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Intel 8086 and 8088

The Intel 8086/8088 family of microprocessors is a 16 bit architecture on a 16 bit (8086) or an 8 bit (8088) bus. The 8088 was the processor in the original IBM PC, and has evolved into the most popular processor used today in PC's and servers.

1,056 Questions

How is a procedure identified as near or far?

The far procedure is used at the place where the function call is given in main program and function definition is given in sub program....

What is the address space in a system with 16-bit addresses?

It depends on the size of the address bus, which is often different than the size of the data bus.

  • If the address bus were 8 bits, then you could address 256 locations.
  • If the address bus were 16 bits, such as in the 8085, then you could address 65,536 locations.
  • If the address bus were 20 bits, such as in the 8086/8088, then you can address 1,048,576 locations.

Which are the highest priority interrupts?

when interrupts requests arrive from two or more devices simultaneously , the process has to decide which request should be serviced first and which one should delayed. the processor takes the decision with the help of interrupt priorities.

What are different program development tools?

A good IDE, or Integrated Development Environment, is useful but not necessary.

What you need is the language installed on your computer, with a compiler if you plan on releasing them, and a basic text editor not a word processor.

How many machine cycles require for call instruction in 8086?

It depends on the type of architecture and controller u use. It can be found in the instruction set documentation. It requires 18 cycles on the Intel 8085.

How_many_machine_cycles_require_for_call_instruction_in_8085

Execution unit bus interface unit function 0f 8086 8088?

The 8086/8088 is comprised of two major subsystems; the execution unit (EU), and the bus interface unit (BIU). They are relatively uncoupled, so they can run somewhat independently of each other. The EU is responsible for executing all of the instructions, while the BIU is responsible for processing the requests from the EU to and from external memory.

By separating these two major functions, Intel achieved two goals.

First, they were able to provide two versions of the same processor, one on an 8-bit bus (the 8088), and the other on a 16-bit bus (the 8086). Both EU's are the same, a 16-bit processor. The two flavors allow the system designer to choose the level of simplicity versus the level of performance.

Second, by decoupling the EU from the BIU, the BIU is now able to start fetching instructions from memory, while the EU is busy processing the previous instruction. Depending on the mix of instructions, the BIU is theoretically capable of having the next instruction already fetched and available by the time the EU needs it. This boosts performance.

What is tristate bus and how it used in microprocessor?

In Microprocessor based system devices are connected n parallel through the bus in this situation it is required that one device is interact with the bus at a time .If more than one device make communication wid bus then more then one signal is places that they will produce damaging current known as Bus Contention.To avoid bus contention tristate buffer are placed between buses and peripheral...

How segment register are used?

The segment register in the 80806/8088 microprocessor contains the base address (divided by 16) of a region of memory. Since the register is 16 bits in size, there are 65,536 possible segment base addresses, ranging from 00000H to FFFF0H, in increments of 00010H.

After address translation at the instruction level, the generated 16 bit offset is added to the selected segment register times 16 to generate a physical address between 00000H and FFFFFH. (If the offset and base go past FFFFFH, they wrap around back to 00000H.) Since the offset is also 16 bits in size, and since the overlap is only 4 bits (times 16), then each 64 kb segment overlaps by 16 bytes.

There are four segment registers; CS, DS, ES, and SS, standing for Code Segment, Data Segment, Extra Segment, and Stack Segment.

CS is used for opcode fetches. DS is used for normal data. ES is used for certain string operations as the destination address. SS is used for stack and frame (BP) data.

The segment registers can be implicitly selected by context, or they can be explicitly selected with a segment prefix opcode.

How many no of address lines required in 1MB memory 111622 or 24?

How many no of address lines required in 1MB memory 11,16,22 or 24

u haven't specified correct options!

20 address lines will be required

because

1 MB is 1024 KB that is 1024*1024 Byte which is equivalent to (2^10)^2 bytes

if ur memory is Byte addressable then address lines required will be 20.

