) or a Field Effect Transistor (N channel JFET, P channel JFET, N channel MOSFET, or P channel MOSFET).

0.1 micron

only with a converter box, but then it becomes just standard definition

It is impossible for a series circuit to have two points with two different currents. Kirchoff's Current Law states that the signed sum of the currents entering a node is zero. A consequence of this is that the current in every part of a series circuit is the same.

Please restate the question, giving correct information.

It was difficult to change directions and the vacuum tubes always burned out

because it is necessary to provide an over load protection ,surge protection,etc....hence an transformer is used...( particularly isolated transformers)

0V, I belive, since all voltage calculations are referenced against the reference node. (Been I while since I took EE201, though.)

The inventer of dead weight testers was Albert Einstein.

Einstein was involved in quite a few different areas of science, but he was hardly the inventor of dead weight testers. They predated him by a few hundred years.

This solution may not be suitable for all... but for some you can use this.. it's just that you need to first simplify the circuit using source transformation and reduce the given network to a current source in parallel or a voltage source in series.... and the resultant resistance is the thevin or norton resistance and that current or voltage source is the equivalent thevin voltage or norton current.

You could try doing your own homework and learning how to solve it for yourself the way your teacher taught you!

OBVIOUSLY a 1 ohms resistor will show as zero for all the higher scale except for the low range

Lock Range of a PLL is the range of frequencies centered at free running frequency of VCO, around which the PLL can remain in locked state.

Capture Range of a PLL is the range of frequencies centered at free running frequency of VCO, around which the PLL can acquire lock-in from an unlocked state.

The relation is Capture Range<=Lock Range

No. The diode conducts during only 1/2 of the cycle, leaving

a big hole and no DC where the other half-cycle should be.

To limit the current

One can purchase good stereo amplifiers from various websites like Amazon or eBay. One could also visit a local hardware store and ask if they have any good stereo amplifiers for sale.

Hall Signal Company ended in 1925.

Some advantages of the Yagi- Uda Antenna include that this is a widely used design and low cost. The construction also is simple. Some disadvantages are that the receiver of the Yagi-Uda Antenna may have problem receiving signal.

That would depend on the power supply.

Yes. As long as the load stays the same. Voltage equals the resistance of the load times the current or amperage. Or , in this case, as an example, if the load is the same, the voltage is 240 and current is 10 amps. At 120 volts, the current is 20 amps. Current x resistance(or the load)=voltage. With simple math, the equation can be moved around.

Have sexwith the teacher

Besides checking engineering texts for these diagrams, there are a number of places to look line. Planet Analog, Red Circuits, AMS, Industrial Controls, and Circuit Finder all have detailed diagrams of capacitive sensors.

In electronics, a common-emitter amplifier is one of three basic single-stage bipolar-junction-transistor (BJT) amplifier topologies, typically used as a voltage amplifier. In this circuit the base terminal of the transistor serves as the input, the collector is the output, and the emitter is common to both, hence its name. An analogous circuit called the common source is constructed using field-effect transistors Common-emitter amplifiers generally have a very high gain which can vary widely from one transistor to the next, as it is a strong function of both temperature and bias current, making the actual gain unpredictable. Stability is another problem associated with such high gain circuits, due to any unintentional positive feedback that may be present. Other problems associated with the circuit are the low input dynamic range imposed by the small-signal limit and the high distortion resulting if this is exceeded. One common way of alleviating these issues is with the use of negative feedback, particularly with emitter degeneration. Emitter degeneration typically refers to the addition of a small resistor (or any impedance) between the emitter of the transistor and ground. The effect of this is to reduce the overall transconductance Gm = gm of the circuit by a factor of gmRE + 1, making the voltage gain depend more on the ratio of the resistors than the transistor's characteristics: The distortion and stability characteristics of the circuit are thus improved, but at the expense of a reduction in gain. Common-emitter circuits are used to amplify weak voltage signals, such as the faint radio signals detected by an antenna. When used in radio frequency circuits, it is common to replace the load resistor with a tuned circuit. This is done to limit the bandwidth to a narrow band centered around the intended operating frequency. More importantly it also allows the circuit to operate at higher frequencies as the tuned circuit can be used to resonate any inter-electrode and stray capacitances, which normally limit the frequency response. Common emitters are also commonly used as low noise amplifiers. At low frequencies and using a simplified Hybrid-Pi model, the following small signal characteristics can be derived. If the emitter degeneration resistor is not present, RE = 0 Ω. According to these formulas and in agreement with the previous discussion, when RE is increased the input resistance is increased and the gain is reduced. {| ! ! Definition ! Expression ! Current gain ! Voltage gain ! Input resistance ! Output resistance |} The bandwidth of the common emitter amplifier tends to be low, due to high capacitance resulting from the Miller effect. The base-collector capacitance is effectively multiplied by the factor 1 − Av, thus increasing the total input capacitance and lowering the overall bandwidth. The discussion of bandwidth parallels that in the article on the common source amplifier. A fix for this bandwidth problem is the cascode amplifier. == ==

1/(2 Pi sqrt(LC))

it works like this the 1.21 giggawatts of electricity that is generated by the plutonium that has been put into the back port of the de lorean is generated into the other electrically materialized parts and there it is