C Programming

(C and Lisp, ... data type") was adopted by many later languages, such as ALGOL 68 (1970), Java, and C#. ... C++ has a separate Boolean data type ( 'bool' ), but with automatic conversions from ... "Report on the Algorithmic Language ALGOL 68

2L is the literal constant for a long (int) type with the value 2.

#include using namespace std;int main() { int age[10]; int num=1;cout<<"How many persons are there in list ? "; cin>>num; for(int x=0; x { cout<<"Enter person"< cin>>age[x]; } int eldest = age[0]; int young = age[0]; for(int y=1; y < num; y++) { if(age[y] > eldest) { eldest = age[y]; } if(age[y] < young) {young = age[y]; } } cout<<"Age of eldest person is "<cout<<"Age of youngest person is "< return 0; }#include using namespace std; int main() { int age[10]; int num=1;cout<<"How many persons are there in list ? "; cin>>num; for(int x=0; x { cout<<"Enter person"< cin>>age[x]; } int eldest = age[0]; int young = age[0]; for(int y=1; y < num; y++) { if(age[y] > eldest) { eldest = age[y]; } if(age[y] < young) {young = age[y]; } } cout<<"Age of eldest person is "<cout<<"Age of youngest person is "< return 0; }

#include<stdio.h>

#include<conio.h>

#include<string.h>

void main()

{ char str1[20];

char str2[20];

int x,y,n,r,counter1,counter2,points=0;

clrscr();

printf ("Please enter a name: \n\n");

gets(str1);

printf ("\nEnter another name: \n\n");

gets(str2);

counter1=strlen(str1);

counter2=strlen(str2);

for (x=0; x<counter1; x++)

{ for (y=0; y<counter2; y++)

{ if (str1[x]==str2[y])

points++;

else;}

if(points!=0)

points++;

}

for (n=1; n<counter1; n++)

{ if (str1[0]==str1[n])

points++;

else;}

printf ("\n%d \n",points);

r=points%6;

switch®

{

case 1: printf ("\nFriends"); break;

case 2: printf ("\nLovers"); break;

case 3: printf ("\nAffection"); break;

case 4: printf ("\nMarriage"); break;

case 5: printf ("\nEnemies"); break;

case 0: printf ("\nSister"); break;

}

getch();

}

In C++, enum signifies a slightly stronger type than in C.

For example, in C, one could write:

enum Direction { UP, DOWN };

Direction d = 1;

In C++, this would be illegal, only UP or DOWN can be assigned to a variable of type Direction, though there is still implicit casting to integer, so one could still write:

int i = UP;

Another difference has to do with the way variable are declared in general in C++. In C, once the enum was declared as above, declaring variables of type Direction would have to be done through the enum keyword, like this:

enum Direction d = UP;

In C++, the name "Direction" becomes a type in itself, so you can write:

Direction d = UP;

He considered the "goto" statement to be harmful.

#include<iostream>

using namespace std;

#include<conio.h>

void main()

{

char m[100];

int units[100],i,j,n;

float x,tb;

cout<<"enter the total number of bills to be calculate:\n";

cin>>n;

for(i=1;i<=n;i++)

{

cout<<"\nenter the name \n:==>";

cin>>m;

for(i=0;i<n;i++)

{

cout<<"\nenter the total units consumed \n:==>";

cin>>units[i];

}

}

if(units[i]<=100)

{

x=units[i]*0.6;

tb=50+x;

if(tb>300)

{

tb=0.15*tb+tb;

}

cout<<"\ncalculated bill:==>";

cout<<m<<tb;

}

else if(units[i]>100 && units[i]<=300)

{

tb=100*0.6+(units[i]-100)*0.8+50;

if(tb>300)

{

tb=0.15*tb+tb;

}

cout<<"\ncalculated bill:==>";

cout<<m<<tb;

}

else if(units[i]>300)

{

tb=100*0.6+200*0.8+(units[i]-300)*0.9+50;

if(tb>300)

{

tb=0.15*tb+tb;

}

cout<<"\ncalculated bill:==>";

cout<<m<<tb;

}

getch();

}

constants are values that does not chnage through out the program exceution..

i cant sorry

FIFO, means "First In, First Out". An example of such a data structure is a queue.