Is flight data recorder fire proof?

Nothing is waterproof, especially considering the high stresses involved in an airplane accident. The flight data recorder is water resistant. It is also designed to minimize the probability of data loss even if it does get wet internally.

Size of 8086 address bus?

The 8086/8088 has an internal 20-bit address bus and 16-bit data bus. Externally, the address bus is 20-bits, and the data bus is 16-bits for the 8086 and 8-bits for the 8088.
The data bus in the 8086 is 16 bits in size, while the address bus is 20.

What is handshake signal in microprocessor 8086?

I/O devices accept or release information at much slower rate than the microprocesor. Handshaking is the method that synchronize the I/O device with microprocessor.

When does a microprocessor encounter the HLT instruction?

It encounters the HLT instruction when there is not an endless loop or other things that are done endlessly.

What is effective address or offset?

the address that is obtained by applying any specified indexing or indirect addressing rules to specified address

What is the different between local address and physical address and port address?

Physical address: the MAC address; most commonly this is a type of unique number assigned to the network card. This can usually be considered fixed. This corresponds to layer 2 in the OSI model.

Logical address: an IP number assigned to a computer. These numbers can and will be changed, to have all the computers in a certain subnet have addresses that start (for example) with the same three octets (bytes). Layer 3 in the OSI model.

Port address: TCP or UDP port numbers. Used to distinguish different services or different conversations on a single computer (in other words, these are not addresses to distinguish different computers, but to distinguish different things within a single computer). Layer 4 in the OSI model.

Note: The above explanation uses the most commonly used protocols; but other protocols (other than IP, TCP or UDP) are also possible.

What is fetching in microprocessor?

1) Fetch is the first of two stages involved in computer processing. The processor operates by processing instructions in what is called the "fetch/execute cycle." The processor fetches (reads from memory) an instruction and then, depending on the instruction, executes it (takes some further action with it, such as shifting bits to the right or left). Then it fetches the next instruction, and so forth.

Why you call microprocessor as a microprocessor?

The emitter of a transistor was placed a micrometer distance between two, so it was called a microprocessor. Technology advanced, and the distance was improved to nano meter. Still, they call it micro.

Why pipelining used in 8086?

8086 is a pipelined processor.

In 8086 to speed up the execution of a program,instruction fetching and executing the instruction are overlapped each other.This is a part of pipelined technique.

What is memory interface unit?

While executing a program, the microprocessor needs to access memory frequently to read instruction codes and data stored in memory and the interfacing circuit enables that access.

Which microprocessor accepts the program written for 8086 without any changes?

Which microprocessor accepts the program written for 8086 without any changes?

Difference between direct addressing mode and indirect addressing mode in detail?

Direct addressing mode means the operand address is contained in the instruction. In the 8085, an example is LDA 1234H, which loads the accumulator with the contents of memory location 1234H. In the 8086/8088, an example is MOV AL,[1234H], which accomplishes nearly the same thing.

Indirect addressing mode means the operand address is contained in a register. In the 8085, an example is LDAX B, which loads the accumulator with the contents of the memory location specified in register BC. In the 8086/8088, an example is MOV AL,[BX], which accomplishes nearly the same thing.

How do you calculate physical memory address?

Physical address's are set at factory, the first 6 characters are that of the manufacturer.

The last 6 digits are unique to that product/device.

This is not a calculated field.

A microprocessor has 24 parallel address lines How many memory locations can the processor address?

32 bit address line can access 4GB of memory. As 2^10 -> 1KB; 2^20 -> 2MB; 2^30 -> 1GB and so on.... 32 bit gives (2^30) * (2^2) = 1GB * 4 = 4GB;

What are the disadvantages of 8085 microprocessor?

It works on 8 bit

lower address lines has to be multiplexed with data lines

Appropriate control signals have to be generated to interface with memory and I/O devices

8 bit processors are slow

Memory is just 64 kb

By Anmol Bhardwaj

SUSCET Tangori Mohali ( India)