Electronics Engineering

Based on Ohm's Law, V = I*R, you would need to know the resistance along with one other parameter or the equation cannot be solved. However, if you are able to develop a set of independent linear equations based on the rest of the system surrounding that resistor using Kirchoff's Voltage Law or Kirchoff's Current Law, then you may still be able to solve for the unknown in the system.

you should specify:

- circuit topology, I assume a series connection.

- diode allows current flow? It depends how it's connected

- diode forward voltage drop value

if diode is in forward conduction, you have VR=10V - VDIODE and, thus, I = VR/R=(10-Vdiode)/1200.

it is one of the configuration of BJT ,which is achieved by making the BASE grounded(i.e common base).Here the emmiter serves as the input and collector as the output.

A pico farad is 1 x 10 minus 12 farads. That's 1 plus 11 zeros.

Here we will just connect DC generator shaft with motor's rotating spindle.

Now connect voltmeter across dc gen. and just calibrate voltmeter in terms of rpm.

If you have worked with micro-controllers then it will be very easy using it's ADC input.

Open the circuit with a switch or contacts.

20 led can be powered from a single 4017 output

X-ZONE ( PRANJAL)

A: RAIL is an English word to apply where we Americans call dc buss. Sometimes it is called the poke by our friends oversea. Anyhow that means that the circuit is probably swinging from bus to buss or rail to rail of poke to poke take your pick.

While working with robots you will blow off some parts or even kill yourself if not careful

To convert from analog (continuously varying) to digital (consisting of ones and zeros) -usually discrete steps that can closely mimic the analog signal.

Buffers are very useful as impedance matching circuits and as current boosters.They have i/p and o/p voltages same. However they amplify the current. Also they can be used to couple two circuits having different o/p and i/p impedances

At least 25 Kw and I don't think its practical to build such a large inverter I'd rather fit a autostart diesel or petrol engine to the compressor

What you are refering to is the use of a variable resistor. It has a shaft on it that when turned either clockwise or counter clockwise it dims or brightens the bulb. It does this by proportinally dropping voltage accross itself. However, a better method would be to use a series resonance circuit using an inductor and capacitor. This would dissipate less electrical energy as heat. Unfortunately, I can't send you a jpeg of this here but do a google for resonance and what you need will be there.

Just under 2 volts

Because the output circuits of the modulator would otherwise present an impedance

to the RF amplifier in parallel with the transmission line and antenna system, which

you don't want. In other words, you want the RF all going up the tower, not down to

ground through the modulator.

radio waves travels at the speed of light i,e 299,792,458 meters

An LM555 Timer has eight pins.

probably

(the carrier frequency +- the maximum frequency of the pulse train)/(the carrier frequency)

but pulses have a lot of harmonics

Internal capacitance of transistor increases propagation delay.Because charging and discharging of these capacitors will take more time which is not favourable.So always try to select transistors with minimum capacitance.

mmm because... that's business my friend, they describe the app, put pictures and reviews of the app. you decide to purchase and if you delete the app that's your problem

You can make it so it does either increase or decrease. The limiting factor is that power out cannot exceed power in. So going to a higher voltage will limit current and going to a lower voltage will increase current available.

A2

Because AC is continuously changing in a sinusoidal waveform, it is hard to determine the exact voltage. It is usually called by it's RMS value (Root Mean Squared).

The result is that when you fully rectify an AC voltage, the DC voltage is actually HIGHER than the RMS AC voltage.

The 'charges' (electrons, in the case of a metal conductor) are ALREADY distributed within the conductor. They are in a state of constant, haphazard, movement at just short of the speed of light. When a potential difference is applied across the conductor, there is a tendency for these electrons to move from the negative potential towards the positive potential. This tendency is VERY slow; for example, an individual electron is unlikely to pass through the filament of a flashlight during the lifetime of its battery!

A : A diode is an dumb animal he does not care how it is used all it cares is that its limitations are not exceeded

Guard bands between channels

it will cause a Short Circuit