Electrical Engineering

CTC refers to the current Cost to Company. CTC is a term that is used to describe an investment without a return. Things like the travel expenditures and interviewing are usually interpreted as CTC's.

The typical analog circuit that connects between the customer premises and the central office (phone company) has two copper wires. These wires are referred to as TIP and RING. There is typically a -48 VDC signal between the TIP and RING wires which is typically powered by the central office switch. When a standard analog phone is connected to the analog circuit and the handset is picked up (going off hook) a switch on the phone closes the connection between the TIP and RING wires and current is drawn from the central office switch. The switch determines that current is being drawn and provides dial tone so the person on the phone knows it is time to dial a number. A PBX FXO circuit running loop start looks like a standard analog phone to the central office switch. Now, one problem that is often seen with loop start circuits is a condition called "glare". Glare occurs when a call comes in on the analog line from the central office at the same time the PBX wants to seize the same line to make an outgoing call. The ground start protocol was designed to eliminate this problem with glare. From the PBX side, the RING lead is grounded first, then the central office circuit must ground the TIP lead before the PBX can close the loop between TIP and RING.

Possibly... but only a trained electrical technician would be licensed to do that kind of work!

Assuming that the output you've listed is after the power factor has been taken into account:

Then 240x100 =24000w.

The power factor is 0.94, therefore 24000 divided by 0.94 = 25531.915 VA.

Power loss 25531.915 - 24000 = 1531.9149 VA.

The way I have done this with things such as heaters, window defrosters, etc. is to model the heating element as a resistor (or a set of resistors in different parallel and series combinations, based on the layout). The wire used in the electric blanket (the heating elements) should have a specific resistance per length; calculate the length of the different sections, and create a lumped resistive element of this total length.

i think sag compensation springs are used in dead end termination of quadra conductor bus where jack bus is passing below bus & required clearence if we are not getting betn two buses their these sag compensation springs are used to bring conductor under tension .

P=v*i i=p/v=0.5/3=1/6 (a)

A: The gains add up to 12 db

Refer IEEE 80- 2003 For Design of grounding of 132kV substation.

Three formulas are used to solve this problem V = Ed, C=(AKE0)/d and Q = CV.

V= Electrical potential (voltage)

E = Electric field (or Electric strength in this case) (3*106 for air

d = distance (plate separation

C = capacitance

A = Surface area (9*10-4 m2)

E0 = 8.85 * 10-12

K = Dielectric constant (roughly 1 for dry Air)

Substitute C and V from the first two formulas into Q = CV.

Q = (AKE0)/d * Ed

the distance cancles and you end up with Q = (AKE0)E.

Substitute in your numbers to find Q

The alternator output voltage in most modern 12 volt automotive systems ranges from 13.5V to 14.5V, with the nominally accepted value being 13.8V. The actual voltage depends on battery charge state and temperature.

One gallon of power is approximately 8.3 pounds, so the energy released, when 1 gallon of water falls 10 feet, is 83 foot-pounds, which is equal to 0.31 watt-hrs.

If this energy were mechanically converted to electrical energy, approximately 40% losses would occur in converting the falling water into rotational, mechanical energy by a Pelton wheel or other water impeller, and about a 5% loss in conversion of rotational energy to electrical energy by a generator. So the extracted energy would be about 50%. Of that 0.31 watt-hours of energy, about 0.15 watt-hours would be delivered in the form of electrical energy, and the other 0.15 watt-hours would be lost in the form of heat.

An Electric field stress depends on the mechanical strength of the materials and the stresses that are generated during their operation. During high voltage applications, the dielectric strength of insulating materials are developed when subjected to high voltages.

11.5 x 240 = 2760W motor.

You didn't describe the type of clock radio or age so the following are just guesses to apply to your situation.

Unplug the radio from the wall. If the noise still persists, it isn't the radio, but something else around the radio.

Is the clock and old fashioned mechanical clock. If so it could be the clock motor.

The radio could still be on when you think it is off. This is possible in some models where the on/off switching is electronic rather than mechanical.

There is something living inside the clock radio. Sound will persist even when unplugged.

There is a strong electromagnetic field in vicinity of radio which is causing a resonance frequency in the radio electronics even when off. Move the radio to another part of house and see if sound changes.

A diode is an electronic component that will only allow current to flow through it in one direction. It is analogous to the valve in a bicycle tyre, which only lets air in but not out (except when you press the release tab). So if you connect a diode in a simple DC circuit one way around, the circuit will be closed and any devices on the circuit will work. If you connect it the other way around the circuit is open and no current will flow.

I presume by 'ordinary diode' you mean a diode that is not a light emitting diode (LED). A LED is just a diode that emits light when current flows through it. Its purpose is to make light. A non-LED diode doesn't emit light. Its purpose is to allow current through a circuit in only one direction.

A common use for ordinary diodes is in "rectifying circuits" which convert AC to DC.There are many other uses though.

I think it's a test for a shorted armature.

A voltage can be induced on a ground wire by other wires nearby. If you have more than one ground wire, The induced voltage will cause a current flow up one, and down through the other. By removing one of the two, you interrupt the loop.

it is related to Slip ring rotor max.currents and voltage ...

No. Touching a live electric current is never a good idea.

Powerplants that run on Natural gas does not hold a very bright future, as most of the Country's land transport relies heavily on Natural Gas, in addition to some of already installed power plants that run on the same fuel. If we look at the geographic distribution of the country's gas reservoirs, then we shall find that most of them are lying at Baluchistan Province, where the security issue is on a rise, since a few years.

So, you may think of a power plant, which may not get the fuel after 5 to 10 years time from local sources, or may be not getting it after the next day you comission it (due to any attacks on the main pipelines).

Powerplants that run on oil can also be converted to use natural gas as their fuel. However, the oil power plants may have better future prospects, as the the oil reservoirs of the country are dithered apart on the map and also the import route of the oil lies in safe regions (Mostly Karachi Port).

However, the most enticing offer for any investor in this sector will be in the coal power plants-- the reservoirs are enough to power the country for next 100 years or more, only if managed with 33% efficiency. The location of the reservoirs are in a very safe places (politically) and that is not far from the main cities which have most of the industrial loads (specially cities of Punjab Province).

The sigmoid sinus is then collapsed with gentle pressure. The surgeon exposes the endolymphatic sac and makes an incision in it in order to insert the shunt.

Electronic Engineering