Statistics

around 81%

45% = 0.45

No.

• i don't know if you know it please help me

50%

Yes.

Yes. It should reduce the variance.

The answer will depend on what is being stored: whether it is low quality audio or high definition video!

7.7% or 4/52

6/7

It is 15/50 = 0.3

Easy don't know

It is 1/12.

1 and 10

If the pearson's skew is between 0.0 and 0.49, then it is a normal or non-problematic distribution. If it is above .50, then it is not a normal distribution.

In appearance:

The data should be symmtrical; the mode and median should be very close to the mean; around 65 % of the observations should be withing one standard deviation (SD) of the mean; 95% of observations with 2 SD of the mean and almost all within 3 sd.

Better evidence can be provided by the chi-square or Kolmogorov-Smirnoff goodness-of-fir tests.

There may also be evidence from the nature of the data. For example, the means of samples will be closer to being normally distributed (Central Limit Theorem) than the individual observations.

Yes

90

It is wrong because there is no such thing the highest "Percent" ever is 100%

you can get graded higher than that in school sure but that is because you have gotten extra credit

The median is a single number. If there are an even number of observations so that there are two "middle" numbers, then the median is the arithmetic average of the two (their sum divided by 2).

None, since there is nothing for the number to be equal to (or eaqual, even).

Because in order to keep the same measurement

Expressed as a percentage, 46/56 x 100 = 82.142857 recurring (that is, 82.142857142857...) percent.

A node.

(4 + 4 + 4)/4 = 3

10100