Electrical Engineering

no

A constant parameter is one that does not vary over time, or varies so slowly, or within a very small, allowable range, that it can be used as a constant. One such parameter is the average temperature of the universe, which is 3 Kelvin. We theorize that over time it will gradually decrease with the expansion of the universe, but in practical terms, in a period of billions of years, it is held as a constant.

Diurnal light and dark cycles (day time and night time) is an example of a time varying parameter. The intensity of solar radiation, measured in a specific location, varies continuously during each day, and the length of each day varies continously through the year.

I=V/R, this is a most basic equation to use to understand what a resistor is and what it does, from the equation it can be seen that an increase of V, will result in an increase of I, also an increase of R will result in a decrease of I, because of that, resistors are used to reduce I so as to control the level of V in a circuit.

Your question is very muddled and it is difficult to understand exactly what you are asking.

Something is in "series" if it is connected in the circuit as a "daisy chain". Thus both loads AND batteries may be placed in series.

A 160A three-pole (TP) isolator can typically handle a maximum load of 160 amperes per phase. However, the actual load it can carry depends on factors such as the type of load, ambient temperature, and installation conditions. It's important to ensure that the isolator is used within its rated capacity to prevent overheating or damage. Always refer to the manufacturer's specifications and local electrical codes for precise guidelines.

To make an improvised generator, you can use a bicycle dynamo or a small DC motor connected to a bicycle wheel. As you pedal or spin the wheel, the dynamo or motor generates electricity. You can connect the output to a battery or LED light for simple applications. Ensure proper connections and safety precautions when handling electrical components.

two windings on the stator

The no load losses are the losses caused by energizing the transformer. These are constant losses, regardless of loading. This in effect tells you the efficiency of the transformer. (Power in) - (no load losses) = (Power out)

The current in a reading lamp would be a small part of the total current in a home. For example, a home may have 100 amp service, while a reading light may draw less than 1 amp, so about 1% of the total.

Yes. In fact hundreds of generators of different sizes are run in sync with each other every day ;-) Now, it may require some special equipment, depending on how you're setting this up.

single phase, double phase & three phase

5 HP is equal to 3.7 KW. 415 Volts 3 phase 50 hz system takes 6.29 amps. Same 3.7 KW motor with 230 volts, single phase 50 hz takes 18.9 amps. Same 3.7 kw motor with 230 volts three phase 50 Hz takes 11.1 amps. These are full load current with 0.85 assumed power factor.

To arrive at over load, you may 5 to10% over load and set the over load setting.

what is the dyn1????

The phantom loading is that no external load is connected in actual sense and the current and pressure coils are connected seperatly so that it will consume only less power. In this connection the voltage across pressure coil will be supply voltage even if the variac is in minimum position. CONNECTION Connect a single phase supply through a single phase variac. Connect the currect coil of wattmeter M and energy meter c1 and an ammeter in series to phase terminal of singlephase variac. The pressure coil of both wattmeter and energymeter should be shorted and connected to phase of supply (not to the variac). The terminal V of wattmeter and p2, c2 of energy meter should be connected to neutral terminal of variac. PROCEDURE Keeping the variac in minimum position and switch on supply. Adjust the variac to get different reading in ammeter and note the time for 5 Revolution of energy meter disc and obtain the wattmeter reading. FORMULAE %error = (R.E - A.E)*100/A.E , WHERE, R.E is the recorded energy = n/N (n=5 & N=energymeter const.) A.E is the actual energy A.E= (wattmeter reading*time)/(3600*1000) while plotting a error graph it will be having a zig-zag shape. Normally the error can be upto 10%

it will be no DC not unless diodes and capacitors are applied. rephrase the question

In a DC parallel circuit, equal voltage is applied to each device that is connected in parallel. For example, if three devices are connected in parallel to a 9 volt battery, each device will have 9 volts applied to it. In a DC series circuit, the sum of the voltage drops across each device connected in series equals the source voltage. So say you have three devices connected in series, and they are connected across a 9 volt battery. Each device will have less than 9 volts across it, but if you add the voltage drops across each device togther, it will equal 9 volts. Batteries in series have an additive effect to the voltage. A single AA battery has 1.5V. Two in series will have 3.0V. Batteries in parallel do not experience an additive effect to voltage. To answer this question briefly there is a big difference. The major difference is the resistance the circuit offers when the same components are wired in series or parallel. I do not know how much you want to know, but resistance of a component is measured in Ohms. An easy way to think of ohms is how much force or energy is required to move an object. The less ohms a circuit has the more it can do with the same amount of energy, which in some cases can be a bad thing. To move on, lets say you have two light bulbs, to give a cliche example, and both are 2 ohm load. Now if you wired these two light bulbs in series, connect positive of one bulb to negative of the other and then the others to a battery, the bulbs would be half as bright as one bulb to the same battery. Yet if you wired these in parallel there brightness would be the same as if one light bulb was connected to the circuit. This is because the voltage in the parallel circuit doesn't decrease when you add a light bulb, whereas on the series circuit it does decrease. Hope that helps

12 volt

10 to the power of 9 (109) is one billion (US) or giga- so 109 Hz is 1 GHz.

70.7

Trains use DC currents!

It's predominantly AC now but more dc in the early days. Both still in use. See DC and AC section below article-

According to Ohm's law i.e. E=IR. When we increase resistance, keeping current constant, voltage will increase as in the above formula since E and R are directly proportional.

It is simple - An input image is subsampled in the same way - the only difference is that a smoothing kernel one might use, which is {gaussian, laplacian, or gabor kernel}. Hope this helps!

Because , ic can provide :-

1. very high gain

2. compact & less bulky circuit