Electronics Engineering

need more info but I'll give it a shot and hope i answer your question.

You will need one of the following to get your desired ohm load:

1- single voice coil at 1 ohms

2 - single voice coil at 2 ohms wired + to +, - to -

2 - dual voice coil at 4 ohm all wired + to +, - to - so that you only have 2

wires conected to the amp.

hope this helps.

Maximum.

As many as you need, and as many as space allows.

Nothing.

But the current is halved.

After FM demodulation to the original AF signal it is necessary to amplify the weak AF signal to have enough power to drive speakers. That is the purpose.

Total Internal Reflection

Ohms law is: R= V x I (resistance = voltage / current) ...where an led typically likes 20mA (0.02A) of current running through it and 2V of voltage across it, therefore:

R= V x I = (220-2) / 0.02 = 218 / 0.02 = 10,900 ohms = 10.6kohms (10kohms will do fine).

hope that helps

ne ebbba

A diode is used as a rectifier, clipper and to get square wave form. The combination of diode (bridge) is used for full wave rectification. It also used as a voltage controlar. Different types of diodes have different uses in different appliences.

If you're allowed to prove this the easy way (by showing you can use XOR and AND to create the set of AND, OR, and NOT), this is pretty straightforward.

x AND y = x AND y (of course) x OR y = (x XOR y) XOR (x AND y)

NOT x = x XOR 1

Also, (x AND y) XOR 1 is equivalent to x NAND y, which is a universal gate.

A: Clipping only occurs if the input surpasses a threshold like the Vbe of a transistor. The 20 Db is really a change3 in voltage of a 100 that is not a small change

That's like having a series combination of 4 + 4 ohms, in parallel with another resistance of 4 ohms. Calculate the series resistance, then use the parallel formula to combine it with the third resistance.

internet

You can. Give an example, and someone here will help.

Yes, the resistance is directly proportional to length of wire and inversely proportional Area, hence when Length of wire increases the resistance also increases and when Area increases the resistance decreases. This means a thick wire has least amount of Electrical resistance.

XNOR gate is a two input gate.And if two inputs are the same they are Known as the Coincidence gate.Electronics can be very interesting if you understand the fundamentals of it.

The gabor pyramid is use gabor kernel to convolution with image intensity and then down sample to get different level pyramid.

Attractors of Hopfield network can be considered as digital presentation of analog inputs. Every analog input is classified as "hear" to some of attractors, so attractor (which is vector, including binary output of neurons) is digital conversion if analog input (vector, including input signals of neurons.

In a Geiger-Müller (GM) tube, there is a central anode and a "case" that is the cathode. A voltage is applied across these two elements, and an ionizing particle passing through the GM tube will cause current flow. But how much? Let's step through things and check it out. At low voltage, any electrons released by the cathode will eventually be collected by the anode, but there is no appreciable "current" per se in this, the ionization region. Things are still pretty "tame" in the GM tube through this range of voltages. By applying more voltage, an ionizing event will generate more current flow, and this current flow will be proportional to the voltage in what is (naturally) the proportional region. And as we apply more voltage, gas amplification, or Townsend avalanche, which appeared at the beginning of this region, is increasing across the area of the anode. As we apply even more voltage, it will only make for limited additional current flow in an ionizing event because the limits of the geometry of the GM tube and of the gas media to ionize and "conduct more" with the increasing voltage are being reached. This is the limited-proportional region. As voltage is increased even more, we enter the Geiger-Müller region. In this region, the current avalanche in an ionizing event is so great that is causes a "shield" of positive ions around the anode. The high current "sucks up" all the electrons and blankets the anode in a positive field that prevents additional current flow even with an increase in voltage. This is the Geiger plateau. It's the operating region where additional differential voltage will not cause higher current flow in an ionizing event.

There is not enough information in your question to provide a complete answer. Circuit testing of an air bag is potentially VERY dangerous. Air bags can be caused to deploy when tested in this manner depending on the equipment used. I caution you to have this done by somebody who is trained to diagnose a problem like this.

Foundation

The inductor is a component which produces inductance. This inductance which opposes any change of current through it, so if any changes occurred in an IC the output will be changed. so inductor is not used.