There is no builtin function 'counta' in C.

#include #include
#include
void main()
{
char a[50],r[50];
int i,j;
printf("\n Enter the string:");
gets(a);
for(i=strlen(a)-1,j=0;i>=0;i--,j++)
r[j]=a[i];
r[j]='\0';
printf("\n Reverse string is %s",r);
if(strcmpi(a,r)==0)
printf("\n the original string is a pallindrome");
else
printf("\n the original string is not pallindrome");
getch();
}








Note:-If you want it case sensitive then use 'strcmp' instead of 'strcmpi'

class Abc

{

public static void main(String[] args)

{

System.out.println("Hello World!");

}

}

by this program you can find the factorial:

#include<iostream>

using namespace std;

main()

{

int n,x,f=1;

cin>> n;

x=0;

while(x<n)

{

x++;

f= f*x;

}

cout<<"factorial is"<<f<<"\n";

system("pause");

return 0;

}

echo enter n value

read n

sumodd=0

sumeven=0

i=0

while [ $i -ne $n ]

do

echo "Enter Number"

read num

if [ `expr $num % 2` -ne 0 ]

then

sumodd=`expr $sumodd + $num`

sumeven=`expr $sumeven+$num`

fi

i=`expr $i + 1`

done

echo Sum of odd numbers = $sumodd

echo Sum of even numbers = $sumeven

design a flowchart that will input three numbers and get their sum. If the sum is greater than 20, then print "sum>20",else print the sum.

For a full binary tree of height 3 there are 4 leaf nodes. E.g., 1 root, 2 children and 4 grandchildren.

Strong number is a number for which sum of factorials of the digits is equal to the given number.

Eg: let us consider 145 where sum of factorials of the digits= 1!+4!+5!=1+24+120=145 i,e., the given number.

c program for strong number is:

#include<stdio.h>

#include<conio.h>

void main()

{

int sof=0,n,dn,ctr,prod,rem;

printf("Enter the number\n");

scanf("%d",&n);

dn=n;

while(n!=0)

{

prod=1,ctr=1;

rem=n%10;

while(ctr<=rem)

{

prod=prod*ctr;

ctr=ctr+1;

}

sof=sof+prod;

n=n/10;

}

if(sof==dn)

{

printf("The number entered is strong number");

}

else

{

printf("The number entered is not a strong number");

}

}

By

Nagarjuna

sri indu ECE,

IBP.

What is the difference between data communication and telecommunication ?

if one dimension means it have only rows but in two dimension means it have both row and coloumns

The native Assembly language of the given platform.

For example it would be stupid to write anything in Motorola 68000 Assembly for Intel x86 platform: it wouldn't work.

#include<stdio.h> main() { int a,b,c,d; // The four integers to be asked printf("Give the first integer: "); //asks for the first integer scanf("%d",&a); // puts the user input in the address of the integer "a" printf("Give the second integer: "); //same explanations scanf("%d",&b); printf("Give the third integer: "); scanf("%d",&c); printf("Give the fourth integer: "); scanf("%d",&d); printf("1. The sum of the four integers is: %d",a+b+c+d); //prints the sum of the four integers given by the user, notice the "a+b+c+d" at the end) printf("2. The sum of the first two numbers minus the sum of the last: %d",a+b-c-d); //prints the second condition by putting the correct operations return 0; //ends the program } I never tested this program though, but i think it would work.

Unfortunately, there is no power function in C/C++, so you'll have to make one yourself. I made one a few days ago, here it is:

int power (int one, int two)

{

int temp = one, counter = 1;

while (counter

{

temp *= one;

counter++;

}

return temp;

}

/* PROGRAM TO CALCULATE THE VALUE OF X RAISED TO GIVEN POWER*/

#include <stdio.h>

#include <math.h>

#include <conio.h>

main()

{

int x,power;

float result;

clrscr();

printf("Enter the value of x:");

scanf("%d",&x);

printf("Enter the value of power:");

scanf("%d",&power);

result=pow(x,power);

printf("The value of %d^%d is %f",x,power,result);

getch();

return;

}